How to open-up a pdf file to a particular page via java? (file and page number from another program)

Question

I have created an Access 2003 Form. Data is entered. The data can be viewed once entered in the same form format, with one addition. The addition is a link to another program where we store files. The files stored are pdf documents. Each document is a scanned file (500+ pages). The link can open-up the pdf file. I want the link to open-up the pdf file to a particular page. I will supply the page number from the database.
I am aware of Adobe Acrobat 7.0 PDF Open Parameters using a URL that specifies the file to be opened plus actions to be performed once the file is openend (i.e. http://example.org/doc.pdf#page=3). However, the 3rd party program transfers a file from a server to the client via java. The file does not go via a web browser. The java code transfer the file directly from the file server to the the client.
Any idea how to accomplish the task of viewing a particular page with the process flow described?
I am using Adobe Acrobat 7.0 Professional.

Answer 1

So you are reading this file in a standalone version of Acrobat? If so then use the PDF Open Parameters /a option via the command line.
Sabian
Example:
C:\Program Files\Adobe\Acrobat 7.0\Acrobat>Acrobat.exe /A "zoom=1000=OpenActions" "C:\Program Files\Adobe\Acrobat 7.0\Acrobat\SimpleSubmit.pdf"
Where:
Path to Acrobat: C:\Program Files\Adobe\Acrobat 7.0\Acrobat>Acrobat.exe
Note: The example starts in the Acrobat application directory
Switch: /A
Parameter Syntax: "zoom=1000=OpenActions"
Path to file: "C:\Program Files\Adobe\Acrobat 7.0\Acrobat\SimpleSubmit.pdf"
Note: The quotes are very important for the syntax to work appropriately.