How to insert 1 element in 2D array?
There is an example of how to replace element in 2D array, but I would like to insert (not replace), I use the insert element. it does not work for 2 D array.
Attachments:
find_and_map_defect_to_image736X554.vi 46 KB
You need to tell more about what you want done. What exactly does it mean
to insert into a 2D array? Are you inserting into the row or column or
both? By that I mean to ask what parts of the array get their indices
incremented. Then what should happen at the endpoints? If you insert a
point into one row then that row will have one more element than the others.
Should the last element in that row be lost or should the other rows get a
zero appended?
"trout00" wrote in message
news:[email protected]..
> There is an example of how to replace element in 2D array, but I would
> like to insert (not replace), I use the insert element. it does not
> work for 2 D array.
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Go to Solution.Thank you for your suggestion.Here is my actual application attached . In the first image, a difference in time is evaluated and an enum const of insert into array is passed to the shift register where it takes to Insert element into array phase (Second image). I need to enter the time difference into an array after every loop iteration. Please have a look and could you let me know where I am mislead.
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Attachments:
realign.jpg 166 KBHi Ralph@NES,
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Attachments:
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How to assign element to String[] array?
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Message was edited by:
sibojava
Message was edited by:
sibojavaDo you have several accounts?
See this thread, it's the same question:
http://forum.java.sun.com/thread.jspa?threadID=5143232
Kaj -
The attached file is work inprogress, with some dummy data sp that I can test it out without having to connect to equipment.
The second tab is the one that I am having the problem with. the output array from the replace element appears to be starting at the index position of 1 rather than 0 but that is ok it is still show that the new data is placed in incrementing element locations. However the main array that I am trying to build that is suppose to take each new calculation and place it in the next index(row) does not ap
pear to be working or at least I am not getting any indication on the inidcator.
Basically what I am attempting to do is is gather some pulses from adevice for a minute, place the results for a calculation, so that it displays then do the same again the next minute, but put these result in the next row and so on until the specifiied time has expired and the loop exits. I need to have all results displayed and keep building the array(display until, the end of the test)Eventually I will have to include a min max section that displays the min and max values calculated, but that should be easy with the min max function.Actually I thought this should have been easy but, I gues I can not see the forest through the trees. Can any one help to slear this up for me.
Attachments:
regulation_tester_7_loops.vi 244 KBI didn't really have time to dig in and understand your program in depth,
but I have a few tips for you that might things a bit easier:
- You use local variables excessively which really complicates things. Try
not to use them and it will make your life easier.
- If you flowchart the design (very similar to a dataflow diagram, keep in
mind!) you want to gather data, calculate a value from that data, store the
calculation in an array, and loop while the time is in a certain range. So
theres really not much need for a sequence as long as you get rid of the
local variables (sequences also complicate things)
- You loop again if timepassed+1 is still less than some constant. Rather
than messing with locals it seems so much easier to use a shiftregister (if
absolutely necessary) or in this case base it upon the number of iterations
of the loop. In this case it looks like "time passed" is the same thing as
the number of loop iterations, but I didn't check closely. There's an i
terminal in your whileloop to read for the number of iterations.
- After having simplified your design by eliminating unnecessary sequence
and local variables, you should be able to draw out the labview diagram.
Don't try to use the "insert into array" vis since theres no need. Each
iteration of your loop calculates a number which goes into the next position
of the array right? Pass your result outside the loop, and enable indexing
on the terminal so Labview automatically generates the array for you. If
your calculation is a function of previous data, then use a shift register
to keep previous values around.
I wish you luck. Post again if you have any questions. Without a more
detailed understanding of your task at hand it's kind of hard to post actual
code suggestions for you.
-joey
"nelsons" wrote in message
news:[email protected]...
> how do I create a 1d array that takes a single calculation and insert
> the result into the first row and then the next calculation the next
> time the loop passes that point and puts the results in thsecond row
> and so on until the loop is exited.
>
> The attached file is work inprogress, with some dummy data sp that I
> can test it out without having to connect to equipment.
> The second tab is the one that I am having the problem with. the
> output array from the replace element appears to be starting at the
> index position of 1 rather than 0 but that is ok it is still show that
> the new data is placed in incrementing element locations. However the
> main array that I am trying to build that is suppose to take each new
> calculation and place it in the next index(row) does not appear to be
> working or at least I am not getting any indication on the inidcator.
>
> Basically what I am attempting to do is is gather some pulses from
> adevice for a minute, place the results for a calculation, so that it
> displays then do the same again the next minute, but put these result
> in the next row and so on until the specifiied time has expired and
> the loop exits. I need to have all results displayed and keep building
> the array(display until, the end of the test)Eventually I will have to
> include a min max section that displays the min and max values
> calculated, but that should be easy with the min max function.Actually
> I thought this should have been easy but, I gues I can not see the
> forest through the trees. Can any one help to slear this up for me. -
Insert element in selected column of 2d array
Hello
How to insert value in selected column of an array
In my program i am reading the CAN data from channels using
CAN read Channel API, the recent data read from the CAN channels
will be displayed in the indicator "Channel Data" 1D array, the
size of array depends on the number of channel selected for
monitor. i want to save all channel data.
i want to insert the first element of "Channel Data" array to
first column of "All Channel Data" 2D array, the second element
to the second column of 2D array...
i attached my VI
how to do this give me an idea.
thanks
sk
I am using LabVIEW 7.1
Attachments:
err2.zip 89 KBFor 2D arrays, you must insert entire rows or columns at one time. You cannot insert just one element. Why? Lets say for example you have a 2 x 3 array (2 rows with 3 columns). If you insert an element in row 3 (a new row) column 1, what goes into columns 2 and 3? You just messed up the integrity of the array, and Labview doesn't allow that. What you need to do is gather data for all columns in the new row and insert the entire row. The Insert Into Array function is used with the row number wired to Row Index and nothing wired to column index. You can gather all your data, build a 1D array and insert that array into a new row in the 2D array.
- tbob
Inventor of the WORM Global -
Hihow to insert 2 elements into 2D array?
Hi I had a hard time figuring out how to insert 2 elements into 2D arrays.
I tried using replace and insert array functions but it does not work right way.
I am using LV7.1. See the pic below.
How do I insert elements in that way?
Pls advise
ClementWell, "replace array subset" is not the right tool, because it keeps the size of the array constant. Insert into array only works for entire rows or columns.
You need a hybrid approach, because you want to insert elements at the beginning of column 1 while padding the remaining columns to the new lenght of column 1. This won't be efficient but there are plenty of ways to do that (here is one example with DBL arrays, should work equally well for string arrays as in your case).
How much flexibility do you need? Is it always at the beginning of the first column? Are the arrays huge (=is performance an issue)? Is this a rare operations or do you constantly need to do this (e.g. inside a loop).
In any case this seems like a rather arbitrary and somewhat silly operation. What is the practical purpose?
LabVIEW Champion . Do more with less code and in less time .
Attachments:
WeirdMerge.vi 21 KB -
How to insert an array of number into access database?
How can I insert an array of numbers(double) into an access database and later read them back to an array I labview. I don't have the Database Connectivity toolset. I would prefer using the LABSQL or other free solution. Any idea on how to solve this. I have tried LABSQL and SQL commands, but when I do that I have to convert the number to a string and then make a SQL-command string. Is there a way where I don't have to convert the number into a string?
Hello,
I am not familiar with LABSQL and we do not do any support on that particular product. However I still want to give you some information on how to proceed. You can either store the array to binary format and by doing this you can save an entire array to one single element of the database. The other alternative is of course to save one-to-one in other words one element of the array in one element in the database.
More info can be found here:
http://digital.ni.com/public.nsf/websearch/3FE68BBDA95E845986256DB4006A22C0?OpenDocument
Have you checked MSDN for information regarding this? You might be able to find useful SQL code there to use.
Regards,
Jimmie A.
Applications Engineer, National Instruments
Regards,
Jimmie Adolph
Systems Engineer Manager, National Instruments Northern Region
Bring Me The Horizon - Sempiternal -
How do you assign multiple values to a single element in an array?
I'm probably not wording the question right.
I have an array, let's call it M[], and for each element in the array (we'll say M[1]), I need assign three integers: row, col and value.
I need to set it up so I can do something like this:
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You can simply write a class that holds your three values and create an array of that type:
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public int row;
public int col;
public int value;
// somewhere else:
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a[0] = new SomeData();
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Edit: I'm getting old ... -
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Is there syntax in bpel that would do that?
ThanksYou need use While Element and use Array like Element[number]
With While element you iterate <employee> node
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I wrote a BPEL that scan a XML file, the input is:
<cliente>
<codigo>01</codigo>
<nombre>Deiby Mauricio Gomez</nombre>
<productos>
<producto>
<nombre>Camisa Polo</nombre>
<precio>50</precio>
</producto>
<producto>
<nombre>Pantalon Lona</nombre>
<precio>100</precio>
</producto>
</productos>
</cliente>
<cliente>
<codigo>02</codigo>
<nombre>Julio Cesar Ayapan</nombre>
<productos>
<producto>
<nombre>Camisa Polo</nombre>
<precio>50</precio>
</producto>
</productos>
</cliente>
In my BPEL I added up all article prices and after that I write to txt file the client and the Total.
Example:
Deiby Gomez, 150
Cesar Ayapan, 50
My while element is this (Please pay attention in bold words):
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<copy>
<from variable="Receive1_input_files" part="body"
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<bpelx:general>
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<copy>
<from variable="Receive1_input_files" part="body"
query='/ns4:clientes/ns4:cliente[number(bpws:getVariableData("variable1"))]/ns4:codigo'/>
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query="/ns4:clientes/ns4:cliente[number(bpws:getVariableData("variable1"))]/ns4:nombre"/>
<to variable="Approved_Write_input" part="body"
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<copy>
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query="/ns7:clientes/ns7:cliente/ns7:total"/>
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</assign>
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partnerLink="fileAdapterWriteApproved"
portType="ns6:Write_ptt" operation="Write"
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<from expression="''"/>
<to variable="Invoke1_process_InputVariable" part="payload"
query="/ns5:process/ns5:cantidad"/>
</copy>
</assign>
</sequence>
</while>
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