How to create a view between two table under different database?

thx

Assuming the different database is Oracle, you'll probably need to create a 'dblink'. Researching that topic should get you where you need to go.

Similar Messages

  • How to create a View between two Ztables?

    Hi experts,
    I have two ztables TableA and TableB both has one common field.
    Now Which type of view (Database,Maintanance,Projection or Help) I should create? If so what are the steps I should follow.
    What I suppose to do in Table/Join Condition tab ,View Flds ,Selection Conditions and Maint stsus tab.
    Reply with the detailed steps.
    Thanks in Advance,
    Dharani

    Hi,
    selection of view is depends on the type of requirement you have.
    1. To create the view go to Se11
    2. select the type of the view you required.
    3.Enter the name of the two z table in the tables and click on the relation button  so that it will automatically create the relationship between 2 table.
    4. add the addition condition if required in the join condition.
    5. In view field select the number of the field required to display in the view from both the table.
    6. specify the selection criteria in the to select the values.
    7. In maintenance tab select the appropriate option as per you requirement.
    8. save and activate the view.

  • How to create the reation between two tables without creating relation

    Hi,
    I have three tables.( A,B and C)
    I created relation between A,B and A,C.
    I want to create the relation between B,C without using realtion in oracle forms.
    Please do the needful.

    ok, now i understand your problem. It is a case of one-many-many relation between three blocks.
    In this situation what i personally follow that - save records in between when it ask for a commit. And i shall advice you to follow that only. This is the safe and easy method.
    Otherwise,
    1> make your third block a non-database block.
    2> When finish entering/modifying each data set related to 2nd block - insert/update/delete the data grammatically into a temporary table. and after that clear the 3rd block.
    3> you need to reload the record in 3rd block from the temporary table when you move to a record of 2nd block that has already been entered.
    4> now when you finally commit your form the insert/update/delete record from the temporary table into the final 3rd table.
    Now follow which ever steps is suitable for you.
    Regards,
    Tarun

  • How to create radio button between two slection screen

    hello all.
    could you please guide me how to create radio button between two SELECTION-SCREEN  in screen painter.
    Thank you,
    srinivas

    hi
    SEE THIS CODE
    REPORT  ZNNR_REPORT NO STANDARD PAGE HEADING MESSAGE-ID ZNNR LINE-SIZE 100 LINE-COUNT 65(4).
    ******DATA DECLARATIONS**********
    DATA : BEGIN OF IT_PLANT OCCURS 0,
            MATNR LIKE MARA-MATNR,
            WERKS LIKE MARC-WERKS,
            PSTAT LIKE MARC-PSTAT,
            EKGRP LIKE MARC-EKGRP,
           END OF IT_PLANT.
    DATA : BEGIN OF IT_PONO OCCURS 0,
            EBELN LIKE EKKO-EBELN,
            EBELP LIKE EKPO-EBELP,
            MATNR LIKE EKPO-MATNR,
            WERKS LIKE EKPO-WERKS,
            LGORT LIKE EKPO-LGORT,
           END OF IT_PONO.
    TABLES EKKO.
    ********END OF DATA DECLARATIONS*********
    ********SELECTION SCREEN DESIGN ***********
    SELECTION-SCREEN BEGIN OF BLOCK B1 WITH FRAME TITLE TEXT-001.
    PARAMETER : P_WERKS LIKE MARC-WERKS MODIF ID S1.
    SELECT-OPTIONS : S_EBELN FOR EKKO-EBELN NO INTERVALS MODIF ID S2.
    SELECTION-SCREEN END OF BLOCK B1.
    SELECTION-SCREEN BEGIN OF LINE.
    PARAMETERS : R3 RADIOBUTTON GROUP G2 DEFAULT 'X'.
    SELECTION-SCREEN COMMENT 5(20) TEXT-003 FOR FIELD R3.
    SELECTION-SCREEN END OF LINE.
    SELECTION-SCREEN BEGIN OF LINE.
    PARAMETERS : R4 RADIOBUTTON GROUP G2.
    SELECTION-SCREEN COMMENT 5(20) TEXT-004 FOR FIELD R4.
    SELECTION-SCREEN END OF LINE.
    SELECTION-SCREEN BEGIN OF BLOCK B2 WITH FRAME TITLE TEXT-004.
    SELECTION-SCREEN BEGIN OF LINE.
    PARAMETERS : R1 RADIOBUTTON GROUP G1 DEFAULT 'X'.
    SELECTION-SCREEN COMMENT 5(20) TEXT-002 FOR FIELD R1.
    SELECTION-SCREEN END OF LINE.
    SELECTION-SCREEN BEGIN OF LINE.
    PARAMETERS : R2 RADIOBUTTON GROUP G1.
    SELECTION-SCREEN COMMENT 5(20) TEXT-003 FOR FIELD R2.
    SELECTION-SCREEN END OF LINE.
    SELECTION-SCREEN END OF BLOCK B2.
    ******END OF SELECTION SCREEN DESIGN****************
    <b>rEWARD IF USEFULL</b>

  • How to check relation between two tables in same database

    How to check relation between two tables in same database using Oracle SQL developer. Version 2.1.1.64

    Hi,
    Try this,
    SELECT   cons.owner AS child_owner, cons.table_name AS child_table,
             cons.constraint_name constaint_name,
             cons.constraint_type constraint_type, col.owner parent_owner,
             col.table_name parent_table, col.column_name column_name
        FROM dba_cons_columns col, dba_constraints cons
       WHERE cons.r_owner = col.owner
         AND cons.r_constraint_name = col.constraint_name
         AND col.owner = 'MY_USER'
    ORDER BY child_table;Thanks,
    Shankar

  • How to create a link between 2 cells in different spreadsheets?

    when using numbers on MacBook Pro/IOS X - how to create a link between 2 cells in different spreadsheets?

    In the cell where you want the duplicate data to appear from another sheet/table do the following:
    type the equal sign ("=") then click the cell you in the sheet table while contents you want to appear in the cell where you just typed the equal sign"
    it reads "The cell I click equals the result of the formula or the contents of the next cell I click"

  • How do i link itunes between two computers with different Apple ID's

    how do I link itunes between two computers with different Apple ID

    You need to set up two user accounts on the mac.  System Preferences>Users & Groups.  Then each user can set up apple IDs for itunes and icloud any way they want.

  • How to create an relation between two block

    Oracle forms 6i
    Hai All
    I have created a form in that i have four button ADD, QUERY, SAVE ,EXIT.
    I have two block named Leader and members.
    Four fields in leader block namely name , codeno, deptcode, unitid.
    When i pressed query button and the cursor goes to name field in leader when i enter the name of leader and click
    enter i gives the codeno, deptcode and unitid of the leader_name.
    so now i have created another block in tabular structure to bring the members in the same deptcode that belongs to Leader_name.
    So pls tell me the steps how to create the relation between these two blocks.
    when i enter the leader_name and gives enter it needs to bring the codeno, deptcode, unitid and
    I also need to gives the members in that deptcode..
    Thanks In Advance
    Srikkanth.M

    If it is possible to create relationship with one table No.
    Or
    I have created a pre-Query in the detali block and my code is
    set_block_property ('block_name', default_where, 'deptcode = (select deptcode from emplmaster where name like :block_in_which_leader_name.leader_name_field');BTW no need of joining here it can be solve by set the block's where clause as u said in ur earlier post above. Just changing the little bit this statement and then try.
    If numeric
    set_block_property ('block_name', default_where, 'deptcode = '||:block_in_which_leader_name.leader_name_field);
    Otherwire
    set_block_property ('block_name', default_where, 'deptcode = '''||:block_in_which_leader_name.leader_name_field||'''');-Ammad

  • [ADF Help] How to create a view for multiple tables

    Hi,
    I am using Jdeveloper 11G and ADF framework, and trying to create a view to update multiple tables.
    ex:
    Table A has these fields: ID, Name
    Table B has these fields: ID, Address
    A.ID and B.ID are primary keys.
    B.ID has FK relationship with A.ID
    (basically, these tables have one-to-one relation)
    I want to create a view object, which contains these fields: B.ID (or A.ID), A.Name, B.Address.
    So I can execute C,R,U,D for both tables.
    I create these tables in DB, and create entity objects for these tables.
    So there are 2 entity objects and 1 association.
    Then I create a view object based on B and add fields of A into the view:
    If the association is not a "Composition Association",
    when I run the model ("Oracle Business Component Browser") and try to insert new data, fields of A can't edit.
    If the association is a "Composition Association", and click the insert button, I will get
    "oracle.jbo.InvalidOwnerException: JBO-25030: Failed to find or invalidate owning entity"
    If I create a view object based on A and add filed of B into the view:
    When I run the model and try to insert new data, fields of B can't edit, no matter the association is or is not a composition association.
    So... how can I create a view for multiple tables correctly?
    Thanks for any advices!
    Here are some pictures about my problem, if there is any unclear point, please let me know.
    http://leonjava.blogspot.com/2009_10_01_archive.html
    (A is Prod, B is CpuSocket)
    Edited by: user8093176 on Oct 25, 2009 12:29 AM

    Hi Branislav,
    Thanks, but the result is same ....
    In the step 2 of creating view object, I can select entity objects to be added in to the view.
    If I select A first, and then select B (the "Source Usage" of B is A), then finishing the wizards.
    When I try to create a new record in the view, I can't edit any properties of B (those files are disabled).
    If I select B first, and then select A in crating view object, the result is similar ...
    Thanks for any further suggestion.
    Leon

  • How to write select statement between two tables

    hi,
    i need to do comparision between two table for each records.ex:
    table1:
    regid            regno         ind
    1                 1001
    1                 1002
    1                 1003
    1                  1004
    and table2:
    regid           regno
    1               1002
    1                1005
    i need to select first row from table and loop for values in second table, if the values found first record , the record must update 'yes' to ind, if not 'No'.
    please help with this.
    thanks in advance
    raja

    Hi Raja,
      Do it like this.  loop  the first table and read the second table.
    Use where condition to satisfy the conditions.
    Or
    In your select query use joins. Like this.
    SELECT mara~matnr
           marc~werks
    INTO   TABLE t_material
    FROM   mara AS mara INNER JOIN marc AS marc
    ON     maramatnr = marcmatnr
    WHERE  mara~mtart = p_mtart.
    Instead of MARA and MARC here use your tables.
    Much Regards,
    Amuktha.

  • How can I share data between two forms on different lists

    Using a custom content type, I created two lists that I want to share the same data - one is a calendar.  Our employees complete a form from the "Out of Office Request" list that has workflow functionality that sends an email to that person's
    manager.  If the manager approves the request, the item automatically populates the "Out of Office Calendar."  The problem is that the only information from the request list that populates the calendar is the Title field and date/time fields. 
    I need the manager name in order to create a view for each manager.  
    How can I connect the other information in the request list to the calendar list.  It seems to me that if the title and date fields carry over the information, there should be a way to connect the other information.  I'm using Designer.
    I've tried to connect the two lists' webparts with the wizard, but when I get to the page that maps the two lists, there are no column names and the "Next >" button is grayed out.  This seems like the logical place to connect the two lists,
    but it isn't working.

    Hi,
    According to your post, my understanding is that you wanted share data between two forms on different lists.
    To show external  information on the calendar event, there are two methods: Calculated column, workflow. You can refer to:
    A Simple Guide to Show More Information on a Calendar Event
    I recommend to use workflow to achieve what you want. But you need to create a people column to display the manager.
    You can create a workflow associated to the "Out of Office Request" list, add action to Start Approve Process. If the manager approves the request, you can create a item in the calendar, and then update the people column and the title column.
    Then the calendar will display the Title, date/time and the manager.
    To create a view for each manager, you need to modify the Filter. You can use the people column is equal to the manager name or the Title contains the manager name.
    Thank you for your understanding.
    Best Regards,
    Linda Li
    Linda Li
    TechNet Community Support

  • Create Foreing Key to one table in different dataBase

    Hi, I need create a reference to one table in other database. I understand that Database Link can be used to connect me to other database but when I am creating the foreing key in my table, I can see only the tables in the schemas that have my data base not the other schemas. I created a connection with database link but I do not see the form to make reference to this connection from the create table wizard. I am using Oracle 9i and the client is 9.01.01.
    Thanks in advance,
    Mónica Alarcón

    We cannot use tables in another table to enforce data integrity. This makes a lot of sense if you think about what would happen if the remote database goes down.
    If you want to do this, then you need to use replication (materilaized view) to bring the parent table's data into the locaL database.
    Cheers, APC

  • How to create a relation between to tables

    hi all
    i have two oracle database:one is oratest(sourse),the other is orawh(destination).
    i have a table named hr.jobs in oratest,and a table named hr.test in orawh.
    now i want to create a relation between these two tables to make them synchronized.But i have no idea how to deal with such a case.
    somebody help me please,thanks a lot!!
    Best regards!

    You can use DML_HANDLERS at the apply side and manipulate the LCR's so that when data is inserted on TABLEA at source it can inserted in TABLEB at target.
    More information on DML Handlers are available at oracle documentation.

  • Creating a relationship between two tables  through configuration manager

    I've just created two tables in the underlying db, each with a primary key and established a primary key - foreign key relationship. I've also created a relationship through stellent and it shows up under the 'Relations' Tab.
    However, when I go to Information Fields > Field Info > Click on my Field > 'Edit' > Enable Option List and Configure > Use the view of one of the tables and click on Dependant Field , I don't see any Relationships defined. What could I have done wrong here?
    Thanks.

    ok...solved...followed metalink note 445363.1 for clarification on the right approach to creating Dependant Choice Lists (DCL).

  • How to get the 'link' between two tables

    hi pple
    i need to find out HOW two tables are related.
    sample tables:
    SHIPS ( HULL_ID [PK] , VESSEL_NAME, GROSS_TONNAGE )
    EQUIPMENT ( E_ID [PK] , HULL_ID [FK frm SHIPS], DESC )
    PARTS ( PART_ID [PK] , E_ID [PK, FK frm EQUIPMENT], MANUFACTURER_ID)
    --> SHIPS and PARTS are some how related thro' EQUIPMENT.
    i need to get this relationship:
    Ships --> Equipment (E_ID) --> PARTS
    currently, i can get the direct parent and child tables of a given table using:
    SELECT lpad ( ' ', 2 * ( LEVEL - 1 ) ) || table_name as Child_Tables
    FROM ALL_CONSTRAINTS
    START WITH R_CONSTRAINT_NAME in
    select constraint_name
    from all_constraints
    where table_name = '%table_name%'
    and constraint_type = 'P'
    CONNECT BY PRIOR CONSTRAINT_NAME = R_CONSTRAINT_NAME ;
    To get ALL parents:
    SELECT lpad ( ' ', 2 * ( LEVEL - 1 ) ) || table_name as Parent_Tables
    FROM ALL_CONSTRAINTS
    where owner = 'CHARTUSER'
    START WITH CONSTRAINT_NAME in
    select constraint_name
    from all_constraints
    where table_name = '%table_name%'
    and constraint_type = 'R'
    CONNECT BY PRIOR R_CONSTRAINT_NAME = CONSTRAINT_NAME ;
    what i need to do is:
    1) get children & parents of SHIPS
    2) for each element of (1), get children, parents till i get PARTS
    3) so, i will get EQUIPMENT and then, PARTS.
    this wud be very expensive. my appln is in Java and i will need to call these functions - that makes it more complex. is there any simpler way out?
    and my main problem is to find out WHAT attributes line two tables. this wudnt be a big deal if it were just simple parent-child tables. but, how do i find out the attributes that link PARTS and SHIPS table?
    any ideas? -please help.
    thanks in advance
    --$uDhA

    Dear Srikanth,
    This tables can be used once we come to know whether its a customer or vendor line item but in our case we using the GL account as reference have to knock off the entries.How we come to know that aginst the GL whether its a customer or vendor line item.. Then it should route to this table.
    Suggest me if any options are there.
    Regards,
    Balaji.c

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