How to get the file path from HTML input form in Firefox3

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature'.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....

Doubleposted and ignored any previous answer: [http://forums.sun.com/thread.jspa?threadID=5342405]. Don't do that. It's rude.
Regarding to your "problem": why do you need the file path?

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How to get the file path from HTML input form in Firefox 3...

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature' because it causes all upload forms in my webapp to stop working on Firefox 3.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....

As you're posting this in the JSF forum and looking at your [previous topic|http://forums.sun.com/thread.jspa?threadID=5342365], I assume that you're using Tomahawk's t:inputFileUpload. In this case, just use UploadedFile#getInputStream(). You may find this article useful: [http://balusc.blogspot.com/2008/02/uploading-files-with-jsf.html].
By the way, are you lazy or just dumb? You wasted one week to this! I've posted the aforementioned article one week ago. How did you stuck?

How to get the file path in adf application

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i have a txt file that i am using in my adf application,
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The file is in web-content and when i am hard coding the complete file path i.e C:/JDeveloper/myApp/ViewController/public_html/log.txt
the application is working fine when run on integrated weblogic server.
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I am using the following path to access the file :-
\myApp-ViewController-context-root\public_html\log.txt
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Hi,
If you put your file under public_html folder, you can use this code to access the file:
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Thanks.
- LSR

File Adapter - how to get the file count from a folder

Hi All,
I have a requirement that have to poll a directory when the file count is reached to number N (ex:number of files avilable in folder is 5) otherwise it should wait and not pick any of the files. Is it possible to get the file count from a folder using file adapter ?? otherwise please suggest me an approach to achieve this requirement.
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JJ

Hi Sarath,
Thank you for your reply.
Go with the list files operation of file adapter it will gives you the number of files in the specified folder as you given. . - this step is already done.
When the number of files reaches your count startup your webservice that which can polls the files. . . - how can i acheive this?? Have to poll the directory and process the number files - please let me know, what could be added to the webservice which is being invoked after cheking file count from parent process.
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Issue with Getting the file path from InputFile component

Hi,
One of our requirement is like below:
I am working on ADF 11g (latest release R1) page. User will select the file and when he/she clicks on the Save button we need to store the file path in the database.
In the database file_path is varchar2(300). We need to store just the file path. I am using InputFile component but filepath is not getting inserted.
This is really urgent. It would be really appreciate if anyone can guide me on this.
Thanks
MC

Hi Mahesh,
I have manage to store the file path from the InputFile component in Jdev 11g. I found the file upload script from this forum and manage to alter it so that i could save the file path to the database. But my problem is to retrieve it back to view as a document. Hope this will help you :)
This is an example of what I have manage to save to my DB :
(CLOB) //192.168.238.53/c$/Research/Docs/0906160744/EyeCandyLog.txt
In my form, I save the file path first before I update the other fields. My code is something like this :
public void uploadFile(ValueChangeEvent valueChangeEvent) {
// Add event code here...
InputStream in;
FileOutputStream out;
if(tanda == 0){
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
id = rS01Proposal.dptProposalid();
tanda = tanda + 1;
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
System.out.println("id"+id);
proposal = id.substring(6);
System.out.println("proposal"+proposal);
UploadedFile file = (UploadedFile)valueChangeEvent.getNewValue();
String fileUploadLoc = "//192.168.238.53/c$/Research/Docs/"+id+"/";//The place where file will saved
//create upload directory
boolean exists = (new File(fileUploadLoc)).exists();
if (!exists) {
(new File(fileUploadLoc)).mkdirs();
if (file != null && file.getLength() > 0) {
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage("File Uploaded " + file.getFilename() +
" (" + file.getLength() + " bytes)");
*// extracting the file message to get the path*
context.addMessage(valueChangeEvent.getComponent().getClientId(context), message);
columnL = valueChangeEvent.getComponent().getClientId(context);
column = columnL.substring(9);
System.out.println(column);
columnLengkap = "RS01"+column.toUpperCase();
System.out.println("columnLengkap"+columnLengkap);
*try {*
out = new FileOutputStream(fileUploadLoc + "" + file.getFilename());
in = file.getInputStream();
*for (int bytes = 0; bytes < file.getLength(); bytes++) {*
out.write(in.read());
in.close();
out.close();
} catch (IOException e) {
e.printStackTrace();
} else {
String filename = file != null ? file.getFilename() : null;
String byteLength = file != null ? "" + file.getLength() : "0";
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage(FacesMessage.SEVERITY_WARN, " " + " " +
filename + " (" + byteLength + " bytes)",
null);
context.addMessage(valueChangeEvent.getComponent().getClientId(context),
message);
System.out.println(fileUploadLoc+file.getFilename());
a = fileUploadLoc+file.getFilename();
b = b + 1;
if (flagInsert == 0){
try {
// final Context context = getInitialContext();
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} catch (Exception ex) {
ex.printStackTrace();
}else{
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try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
rS01Proposal.updateDoc(id,proposal,columnLengkap,a);
flagInsert = flagInsert + 1;
//session
ProposalSession.storeCurrentProposalId(id);
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
}

How to get the FILE COUNT from File directory

Hello,
i have to develop a scenario like, get the file count from source file directory and validate whether the file count is 5 or not. if 5 files exist i need to process those 5 files to DB tables. if file count is not equal to 5 then i need to send a mail to customer that files are missed at source directory. (subject as files were missed at source directory and in content i need to display the file names exist at source file directory. So that missed file will be generated by the customer based on this mail).
Could you please let me know how to get the count of files from source file directory. if it is possible only with UDF please provide the Java code
Best Regards,
SARAN

Do these files have some fixed names?
Can you try to use the option Advanced Selection For Source File to make XI pick all 5 files in one shot?
Check this blog on the same -
/people/mickael.huchet/blog/2006/09/18/xipi-how-to-exclude-files-in-a-sender-file-adapter
If this is not a option - BPM sounds the only possible way.
Regards,
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How to get physical file path from logical file path

Hi
there is a immediate requirement ,
I have logical file path but I need to get physical file path from it.
So is there any FM which providesthis functionality.
Points will be rewarded.
Thanks

Can you please share the piece of code ?
Which File APIs are you using ?
For java file, you can get complete path by simple method call : getAbsolutePath() on file object.
Regards,
Ashwani Kr Sharma

How to get the file name from Oracle B2B 10g

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Thanks,
b2b user

Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
In my BPEL 10g I am using AQ adapter to get the message from IP_IN_QUEUE.
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<sequence name="main">
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</sequence>
Can you help me to get the file name from Oracle b2b 10g ?
Thanks,
b2b user

Getting the file path from a File browse button

Hi,
I was wondering if there is a way to extract the whole file path (not just the file name) from a file which is selected using a file browse button?
I am trying to save the file path as text in my database (I don't want to upload the file). I have linked the file browse object to a table field in the database. But when entered in the database, all I get is a series of random characters, followed by the file name. I would like to have the complete file path instead.
Tom

Hi thanks
I've placed the java script into the head of the page, but unsure as to how to change the taget url for my submit button from doSubmit('SUBMIT') to doPrepareAndSubmit('SUBMIT'). In fact I don't actually have a submit button, but a save new record (which performs an SQL INSERT into the database using the values contained in the fields on the page) or a update record buttons instead.
I'm sorry but my knowledge of java scripts is not very good either.
How do I do the follwoing?: if your submit button has not any target set its target to url:
javascript: doPrepareAndSubmit('SUBMIT')
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How to get the file name from directory

Hi,
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Hi Saubhik ,
Wheni execute the function i am getting the following error
Warning: compiled but with compilation errors
Errors for FUNCTION LISTDIR
LINE/COL
ERROR
7/3
PLS-00201: identifier 'DBMS_BACKUP_RESTORE.SEARCHFILES' must be declared
7/3
PL/SQL: Statement ignored
8/54
PL/SQL: ORA-00942: table or view does not exist
8/20
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10/11
PLS-00364: loop index variable 'EACH_FILE' use is invalid
10/2
PL/SQL: Statement ignored      Cheers,
Shan

How to get the file name from downloads folder with the applescript??

Hi All..
I am downloading an application to downloads folder, I need to install the same application after downloading programatically.
So how do I get the filename in runtime while downloading or after downloading from downloads folder with Applescript or Java?
Also my download URL link doesnot contain full name of the download file.
Pls suggest.

Hi,
The best method is to use curl.
Other methods are not reliable, but can work, it depends on several factors (what the script does, what the user does).
Here is an example with the curl command:
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set dFolder to path to downloads folder
tell application "Finder" to set newFolder to (make new folder at dFolder) as string
set f to quoted form of POSIX path of newFolder
do shell script "cd " & f & " && curl -L " & tUrl & " -o 'vlc.dmg'" -- download to file "vlc.dmg"
set downloadedFile to newFolder & "vlc.dmg" --<-- HFS path
--do something with the downloadedFile

How to get the File-Type from a BLOB-Column

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I have the database table with the BLOB-Column. In this column are Word/Pdf/Excel/... files can be stored.
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I can download the file from database to the client and then open the file with client_ole2.CREATE_OBJ('Word.Application');
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How can I know which application is saved in the BLOB-column?
Regards

Hi Francois,
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Unfortunatelly I do not know the interMedia functions. Can you send me an example with interMedia?
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Hi All,
I am trying to store the file on my FTP server after selecting the file from the user workstation using JFileChooser. But I am not able to write the file on FTP server or on user local machine where application is running. I am new to this FTP server coding. Can anyone help me in this.
This is the code I wrote on button click user will able to select the file:
String filename1;
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fc.showOpenDialog(this);
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Below is the code to write the file on my local machine first:
BufferedWriter outFile = new BufferedWriter( fileName ) );
outFile.write();
outFile.flush( );
outFile.close( );
Any help will be greatly appriciated

rp0428 wrote:
>
BufferedWriter outFile = new BufferedWriter( fileName ) );
>
There is NOTHING named 'fileName' in any of the code you posted so that code can't possibly compile let alone actually run.
How can anyone help you if you won't post the actual code you are using?Its just a random snippet of other code that is totally irrelevant to this thread if you ask me.

How to get the absolute path of a file from the local disk given the file n

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Hi,
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Using the URL class i can get the content of the data from a STATIC page and output that response to file so that is does not display to the client broswer.
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How to get the file path from HTML input form in Firefox3

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