How to exclude the data from the query ?

Question

Hi all,
I got the following sql script :-
SELECT OS.SL_DT, OS.sl_item_code, OS.SL_REF, (OS.sl_val_1) recp,B.CGCV_VALUE_1
FROM OS_STK_LEDGER OS, ( SELECT cgcv_item_code, CGCV_STK_QTY_BU, CGCV_COST_1, CGCV_VALUE_1
                         FROM OS_COST_GROUP_CURR_VAL
                         WHERE CGCV_COST_GROUP_CODE = 'ACOSG'
                         AND CGCV_GRADE_CODE_1 = 'G1' ) B
WHERE OS.sl_dt <= TO_DATE('31/05/2012', 'dd/mm/yyyy')
AND OS.sl_rcvd_issd = 'R'
AND (OS.sl_txn_code = 'SGRN' OR OS.sl_txn_code = 'PGRN' OR OS.SL_TXN_CODE = 'SAOP' )
--AND (os.SL_REF LIKE 'CRE%' OR os.SL_REF LIKE 'UT%' OR os.SL_REF LIKE 'MAR%' OR os.SL_REF IS NULL )
AND B.CGCV_ITEM_CODE(+) = OS.SL_ITEM_CODE
AND OS.SL_COST_GROUP_CODE(+) = 'ACOSG'
AND sl_grade_code_1 = 'G1'
order by sl_item_code, sl_dt
The following output will be :-
Date_______Item__Code________V1___V2
01/01/2012_AAA___CRE1005____100___200
02/02/2012_AAA___ABC1005_____50____200
02/03/2012_AAA___CRE1005_____90____200
01/03/2012_BBB___ABC1005_____50____1000
04/04/2012_BBB___ABC1005_____12____1000
From the output, when group by item & code, I am actual needs only Code with CRE1005, but for item : AAA group, I cannot delete code of ABC1005 because it consists of code with CRE%. For item : BBB, where Code not like CRE% then the two records actually I don't need to select in my SQL.
Can anyone help me to think about ways of solving this issue ?
Thanks.
Lim

Answer 1

with t
as
select to_date('01/01/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'CRE1005' code, 100 v1, 200 v2 from dual
union all
select to_date('02/02/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'ABC1005' code, 50  v1, 200 v2 from dual
union all
select to_date('02/03/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'CRE1005' code, 90  v1, 200 v2 from dual
union all
select to_date('01/03/2012', 'mm/dd/yyyy') dt, 'BBB' item, 'ABC1005' code, 50  v1, 1000 v2 from dual
union all
select to_date('04/04/2012', 'mm/dd/yyyy') dt, 'BBB' item, 'ABC1005' code, 12  v1, 1000 v2 from dual
-- Output sample ends.
-- Original select begins
select t1.dt, t1.item, t1.code, v1, sum_v1, v2
from t t1,
        select item, code, sum(v1) sum_v1
        from t
        group by item, code
        ) t2
where t1.item =t2.item
    and t1.code = t2.code;
DT       ITEM CODE            V1     SUM_V1         V2
01.01.RR AAA  CRE1005        100        190        200
02.02.RR AAA  ABC1005         50         50        200
03.02.RR AAA  CRE1005         90        190        200
03.01.RR BBB  ABC1005         50         62       1000
04.04.RR BBB  ABC1005         12         62       1000
5 rows selected.
with t
as
select to_date('01/01/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'CRE1005' code, 100 v1, 200 v2 from dual
union all
select to_date('02/02/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'ABC1005' code, 50  v1, 200 v2 from dual
union all
select to_date('02/03/2012', 'mm/dd/yyyy') dt, 'AAA' item, 'CRE1005' code, 90  v1, 200 v2 from dual
union all
select to_date('01/03/2012', 'mm/dd/yyyy') dt, 'BBB' item, 'ABC1005' code, 50  v1, 1000 v2 from dual
union all
select to_date('04/04/2012', 'mm/dd/yyyy') dt, 'BBB' item, 'ABC1005' code, 12  v1, 1000 v2 from dual
-- Output sample ends.
-- Original select begins
select t1.dt, t1.item, t1.code, v1, sum_v1, v2
from t t1,
        select item, code, sum(v1) sum_v1
        from t a
        where exists
                select 1
                from t b
                where code like 'CRE%'
                    and a.item = b.item
        group by item, code
        ) t2
where t1.item =t2.item
    and t1.code = t2.code;
DT       ITEM CODE            V1     SUM_V1         V2
01.01.RR AAA  CRE1005        100        190        200
02.02.RR AAA  ABC1005         50         50        200
03.02.RR AAA  CRE1005         90        190        200
3 rows selected.