How to get missing records from one table

Question

I have one table with many records in the table. Each time a record is entered the date the record was entered is also saved in the table.
I need a query that will find all the missing records in the table.
so if I have in my table:
ID          Date          Location
1           4/1/2015        bld1
2           4/2/2015        bld1
3           4/4/2015        bld1
I want to run a query like
Select Date, Location FROM [table] WHERE (Date Between '4/1/2015' and '4/4/2015') and (Location = bld1)
WHERE Date not in
(Select Date, Location FROM [table])
and the results would be:
4/3/2015   bld1
Thank you

Answer 1

Do you have a table with all possible dates in it?  You can do a left join from that to your above mentioned table where the right side of the join is null.  If you don't have a table with all possible dates you could user a numbers table.
Below is one way to achieve what you want with a numbers table...
DECLARE @Table table (ID Int, DateField Date, Location VarChar(4))
DECLARE @RunDate datetime
SET @RunDate=GETDATE()
IF OBJECT_ID('dbo.Numbers') IS NOT NULL 
DROP TABLE NUMBERS
SELECT TOP 10000 IDENTITY(int,1,1) AS Number
   into Numbers
    FROM sys.objects s1
    CROSS JOIN sys.objects s2
ALTER TABLE Numbers ADD CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number)
INSERT INTO @Table (ID, DateField, Location)
VALUES ('1','20150401','bld1')
,('1','20150402','bld1')
,('1','20150404','bld1');
WITH AllDates
as
SELECT DATEADD(dd,N.Number,D.StartDate) as Dates
FROM Numbers N
cross apply (SELECT CAST('20150101' as Date) as StartDate) as D
select * 
from AllDates AD
left join @Table T on AD.Dates = T.DateField
where ad.Dates between '20150401' and '20150404'
AND T.ID IS NULL
LucasF