How to get the Real Path of a file which is accessed by URL?

Question

iam using tomcat6.0.
I have a file xyz.xml at the top of the webapplication HFUSE which i can able to access by URL
http://localhost:8080/HFUSE/xyz.xml
My problem is how to get the realpath of the file "xyz.xml" for reading and writing purposes.
I tried various things but i could not able to successfully solved the problem?
1) File f = new File("/xyz.xml");
print(f.getAbsolutePath()) ============== it is not fetching the file @ http://localhost:8080/HFUSE/xyz.xml rather it is creating a file
at the root of the drive where eclipse is running.
2) File f = new File("xyz.xml");============> this is also not working , it is creating the file xyz.xml in the eclipse directory ..................
Can anyone please guide on this problem?

Answer 1

RevertInIslam wrote:
If you want your context root(i.e HFUSE)
use this:
request.getContextPath() //where request is HttpServletRequest object to get the needful path.
e.g:
File f = new File(request.getContextPath()+"/xyz.xml");//it will create the file inside HFUSE.
Hope this helps.
Regards
BWrong. The File constructor expects an absolute filesystem path. The HttpServletRequest#getContextPath() doesn't return the absolute filesystem path, it only returns the relative path from the current context root. Use ServletContext#getRealPath() instead, it returns the absolute filesystem path for the given relative path from the current context root.
File file = new File(servletContext.getRealPath("/"), "xyz.xml");