How to get userinformation by passing userid

Hi All,
I know how to get IUser Object for the current logged in user and get the user information like Job title, City, Time Zone, Country, Department etc..
The same details I want go get for a particular user (not current logged in user).
Hence I am trying to pass the userid but not getting the IUser object and getting only null always. The user I am passing exists and also tried passing the full LDAP Unique ID.
IUser user2 = (IUser)WDClientUser.getClientUser("ramesh.kotagiri");
Is there any other way using UME API to get the IUser object and the user details like country, department from it, by passing a known userid.
Regards,
Ramesh.

Hi ,Ramesh Kotagiri
1) Depend DC :tc/je/usermanagement/api
2) Use UME API like this "UMFactory.getUserFactory().getUserXXX()",you will see many method to get
user information.
Regards,
Shiyu

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chris227 wrote:
I would propose the usage of regexp for readibiliy purposes and only in the case if this doesnt perform well, look at solutions using substr etc.
select
regexp_substr( '(25,23,35,1)', '\d+', 1, 1) s1
,regexp_substr( '(25,23,35,1)', '\d+', 1, 2) s2
,regexp_substr( '(25,23,35,1)', '\d+', 1, 3) s3
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"25" "23" "35" "1"In pl/sql you do something like l_val:= regexp_substr( '(25,23,35,1)', '\d+', 1, 1);
If t2.att_type is type of number you will do:
t2.att_type= to_number(regexp_substr( '(25,23,35,1)', '\d+', 1, 1))Edited by: chris227 on 01.03.2013 08:00Sir,
I am using oracle 10g.
In the process of getting each number from the parm '(25,23,35,1)' , I also need the position of the number
say 25 is at 1 position.
23 is at 2
35 is at 3
1 is at 4.
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BEGIN
IF(pi_flag_codes IS NOT NULL) THEN
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V_E_POS:=instr(pi_flag_codes, ',', 1, 1)-1;
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