How to execute sh file of unix in java

Question

iam trying to execute a sh file in target machine which will startup the database from source machine..
sh file is ..
# Synopsys
# This program startup's the database.
# Parameters
# @1: tuserconnect
# @2: tenvfile
# @3: tUserHome
progname=ajstartdb
echo "ssh ${1} . ${2} \&\& ${3}"
ssh ${1} . ${2} \&\& ${3}/ajss/sql/ajstrtdb.sh
retval=$?
echo "DEBUG::${progname}--> Completing execution with return code: $retval" > $progname.out
If i try to execute this ajstartdb.sh file in target itself it is executing perfectely.So i think no prob's with sh file..
but when i try to execute this sh file from java.. the process control is remaining in the prgm itself even after the cmd is executed.. i mean prgm is not exiting.
java prgm is :
import java.io.*;
class StartShut1
public static void main(String[] args)
try {
String cmd="ssh [email protected] . /d03/AppsGOLD/golddb/9.2.0/GOLD_hydapps.env \\&\\& /home/oragold/ajss/ajstrtdb.sh";
                         System.out.println(" the cmd is: "+cmd);
     Process p =Runtime.getRuntime().exec(cmd);
     int i = p.waitFor();
     System.out.println("Exit value of process is "+j);
                         System.out.println("Output of the Cmd is : "+i);
     String s=null;
     if (i!=0){
                              System.out.println("ERROR in executing the command");
                              BufferedReader cmdr = new BufferedReader(new InputStreamReader(p.getErrorStream()));
     while ((s = cmdr.readLine()) != null) {
                                             System.out.println(s);
                                                  s = null;
     BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream()));
                                   // read the output from the command
                                   s=stdInput.readLine();
                         System.out.println(s);
     while (s!= null)
     System.out.println(s);
InputStream in = p.getInputStream();
int ch;
StringBuffer sb = new StringBuffer(512);
while ( ( ch = in.read() ) != -1 )
{ sb.append((char) ch); }
System.out.println("output from string buffer"+sb);
}catch(Exception e)
System.out.println("ERROR :"+e);
e.printStackTrace();
}//main
}//class
Kindly Reply me if u get an idea

Answer 1

And also u hv specified & in the cmd ... it is executing when we specify \&\& there.
Do u hv any idea ragarding this symbol (\&\&) in unix..Let us try first without vowels (the OP tends to drop them):
& n cmmnd prmpt wll trmnt th cmmnd nd rn t n th bckgrnd.
&& wll wrk lk n C (r Jv fr tht mttr): t wll vlt th frst trm nd g n xctng nd vltn
g f t ws "tr", tht s, f t yldd "zr" s rtrn cd.
For the faint the one with vowels:
& in a command prompt will terminate the command and run it in the background.
&& will work like in C (or Java for that matter): it will evalute the first term and go on executing and evaluating if it was "true", that is, if it yielded "zero" as return code.
Thus
posman@proli:~/ivan/fnt> test -d mydir && ls -l mydir
posman@proli:~/ivan/fnt> mkdir mydir
posman@proli:~/ivan/fnt> ls >mydir/1
posman@proli:~/ivan/fnt> test -d mydir && ls -l mydir
total 4
-rw-r--r--  1 posman users 522 Oct  4 12:24 1