How to display on open dialog in forms9i

Hi,
I have a program that will upload a picture to the database. my problem is, i don't know the command which will display the current directory of the drive so that the user can choose what kind of picture they are going to upload. can you give me the code? by the way i am using oracle forms9i.
Thanks for your help.

Hi,
Here is a link from this disscussion group itself. It will help you to got lot of info. about your problem.
Open File Dialog on the WEB...
Hoping that it will help you.
Regards
Yogesh

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I am using Forms 10g with Windows environment .. My requirement is, to display File Open Dialog Box, and whatever file I am selecting it has to open .. I am able to get Dialog box, problem is, when I select a file (for example, test.txt), I cant see the file getting opened .. Can anyone suggest me how to get the desired result ...
Pasting my code below
declare
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begin
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Regards

You can see the code in the webutil.pll library.
FUNCTION CLIENT_GET_FILE_NAME (directory_name Varchar2 := NULL,
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                               file_filter    Varchar2 := NULL,
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* Version 1.0.0
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*   1.0.0 DRMILLS 23/DEC/2002 - Creation
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How to display on open dialog in forms9i

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