How to get the files related to a module from server

Hi,
I am facing a problem. i have to extends controller but it has lot of imports from the same module but different folders. and all the files are in .class files. Can you tell me a process where i can download onto my local system from the server all the files from server and they are converted back to java files. Can i also get the xml files onto my local system.
Please help me on this. are there any tools which can do this? plz share links.
Thanks in advance.
Regards,
Prakash

Prakash
Its better through any tools (such as(WINFTP or WINSCP) you copy all the package structure into your local machine.For decompling all files in one go you can make use of JAD that is easily downloadable over net.
http://www.varaneckas.com/jad
Hope it helps!!!
Thanks
AJ

Similar Messages

How to get the files in presentation server while uploading?

how to get the files in presentation server while uploading?
give me the function module name

Hi,
PARAMETERS: P_FILE LIKE RLGRAP-FILENAME DEFAULT C_PRES. "Prsnt Srvr
AT SELECTION-SCREEN ON VALUE-REQUEST FOR P_FILE.
CALL FUNCTION 'WS_FILENAME_GET'
    EXPORTING
      DEF_PATH         = P_FILE
      MASK             = ',..'
      MODE             = '0 '
      TITLE            = 'Choose File'
    IMPORTING
      FILENAME         = P_FILE
    EXCEPTIONS
      INV_WINSYS       = 1
      NO_BATCH         = 2
      SELECTION_CANCEL = 3
      SELECTION_ERROR = 4
      OTHERS           = 5.

How is it posible to get the File name, size and type from a File out the H

How is it posible to get the File name, size and type from a File out the HttpServletRequest. I want to upload a File from a client and save it on a server with the client name. I want to conrole before saving the name, type and size of the file.How is it posible to get the File name, size and type from a File out the HttpServletRequest.
form JSP
<form name="form" method="post" action="procesuploading.jsp" ENCTYPE="multipart/form-data">
File: <input type="file" name="filename"/
Path: <input type="text" readonly="" name="path" value="c:"/
Saveas: <input type="text" name="saveas"/>
<input name="submit" type="submit" value="Upload" />
</form>
proces JSP
<%@ page language="java" %>
<%@ page import="java.util.*" %>
<%@ page import="FileUploadBean" %>
<jsp:useBean id="TheBean" scope="page" class="FileUploadBean" />
<%
TheBean.doUpload(request);
%>
BEAN
import java.io.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletInputStream;
public class FileUploadBean {
public void doUpload(HttpServletRequest request) throws IOException
          String melding = "";
          String filename = request.getParameter("saveas");
          String path = request.getParameter("path");
          PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("test.java")));
          ServletInputStream in = request.getInputStream();
          int i = in.read();
          System.out.println("filename:"+filename);
          System.out.println("path:"+path);
          while (i != -1)
               pw.print((char) i);
               i = in.read();
          pw.close();
}

Thanks it works great.
Here an excample from my code
import org.apache.commons.fileupload.*;
public class FileUploadBean extends Object implements java.io.Serializable{
String foutmelding = "geen";
String path;
String filename;
public boolean doUpload(HttpServletRequest request) throws IOException
     try
     // Create a new file upload handler
     FileUpload upload = new FileUpload();
     // Set upload parameters
     upload.setSizeMax(100000);
     upload.setSizeThreshold(100000000);
     upload.setRepositoryPath("/");
     // Parse the request
     List items = upload.parseRequest(request);
     // Process the uploaded fields
     Iterator iter = items.iterator();
     while (iter.hasNext())
     FileItem item = (FileItem) iter.next();
          if (item.isFormField())
               String stringitem = item.getString();
     else
          String filename = "";
               int temp = item.getName().lastIndexOf("\\");
               filename = item.getName().substring(temp,item.getName().length());
               File bestand = new File(path+filename);
               if(item.getSize() > SizeMax && SizeMax != -1){foutmelding = "bestand is te groot.";return false;}
               if(bestand.exists()){foutmelding ="bestand bestaat al";return false;}
               FileOutputStream fOut = new FileOutputStream(bestand);
               BufferedOutputStream bOut = new BufferedOutputStream(fOut);
               int bytesRead =0;
               byte[] data = item.get();
               bOut.write(data, 0 , data.length);
               bOut.close();
     catch(Exception e)
          System.out.println("er is een foutontstaan bij het opslaan de een bestand "+e);
          foutmelding = "Bestand opsturen is fout gegaan";
     return true;
     }

[CS3][JS] How to get the file type of current document

Hi,
How to get the file type of current opening document (e.g., tif, jpeg, png) using JavaScript with Photoshop CS3.
I am using file object the open the files one by one in the folder (the files sometimes don't have the extensions).
If the current document is in tiff format then I need to convert to 8-bit, if its an Jpg image then needs to ignore the file.
Regards,
Karthik

Do you really need to know the file type? What about just checking the bit depth?
var doc = activeDocument;
if (doc.bitsPerChannel != BitsPerChannelType.EIGHT) {//Not 8 bit
doc.bitsPerChannel = BitsPerChannelType.EIGHT;
//do your save etc
}else{
//Ignore

How to get the file size (in bytes) for all files in a directory?

How to get the file size (in bytes) for all files in a directory?
The following code does not work. isFile() does NOT recognize files as files but only as directories. Why?
Furthermore the size is not retrieved correctly.
How do I have to code it otherwise? Is there a way of not converting f-to-string-to-File again but iterate over all file objects instead?
Thank you
Peter
java.io.File f = new java.io.File("D:/todo/");
files = f.list();
for (int i = 0; i < files.length; i++) {
System.out.println("fn=" + files);
if (new File(files[i]).isFile())
     System.out.println("file[" + i + "]=" + files[i] + " size=" + (new File(files[i])).length() ); }

pstein wrote:
...The following code does not work. Work?! It does not even compile! Please consider posting code in the form of an SSCCE in future.
Here is an SSCCE.
import java.io.File;
class ListFiles {
    public static void main(String[] args) {
        java.io.File f = new java.io.File("/media/disk");
        // provides only the file names, not the path/name!
        //String[] files = f.list();
        File[] files = f.listFiles();
        for (int i = 0; i < files.length; i++) {
            System.out.println("fn=" + files);
if (files[i].isFile()) {
System.out.println(
"file[" +
i +
"]=" +
files[i] +
" size=" +
(files[i]).length() );
}Edit 1:
Also, in future, when posting code, code snippets, HTML/XML or input/output, please use the code tags to retain the indentation and formatting.   To do that, select the code and click the CODE button seen on the Plain Text tab of the message posting form. It took me longer to clean up that code and turn it into an SSCCE, than it took to +solve the problem.+
Edited by: AndrewThompson64 on Jul 21, 2009 8:47 AM

How to get the form reference in .js page from .jsp page

hi
i have written one form in jsp page omething like:-
<html:form action="/shopping" onsubmit="return false;">
can anybody tell me,how to get the form reference in .js page from .jsp page ,
i have tried:-
var formRef = document.forms[0];
butits not working.
Thanks.

Its very simple......y cant u prefer google...Bad
c this example...
function submit()
alert("textbox"+ document.forms[0].name.value);//to get textbox value in js
document.forms[0].submit();//to submit jsp page using js
<html:html>
<html:form action="/shopping" onsubmit="submit()">
<html:text property=name>
learn to search in google..
</html:form>
</html:html>

File Adapter - how to get the file count from a folder

Hi All,
I have a requirement that have to poll a directory when the file count is reached to number N (ex:number of files avilable in folder is 5) otherwise it should wait and not pick any of the files. Is it possible to get the file count from a folder using file adapter ?? otherwise please suggest me an approach to achieve this requirement.
Thanks,
JJ

Hi Sarath,
Thank you for your reply.
Go with the list files operation of file adapter it will gives you the number of files in the specified folder as you given. . - this step is already done.
When the number of files reaches your count startup your webservice that which can polls the files. . . - how can i acheive this?? Have to poll the directory and process the number files - please let me know, what could be added to the webservice which is being invoked after cheking file count from parent process.
The reason for the above question is - we cannot use ReadFile operation in second webservice because it will be automatically triggered when the file is avilable. Also SyncRead operation supports reading one file in b/w bpel process. Kindly explain me the implementation steps.
Thanks,
JJ

How to get the file path in adf application

hii all,
i have a txt file that i am using in my adf application,
i am passing this txt file through a File Reader, for which i have to mention the file path.
The file is in web-content and when i am hard coding the complete file path i.e C:/JDeveloper/myApp/ViewController/public_html/log.txt
the application is working fine when run on integrated weblogic server.
My requirement is to access this file without giving the static file path, as in case i have to use this application on any other machine..
for that how to mention the file path-
i tried using FacesContext to get the context path :-
FacesContext.getCurrentInstance().getExternalContext().getRequestContextPath();
which gives me
\myApp-ViewController-context-root
after appending public_html\log.txt
I am using the following path to access the file :-
\myApp-ViewController-context-root\public_html\log.txt
again i am getting the java.io.FileNotFoundException
Does anyone know how to use file from inside the web-content without giving the complete path..???
Thanks

Hi,
If you put your file under public_html folder, you can use this code to access the file:
For example file is : log.txt
FacesContext.getCurrentInstance().getExternalContext().getRealPath('/log.txt').toString().trim();
Thanks.
- LSR

Help ...how to get the file size on a server

Hi.I use this code to parse a file that is on a server.
The question is: how can i get the file size (bytes size)?
Thanks.
//Open the file for reading:
URL u = new URL(entry);
InputStream inputXML = u.openStream();
//Build document:
DocumentBuilder builder = factory.newDocumentBuilder();
doc = builder.parse(inputXML);

Try this instead:
URL u = new URL(entry);
URLConnection conn = u.openConnection();
// get the file size
int size = conn.getContentLength();
// open the input stream from the URLConnection (which is functionally the same as opening it directly from the URL)
InputStream inputXML = conn.getInputStream();
Shaun

How to get the file path from HTML input form in Firefox3

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature'.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....

Doubleposted and ignored any previous answer: [http://forums.sun.com/thread.jspa?threadID=5342405]. Don't do that. It's rude.
Regarding to your "problem": why do you need the file path?

How to get the file path from HTML input form in Firefox 3...

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature' because it causes all upload forms in my webapp to stop working on Firefox 3.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....

As you're posting this in the JSF forum and looking at your [previous topic|http://forums.sun.com/thread.jspa?threadID=5342365], I assume that you're using Tomahawk's t:inputFileUpload. In this case, just use UploadedFile#getInputStream(). You may find this article useful: [http://balusc.blogspot.com/2008/02/uploading-files-with-jsf.html].
By the way, are you lazy or just dumb? You wasted one week to this! I've posted the aforementioned article one week ago. How did you stuck?

How to get the file name in one of the Xml node field?

Hi Experts,
i have one requirement with file name in xml file.
i need to get <b>the file name of file</b> in one of the node in xml content of that file.
how can i achieve that req?
treat this as Very Urgent.

Hi Bheem,
Explain your scenario in detail..
>>i need to get the file name of file in one of the node in xml content of that file.
1. Create an node <b>Filename</b> in the target datatype.
2. Check the Option Filename in the Adapter Specific Message Attributes in the sender file CC.
3. Use the following UDF and map it to the Filename field in the target message type.
public String getFileName(Container container)
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
String ourSourceFileName = conf.get(key);
return ourSourceFileName;
Regards
San

AI CS3 Plugin: How to get the file format that is selected in the "save as" dialog??

Hi,
Someone please help me in getting the file format that is selected in the "save as" dialog. I wanted to retrieve it in the string format.
I tried sAIDocument->GetDocumentFileFormat. But i'm unable to implement it correctly. Is there a better way or How do I implement this? Precisely, I wanna get the value as a string when the user selects "save as .pdf".

Do you really need to know the file type? What about just checking the bit depth?
var doc = activeDocument;
if (doc.bitsPerChannel != BitsPerChannelType.EIGHT) {//Not 8 bit
doc.bitsPerChannel = BitsPerChannelType.EIGHT;
//do your save etc
}else{
//Ignore

How to get the FILE COUNT from File directory

Hello,
i have to develop a scenario like, get the file count from source file directory and validate whether the file count is 5 or not. if 5 files exist i need to process those 5 files to DB tables. if file count is not equal to 5 then i need to send a mail to customer that files are missed at source directory. (subject as files were missed at source directory and in content i need to display the file names exist at source file directory. So that missed file will be generated by the customer based on this mail).
Could you please let me know how to get the count of files from source file directory. if it is possible only with UDF please provide the Java code
Best Regards,
SARAN

Do these files have some fixed names?
Can you try to use the option Advanced Selection For Source File to make XI pick all 5 files in one shot?
Check this blog on the same -
/people/mickael.huchet/blog/2006/09/18/xipi-how-to-exclude-files-in-a-sender-file-adapter
If this is not a option - BPM sounds the only possible way.
Regards,
Bhavesh

How to get the files from Time Capsule

Hi everyone. I have a old model of Time Capsule which is never used before. I just have finished the setup and now the Time Machine is doing backup. May I know that after the backup is done, how can I get the files (e.g. photos, mp3, video...) from the Time Capsule or Time Machine?
Thanks for you help.

You can use Time Machine, the Migration Assistant, or the Setup Assistant to restore data from it.
(125023)

How to get the files related to a module from server

Similar Messages

Maybe you are looking for