How to hide table with empty content using Javascript?

Question

Hello!
I'm using Adobe LiveCylce Desinger integrated in SAP. I have a task to hide a database-table, if the table empty is.
Normmaly we can do following to check, whether the content empty is.
if (this.REMARK_TEXT.rawValue == null )
this.presence = "hidden";
else
this.presence = "visible";
The question is, how to check in Javascript, if a table empty is.
Many thanks in advance!
regards
longholiday

Answer 1

could try something like this:
function showOrHideTable(table){
     var isVisible = false;
    // gets the count of instance managers, event_initialize and row objects
    var rowCount = table.nodes.length;
    for(var i=0; i<rowCount; i++)
        //get the class name
        var myTestNode = table.nodes.item(i).className;
        //ignores the instance managers and event_init
        if(myTestNode == "subform")
            var innerCells = table.nodes.item(i).nodes;
            for(var j=0; j<innerCells.length; j++){
                //ignores non-input boxes
                if(innerCells.item(j).className == "field")
                    //check value
                    if(innerCells.item(j).rawValue != ""))
                        isVisible = true;
                    else
                        //hide the row
                        table.nodes.item(i).presence = "hidden";
    //if any row has a value specified
    if(isVisible)
        table.presence = "visible";
    //no value specified
    else
        table.presence = "hidden";