How to get file name and set it as static text in a dialog

Hi,
I m new to InDesign Programming.
I have a menu that creates a dialog with different controls in it.
The dialog will appear only if there is an open file. I need to display the name of the open file as a static text in the dialog. I know to get the name of the current file but don't know how to pass this each time the dialog is opened.
Can someone help me in doing this?
I m using InDesign CS3 in MAC OS.
Thank You.

those are the methods, but you can't use getCharacterEncoding(), actually, cuz it seems it's not necessarily filled in.. or at least that might be on some servers only, like Tomcat 4. As for encodings, you need to do a search for character encoding names and use the appropriate one.

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Hi,
According to my business scenario, one XML file name comes from Legacy system and stores in a predefined directory. Now XI has to pick up that XML file and needs to call BAPI's which in turn updates the Target system ( SAP Tables).
Now my problem is , XML File name is a combination of three fileds those are DATE , OBJECTKEY AND WORKFLOWNAME.
Ex : YYYYMMDD_1234565789_WORKFLOWNAME.XML
DATE_OBJECTKEY_WORKFLOWNAME.XML
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Thanks & Regards
K. naveen Kumar

Hi,
have a look at my new weblog:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
to see how you can access filename
Regards,
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File adapter - How to pass File name and path at runtime

Hi gurus,
We want to use PI 7.0 as an ftp server and expose the config as a webservice where the service consumer can pass one or more file names and the path to pick them and drop them on a fixed ftp server.
So precisely, I need to be able to set the file name, target directory parameters in both sender and receiver file/ftp adapters at runtime. is this possible at all ?
I am aware of passing Adapter specific parameters from sender file adapter to receiver file adapter to create the same folder structure and file names. But my requirement is different. I hope I am clear.
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Hi Jhansi,
Either you can go ahead with dynamic configuration as said by other SDN'ers. Else can go with Java Mapping:
Here is the code for Java Mapping:
import com.sap.aii.mapping.api.*;
import java.io.*;
import java.text.*;
import java.util.*;
public class GetDynamicConfiguration implements StreamTransformation {
private Map param;
public void setParameter(Map map1) {
this.param = map1;
public void execute(InputStream inputstream, OutputStream outputstream) throws StreamTransformationException {
try {
AbstractTrace trace = null;
// a) Set ouput File name
String directory=null;
trace = (AbstractTrace)param.get(StreamTransformationConstants.MAPPING_TRACE );
param.put(DynamicConfigurationKey.create("http://sap.com/xi/XI/Dynamic", StreamTransformationConstants.DYNAMIC_CONFIGURATION), "");
DynamicConfiguration conf = (DynamicConfiguration) param.get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File", "FileName");
DynamicConfigurationKey key1 = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File", "Directory");
String filename =conf.get(key);
conf.put(key, filename);
trace.addInfo("File name is "+filename);
if(filename.equals("in.txt"))
directory = "/home/ftpxi/in";
if(filename.equals("test.txt"))
directory = "/home/ftpxi/in/test";
if(filename.equals("shweta27.txt"))
directory = "/home/ftpxi/in/test";
trace.addInfo("Directory name is "+directory);
conf.put(key1, directory);
// b) Just copy input file to output file
byte[] b = new bytehttp://inputstream.available();
inputstream.read(b);
outputstream.write(b);
} catch (Exception exception) {
exception.printStackTrace();

Get file name and path from adf inputFile

Hi,
I use adf's inputFile component. I need to get the file name and filePath. Does anyone knows how to do that?
Thanks in advance

You may bind the value to an UploadedFile object and get the name from this object.
You may use a valueChangeListener backin bean method or a managed bean.
Here the code i just write for something similar. Note that i'm not able to test it because of a bug in 10.1.3.1 with inputFile and web.xml parameters. I still waiting for the patch.
public void uploadedFile(ValueChangeEvent valueChangeEvent) throws IOException,
Exception {
final int BUFFER = 2048;
byte data[] = new byte[BUFFER];
int currentByte;
String fileName;
UploadedFile uploadedFile =
(UploadedFile)valueChangeEvent.getNewValue();
if (uploadedFile != null) {
String mimeType = uploadedFile.getContentType();
if (mimeType == "application/x-zip-compressed") {
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FacesContext context =
FacesContext.getCurrentInstance();
ResourceBundle errorMessage =
ResourceBundle.getBundle(context.getApplication().getMessageBundle());
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// Process each entry
while (zipFileEntries.hasMoreElements()) {
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ZipEntry entry =
(ZipEntry)zipFileEntries.nextElement();
// check the entry is not a directory
if (entry.isDirectory()) {
Exception ZipFileContentException =
new Exception(JSFUtils.getStringFromBundle("error.fileUpload.zipFileContent.isDirectoryInsteadFile"));
throw ZipFileContentException;
File destFile = new File(entry.getName());
Magic magic = new Magic();
// getMagicMatch accepts Files or byte[],
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MagicMatch match = magic.getMagicMatch(destFile, true);
if (match.getMimeType() != "application/xml") {
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//TODO get the repository directory from classification-param.xml
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FileOutputStream fos = new FileOutputStream(destFile);
BufferedOutputStream dest =
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while ((currentByte = is.read(data, 0, BUFFER)) !=
-1) {
dest.write(data, 0, currentByte);
dest.flush();
dest.close();
is.close();
zipFile.close();
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String currentEntry = uploadedFile.getFilename();
File destFile = new File(currentEntry);
BufferedInputStream is =
new BufferedInputStream(uploadedFile.getInputStream());
FileOutputStream fos = new FileOutputStream(destFile);
BufferedOutputStream dest =
new BufferedOutputStream(fos, BUFFER);
// read and write until last byte is encountered
while ((currentByte = is.read(data, 0, BUFFER)) != -1) {
dest.write(data, 0, currentByte);
dest.flush();
dest.close();
is.close();
} else {
Exception ZipFileContentException =
new Exception(JSFUtils.getStringFromBundle("error.fileUpload.isNotXMLFile").replace("{0}",
mimeType));
throw ZipFileContentException;
}

Need to get file name and directory back from file adapter - WRITE

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I have an invoke in my BPEL process to the file adapter. My first try was to assign the jca.file.FileName property to a variable, but it never comes back. I looked around and saw plenty of ways to SET the file name for a write and GET the file name for a read, but no GET file name for WRITE.
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I think I got your point... You can tell FileAdapter the filename to write, but if you don't then FileAdapter can not tell you the filename that it wrote... I think it is pretty possible Oracle didn't implement the latter, as the write operation is probably asynchronous and the filename is calculated later on...
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http://docs.oracle.com/cd/E15586_01/integration.1111/e10226/ad_mon.htm#CJHHBBID
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Hi,
is there anybody who is able to help me with the following problem???
I started my process from Workspace ES and as a first step I attached one locale file (IMG.JPG or IMG.TIF e.g.) as a form attachment. I used "Attachments" bookmark in the Workspace ES.
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hope this helps,
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Blog: http://livecyclekarma.wordpress.com

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How to get file name in faultpolices file for file based rejection handler

Hi All,
I am implementing the file rejection handler in fault polices.xml
Now i want to catch exact file name and use this in faultpolices.xml under Filename tag and move the rejected file to custom directory.
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Suppose If we don't handle the rejection handler then these files will move to the default path in SOA HOME. But the file name remains the same. So i think this can be changed in SOA, but i am afraid i how can i do it.
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Hi,
have a look at my new weblog:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
to see how you can access filename
Regards,
michal

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You will have to create 2 different versions.
See this example we have created using JSystem
http://jsystem.flashjester.com
Download the example file provided.
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Regards
FlashJester Support Team
e. - [email protected]
w. - www.flashjester.com
"This has been one of the most impressive and thoroughly
pleasant
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Director - hedgeapple

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I can't hardcode this.
Can someone please help with how to retrieve an attribute name/value on a node that is not a child. Here's an example of what
my xml looks like:
DECLARE
@myDoc1 xml
,@mydoc2 xml
DECLARE
@ProdID int
SET @myDoc1 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
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<features featureID = "2" featureName = "seat">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
SET @myDoc2 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>2 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<features featureID = "2" featureName = "wheel">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>
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I used node('//*') for the path, and value('local-name(../.)', 'varchar(50)') as element
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cee

Are you looking for something like this:
DECLARE @myDoc1 xml
SET @myDoc1 ='<ProductDescription ProductID="1" ProductName="Road Bike">
<Features featureID = "1" featureName = "body">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>3 year parts and labor extended maintenance is available</Maintenance>
</Features>
<Features featureID = "2" featureName = "seat">
<Warranty>1 year parts and labor</Warranty>
<Maintenance>2 year parts and labor extended maintenance is available</Maintenance>
</Features>
</ProductDescription>'
SELECT T.c.value('local-name(.)', 'nvarchar(50)') AS name,
T.c.value('.', 'nvarchar(50)') AS value
FROM @myDoc1.nodes('ProductDescription/@*') AS T(c)
Erland Sommarskog, SQL Server MVP, [email protected]

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Click the menu:
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How to get file name for failed request in JSOM

hello friends,
i am uploading files to sharepoint 2013 document library. due to some problem when a file is not uploaded request is failed and failed callback handler is executed. at this time how i can know for which file has not been uploaded.
as i am uploading multiple files so it is necessary to know for which file error occurs.
please help
Thanks in advance.
Mukesh

Hi Z..
it will be hard for any one to understand the code. how ever I have provided bellow.
theme is I need to upload multiple files selecting one by one asynchronously when a file will begin to upload It will show status of file name with processing image. similarly for other files.
ones file successfully uploaded processing image will get hidden. and delete will appear.
when error occurs for a file then processing div need to be removed for which I need file name when request failed. in failed handler
function uploadData()
var input = $("#fldFile")[0];
if (input) {
$("#uploadedfile").append("<div class='file'><label>" + input.files[0].name + "</label><div class='image'><img src='/_layouts/15/KPMG.VendorPortal.DMS/processing.gif' alt='processing..'/><img src='/_layouts/15/KPMG.VendorPortal.DMS/error.png' alt='delete' style='display:none;' /></div>");
file = input.files[0];
filename = input.files[0].name;
fr = new FileReader();
fr.onload = uploaddocument;
fr.readAsDataURL(file);
function uploaddocument()
web = clientContext.get_web();
clientContext.load(web);
list = web.get_lists().getByTitle("TempLibrary");
rootFolderUrl = list.get_rootFolder();
file = this.result;
clientContext.load(rootFolderUrl);
clientContext.executeQueryAsync(onuploaddocumentsuccess, failed);
function onuploaddocumentsuccess()
fileCreateInfo = new SP.FileCreationInformation();
fileCreateInfo.set_url(rootFolderUrl.get_serverRelativeUrl() + "/" + foldername + "/" + filename);
fileCreateInfo.set_overwrite(true);
fileCreateInfo.set_content(new SP.Base64EncodedByteArray());
// Read the binary contents of the base 64 data URL into a Uint8Array
// Append the contents of this array to the SP.FileCreationInformation
var arr = convertDataURIToBinary(file);
for (var i = 0; i < arr.length; ++i) {
fileCreateInfo.get_content().append(arr[i]);
// Upload the file to the root folder of the document library
uploadedfile= list.get_rootFolder().get_files().add(fileCreateInfo);
clientContext.load(uploadedfile);
clientContext.executeQueryAsync(documentuploaded, documentfailed);
function documentuploaded()
var fname = uploadedfile.get_name();
$("#uploadedfile").children("div").each(function () {
var flabelname = $(this).children("label").text();
if (flabelname.trim() == fname.trim())
$(this).children("div").children("img").get(0).style.display="none";
$(this).children("div").children("img").get(1).style.display="block";
alert("uploaded");
function documentfailed(sender,args)
Mukesh

How to get file name using File adapter Sync read

Hi All,
I am using SOA 10.1.3.3 and JDEV 10.1.3.3.
I have an async bpel process.
I have to read file name in this process... so i have used file adapter sync read operation.
How can we get the file name with out payload using sync read.
For normal read (Inbound Spec)we have UseHeaders="true" property.
Is there any property for sync read to read the file name.
Please help me
Regards
PavanKumar.M
Edited by: [email protected] on Oct 27, 2009 11:23 PM

Hi Eric,
The info in the link provided by you is for a normal read.
I need to read he file name using Sync read operation.
Regards
PavanKumar.M

How to get file name on the base of extension

hi
reply me
how to get the filename on the base of extension from the
current directory......
for example
i create file with the "igg" extension and save in the folder
where the exe file of director save....
i want when exe run then exe file read filename of the
define( "igg" ) extension with out path just name of the file with
igg extension
tel me how
regards
farhana khan

Here's a solution that requires no xtras:
on GetFilesWithExtension(aFolderPath, aExtension)
-- INPUT: <aFolderPath> should be a valid string
folder path
-- <aExtension> may be a string file extension,
without the
-- dot. For example: "txt" or "igg"
-- OUTPUT: Returns an error symbol or a linear list of file
names
-- in the given folder. If an extension is given, only
-- files with the given extension will be listed. If not,
-- all files and folders will be listed.
vFileList = []
if not stringP(aFolderPath) then
return #stringPathExpected
end if
vIgnoreExtension = not stringP(aExtension)
vDelimiter = the itemDelimiter
the itemDelimiter = "."
n = 0
repeat while TRUE
n = n + 1
vFileName = getNthFileNameInFolder(aFolderPath, n)
if vFileName = "" then
exit repeat
end if
if vIgnoreExtension then
vFileList.append(vFileName)
else if the last item of vFileName = aExtension then
vFileList.append(vFileName)
end if
end repeat
the itemDelimiter = vDelimiter
return vFileList
end GetFilesWithExtension
You can also use
Buddy API's baFileList,
which allows you to do wildcard searching.

How to get file names?

Hi,
I'm currently trying to use com.oreilly.servlet.MultipartRequest by Jason Hunter to handle file uploading. This is the first time i handling this using jsp. I facing problem of getting the file names. I created the upload logic in a bean and i wanted it passing back the file names.
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?
Regards,
jeffcjm

jeffcjm wrote:
1) The file names actually in Enumeration type. Can i know what actually is Enumeration type?Read the java.util.Enumeration API: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Enumeration.html
2) Is it possible i return those names by converting them into string and as an array type? then accessing it using getProperty?Yes.
On the other side, you may find this stuff useful too. It sets all parameters back in the HttpServletRequest#getParameter()/getParameterValues()/getParameterMap() and puts the files as attributes of the HttpServletRequest. Very useful. http://balusc.blogspot.com/2007/11/multipartfilter.html

How to get file name and set it as static text in a dialog

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