How to open a file using OAF

Question

Hi,
I want to open a file using OAF. I know the path and file name.
How can I open it, if file is in UNIX or in windows, where ever.
Is there any way to do that.
Thanks in Advance!!

Answer 1

Hi Ankur,
I had something link this requirement, that also for a concurrent program output only, but the output was txt file, and make it a zip file and give a dynamic link and open it.
For that i used the following code, may be it will help.
String zipout = pageContext.getParameter("ZIPOUT");
if(zipout!=null && zipout.equals("Y"))
try
DataObject sessionDictionary = (DataObject) pageContext.getNamedDataObject("_SessionParameters");
HttpServletResponse response = (HttpServletResponse) sessionDictionary.selectValue(null, "HttpServletResponse");
HttpServletRequest request = (HttpServletRequest) sessionDictionary.selectValue(null, "HttpServletRequest");
String requestID = pageContext.getParameter("REQUESTID");
response.setHeader("Content-Disposition","p; filename=CatExtract"+requestID+".zip");
response.setContentType("application/x-zip-compressed");
ZipOutputStream zip = new ZipOutputStream(response.getOutputStream());
try
byte[] buffer = new byte[1024];
int bytesRead;
//to get the value of output directory
String fileName = "/o"+requestID+".out";
Serializable[] parameters = { requestID };
//Get the output URL for this requests output.
pageContext.getApplicationModule(webBean).invokeMethod("getOutputURL", parameters);
String outputURL = (String)pageContext.getTransactionValue("OutputURL");
pageContext.writeDiagnostics(this.getClass().getName(),"outputURL in the xxt CO"+outputURL,1);
try
URL fileURL = new URL(outputURL);
URLConnection urlConn = fileURL.openConnection();
DataInputStream out = new DataInputStream(urlConn.getInputStream());
try
ZipEntry entry = new ZipEntry(fileName);
zip.putNextEntry(entry);
while ((bytesRead = out.read(buffer)) != -1)
zip.write(buffer, 0, bytesRead);
zip.closeEntry();
pageContext.writeDiagnostics(entry.getName(), " added.",1);
catch (Exception ex)
pageContext.writeDiagnostics(this.getClass().getName(),"Exception 113"+ex,1);
finally
out.close();
catch (IOException ex)
pageContext.writeDiagnostics(this.getClass().getName(),"Exception 124"+ex,1);
System.out.println("Exception 124 "+ex);
Thanks.
With Regards,
Kali.