How to parse xml file in midlet

Hi Guys,
i wish to parse xml file and display it in my midlet. i found api's supporting xml parsing in j2se ie., in java.net or j2se 5.0. Can u please help me what package to use in midlet?
how to parse xml info and display in midlet? Plz reply soon......Thanks in advance....

i have exactly the same problem with KXml2, but using a j2me-polish netbeans project.
i've tried to work around with similar ways like you, but none of them worked. now i've spent 3 days for solving this problem, i'm a bit disappointed :( what is wrong with setting the downloaded kxml2 jar path in libraries&resources?
screenshot

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I want to parse xml files from a normal FTP Servers , NOT the sap application severs itself. How can i do that?
I know how to use the SAPFTP getting and putting files ,but I don't want to download and then parse it.
Who knows how to parse it directly? I Just need to read the contents into a database.
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I want to parse xml files from a normal FTP Servers , NOT the sap application severs itself. How can i do that?
I know how to use the SAPFTP getting and putting files ,but I don't want to download and then parse it.
Who knows how to parse it directly? I Just need to read the contents into a database.
Thanks.

How to parse xml file

Hi,
I am having an XML file which is having set of repeated tags like
<gender>
<male>
<name>sk</name>
<age>19</age>
</male>
<male>
<name>raj</name>
<age>20</age>
</male>
<male>
<name>kris</name>
<age>18</age>
</male>
</gender>
Like this i am having the xml file, i have to read the values from this xml file, here we are having male tag is repeated, from this i have to take the name, and age values. can you tell me how to take these values. If you are having the sample send me.
Thanks,

Hai
It may be a bit late to reply but i hope this code will help you
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import java.io.*;
import java.io.File;
import org.w3c.dom.*;
class DomParse
     public void func()
          try
               DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
               DocumentBuilder db = dbf.newDocumentBuilder();
               //File f =new File("trial.xml");
               Document doc = db.parse(new File("trial.xml")); //your xml file name here
               //Document doc = db.parse(f);
               NodeList nl1 = doc.getElementsByTagName("male");
               for(int i=0;i<nl1.getLength();i++)
                    Node nd = nl1.item(i);
                    NodeList tmplist = nd.getChildNodes();
                    for(int j=0;j<tmplist.getLength();j++)
                         Node tmpNode = tmplist.item(j);
                         String locStr = tmpNode.getTextContent();
                         System.out.println(""+tmpNode.getTextContent());
          catch(Exception e)
               System.out.println("Error: "+e);
               e.printStackTrace();
     public static void main(String[] args) //throws
          new DomParse().func();
with regards
shan

How to parse XML file with namesapce?

Hi,
   I am trying to parse an xml file having namespace. But no data is returned.
Sample Code:
public class XMLFileLoader
var xml:XML = new XML();
var myXML:XML = new XML();
var XML_URL:String = "file:///C:/Documents and Settings/Administrator/Desktop/MyData.xml";
var myLoader:URLLoader = null;
public function XMLFileLoader()
var myXMLURL:URLRequest = new URLRequest(XML_URL);
myLoader= new URLLoader(myXMLURL);
myLoader.addEventListener(Event.COMPLETE,download);
public function download(event:Event):void
myXML = XML(myLoader.data);
var ns:Namespace=myXML.namespace("xsi");
for(var prop:String in myXML)
     trace(prop);
//Alert.show(myXML..Parameters);
//trace("Data loadedww."+myXML.toString());
//Alert.show(myXML.DocumentInfo.attributes()+"test","Message");
The XML Contains the following format.
<Network xmlns="http://www.test.com/2005/test/omc/conf"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://www.test.com/2005/test/omc/conf/TestConfigurationEdition3proposal4.xsd">
    <TestDomain>
      <WAC>
        
        <Parameters ParameterName="ne_release" OutageType="None"
                    accessRight="CreateOnly" isMandatory="true"
                    Planned="false"
                    Reference="true" Working="true">
          <DataType>
            <StringType/>
          </DataType>
          <GUIInfo graphicalName="Release"
                   tabName="All"
                   description="Describes the release version of the managed object"/>
        </Parameters>
</TestDomain>
</Network>
Any sample code how to parse this kind of xml file with namespaces...
Regards,
Purushotham

i have exactly the same problem with KXml2, but using a j2me-polish netbeans project.
i've tried to work around with similar ways like you, but none of them worked. now i've spent 3 days for solving this problem, i'm a bit disappointed :( what is wrong with setting the downloaded kxml2 jar path in libraries&resources?
screenshot

How to parse xml file, containing image, generaged from JAX-RS connector?

Hi,
We are using JAX-RS connector and just want to call getBusinessObjects() directly using JerseyMe (basically bypassing sync engine). We have used sync engine so far and want to try as how to bypass it. The method produces the text/xml and verified the xml file in the web by giving the full url. The plan is to call the same URL from the Java Me Client using JerseyMe. When I print the bytes at the client I receive the same xml that I have seen in the web. Actually, I am passing an image that I can see in a different character format in xml (assuming this is bcos of UTF-8 encoding). I am wondering as how to parse this xml file and how to decode the "UTF-8" format? Do we need to use SGMP for this or use kxml or java me webservices spec.
I would really appreciate if somebody can answer this one.
I have been observing in this forum that SGMP team is not at all active in answering the questions. Please let us know whether Oracle is keeping this product and we can continue using SGMP1.1. Please let us know so that we can plan accordingly as we are building a product based on SGMP.

Hi Rajiv,
The client library is using org.apache.commons.codec.binary.Base64 internally. We don't have the full Commons Codec library bundled, but you can look up the javadoc for the Base64 class online. All you need to do is call Base64.decode(obj.getBytes()) on the objects you get out of the XML.
In general it isn't a good idea to depend on implementation details of the client library, but in this case, I think it is pretty safe to expect org.apache.commons.codec.binary.Base64 to remain in our library.
--Ryan

How to parse xml file to read the tags

Hi All,
I am having a requirement to read the tags from the xml file(xml parsing).
The main issue is *xml file is stored in the table with xml type column* (not placed directly in the server) and we have to read the tags from that xml file.
Please help me to achieve it.
Regards,
Akshata
Edited by: Akshata on Mar 21, 2013 3:44 AM

Hi,
Akshata wrote:
The main issue is xml file is stored in the table clob/blob type column (not placed directly in the server) and we have to read the tags from that xml file.How is that an issue? On the contrary, it's better when the data already resides in the database, though it should be in an XMLType column to leverage the full capacity of the Oracle parser.
What's the datatype of the column exactly? CLOB or BLOB?
Either way you'll have to convert in to XMLType datatype using the XMLType constructor.
Did you go through the countless examples on this forum? Examples with XMLTable should be helpful.
Post some sample data and database version if you need additional guidance.
Thanks.

How to compare after parsing xml file

Hi,
following code, parse the input.xml file, counts how many nodes are there and writes the node name and its value on screen.
1) i am having trouble writing only node name into another file instead of writing to screen.
2) after parsing, i like to compare each node name with another .xsd file for existence.
Please keep in mind that, input.xml is based on some other .xsd and after parsing i have comparing its tag with another .xsd
Need you help guys.
thanks
* CompareTags.java
import java.io.*;
import org.w3c.dom.*;
import org.xml.sax.*;
import javax.xml.parsers.*;
import javax.xml.transform.*;
import javax.xml.transform.dom.*;
import javax.xml.transform.stream.*;
/** This class represents short example how to parse XML file,
* get XML nodes values and its values.<br><br>
* It implements method to save XML document to XML file too
public class CompareTags {
private final static String xmlFileName = "C:/input.xml";
     int totalelements = 0;
/** Creates a new instance of ParseXMLFile */
public CompareTags() {
// parse XML file -> XML document will be build
Document doc = parseFile(xmlFileName);
// get root node of xml tree structure
Node root = doc.getDocumentElement();
// write node and its child nodes into System.out
System.out.println("Statemend of XML document...");
writeDocumentToOutput(root,0);
               System.out.println("totalelements in xyz tag " + totalelements);
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/** Returns element value
* @param elem element (it is XML tag)
* @return Element value otherwise empty String
public final static String getElementValue( Node elem ) {
Node kid;
if( elem != null){
if (elem.hasChildNodes()){
for( kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling() ){
if( kid.getNodeType() == Node.TEXT_NODE ){
return kid.getNodeValue();
return "";
private String getIndentSpaces(int indent) {
StringBuffer buffer = new StringBuffer();
for (int i = 0; i < indent; i++) {
buffer.append(" ");
return buffer.toString();
/** Writes node and all child nodes into System.out
* @param node XML node from from XML tree wrom which will output statement start
* @param indent number of spaces used to indent output
public void writeDocumentToOutput(Node node,int indent) {
// get element name
String nodeName = node.getNodeName();
// get element value
String nodeValue = getElementValue(node);
// get attributes of element
NamedNodeMap attributes = node.getAttributes();
System.out.println(getIndentSpaces(indent) + "NodeName: " + nodeName + ", NodeValue: " + nodeValue);
for (int i = 0; i < attributes.getLength(); i++) {
Node attribute = attributes.item(i);
System.out.println(getIndentSpaces(indent + 2) + "AttributeName: " + attribute.getNodeName() + ", attributeValue: " + attribute.getNodeValue());
// write all child nodes recursively
NodeList children = node.getChildNodes();
          //int totalelements = 0;
for (int i = 0; i < children.getLength(); i++) {
Node child = children.item(i);
               //     System.out.println("child value.."+child);
if (child.getNodeType() == Node.ELEMENT_NODE) {
writeDocumentToOutput(child,indent + 2);
                         if(node.getNodeName() == "DATA"){
                         totalelements = totalelements+1;}
                    //System.out.println("totalelements in DATA tag " + totalelements);
/** Parses XML file and returns XML document.
* @param fileName XML file to parse
* @return XML document or <B>null</B> if error occured
public Document parseFile(String fileName) {
System.out.println("Parsing XML file... " + fileName);
DocumentBuilder docBuilder;
Document doc = null;
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
docBuilderFactory.setIgnoringElementContentWhitespace(true);
try {
docBuilder = docBuilderFactory.newDocumentBuilder();
catch (ParserConfigurationException e) {
System.out.println("Wrong parser configuration: " + e.getMessage());
return null;
File sourceFile = new File(fileName);
try {
doc = docBuilder.parse(sourceFile);
catch (SAXException e) {
System.out.println("Wrong XML file structure: " + e.getMessage());
return null;
catch (IOException e) {
System.out.println("Could not read source file: " + e.getMessage());
System.out.println("XML file parsed");
return doc;
/** Starts XML parsing example
* @param args the command line arguments
public static void main(String[] args) {
new CompareTags();
}

hi,
check out the following links
Check this blog to extract from XML:
/people/kamaljeet.kharbanda/blog/2005/09/16/xi-bi-integration
http://help.sap.com/saphelp_nw04/helpdata/en/fe/65d03b3f34d172e10000000a11402f/frameset.htm
Check thi link for Extract from any DB:
http://help.sap.com/saphelp_nw04s/helpdata/en/58/54f9c1562d104c9465dabd816f3f24/content.htm
regards
harikrishna N

How to parse xml and import to execel

pls let me know how to parse XML file and import all data to execel sheet.

Hi Mandya,
This is outside of the normal use case for TestStand. It would be best to use a code module (developed in LabVIEW, C, or any other language) to accomlish this and then call it from a step in TestStand. You can find examples on ActiveX here:
http://forums.ni.com/t5/NI-TestStand/Controlling-Excel-from-TestStand-with-Activex-Automation/td-p/1...
I hope this helps.
Frank L.
Software Product Manager
National Instruments

How to stop parse XML file

When using saxParser.parse(XMLfile, handler) to parse XML file, How to stop the parsing but not exit. I catched thread interrupted in startElement(), but can not stop it because it still go through all other startElement()s and endElement()s. Is there any method or class can stop parse XML?
Appreciate your help!
Edward

Please look at the technote:
http://access1.sun.com/technotes/01185.html
Hope this helps.
Michelle Cope
Sun Microsystems.

How to parse XML against XSD,DTD, etc.. locally (no internet connection) ?

i've searched on how to parse xml against xsd,dtd,etc.. without the needs of internet connection..
but unfortunately, only the xsd file can be set locally and still there needs the internet connection for the other features, properties.
XML: GML file input from gui
XSD: input from gui
javax.xml
package demo;
import java.io.File;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;
import javax.xml.XMLConstants;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
import org.xml.sax.SAXException;
public class Sample1WithJavaxXML {
     public static void main(String[] args) {
          URL schemaFile = null;
          try {
               //schemaFile = new URL("http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd");
               File file0 = new File("AppSchema-C01-v1_0.xsd");
               schemaFile = new URL(file0.toURI().toString());
          } catch (MalformedURLException e1) {
               // TODO Auto-generated catch block
               e1.printStackTrace();
          //Source xmlFile = new StreamSource(new File("web.xml"));
          Source xmlFile = new StreamSource(new File("C01.xml"));
          SchemaFactory schemaFactory = SchemaFactory
              .newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
          //File file1 = new File("XMLSchema.dtd");
          //SchemaFactory schemaFactory = SchemaFactory
               //.newInstance("javax.xml.validation.SchemaFactory:XMLSchema.dtd");
          Schema schema = null;
          try {
               schema = schemaFactory.newSchema(schemaFile);
          } catch (SAXException e1) {
               // TODO Auto-generated catch block
               e1.printStackTrace();
          Validator validator = schema.newValidator();
          try {
            validator.validate(xmlFile);
            System.out.println(xmlFile.getSystemId() + " is valid");
          } catch (SAXException e) {
            System.out.println(xmlFile.getSystemId() + " is NOT valid");
            System.out.println("Reason: " + e.getLocalizedMessage());
          } catch (IOException e) {
               // TODO Auto-generated catch block
               e.printStackTrace();
}Xerces
package demo;
import java.io.File;
import java.util.Date;
import org.apache.xerces.parsers.DOMParser;
public class SchemaTest {
     private String xmlFile = "";
     private String xsdFile = "";
     public SchemaTest(String xmlFile, String xsdFile) {
          this.xmlFile = xmlFile;
          this.xsdFile = xsdFile;
     public static void main (String args[]) {
          File file0 = new File("AppSchema-C01-v1_0.xsd");
          String xsd = file0.toURI().toString();
          SchemaTest testXml = new SchemaTest("C01.xml",xsd);
          testXml.process();
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          File docFile = new File(xmlFile);
          DOMParser parser = new DOMParser();
          try {
               parser.setFeature("http://xml.org/sax/features/validation", true);
               parser.setFeature("http://apache.org/xml/features/validation/schema", true);
               parser.setProperty("http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation",
                         xsdFile);
               ErrorChecker errors = new ErrorChecker();
               parser.setErrorHandler(errors);
               System.out.println(new Date().toString() + " START");
               parser.parse(docFile.toString());
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               System.out.print("Problem parsing the file.");
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}

Thanks a lot Sir DrClap..
I tried to use and implement the org.w3c.dom.ls.LSResourceResolver Interface which is based on the SAX2 EntityResolver.
please give comments the way I implement it. Here's the code:
LSResourceResolver Implementation
import org.w3c.dom.ls.LSInput;
import org.w3c.dom.ls.LSResourceResolver;
import abc.xml.XsdConstant.Path.DTD;
import abc.xml.XsdConstant.Path.XSD;
public class LSResourceResolverImpl implements LSResourceResolver {
     public LSResourceResolverImpl() {
      * {@inheritDoc}
     @Override
     public LSInput resolveResource(String type, String namespaceURI, String publicId, String systemId, String baseURI) {
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          LSInput input = new LSInputImpl(publicId, systemId, baseURI);
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          } else if (XsdConstant.PUBLIC_ID_DATATYPES.equals(publicId)) {
               input.setByteStream(classLoader.getResourceAsStream(DTD.DATATYPES));
          return input;
}I also implement org.w3c.dom.ls.LSInput
import java.io.InputStream;
import java.io.Reader;
import org.w3c.dom.ls.LSInput;
public class LSInputImpl implements LSInput {
     private String publicId;
     private String systemId;
     private String baseURI;
     private InputStream byteStream;
     private String stringData;
     public LSInputImpl(String publicId, String systemId, String baseURI) {
          super();
          this.publicId = publicId;
          this.systemId = systemId;
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     //getters & setters
}Then, here's the usage/application:
I create XMLChecker class (SchemaFactory implementation is Xerces)
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.xml.XMLConstants;
import javax.xml.stream.FactoryConfigurationError;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import abc.xml.XsdConstant.Path.XSD;
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     private ErrorMessage errorMessage = new ErrorMessage();
     public boolean validate(String filePath){
          final ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
          List<Source> schemas = new ArrayList<Source>();
          schemas.add(new StreamSource(classLoader.getResourceAsStream(XSD.XML_SCHEMA)));
          schemas.add(new StreamSource(classLoader.getResourceAsStream(XSD.XLINKS)));
          schemas.add(new StreamSource(classLoader.getResourceAsStream("abc/xml/AppSchema.xsd")));
          SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
          schemaFactory.setResourceResolver(new LSResourceResolverImpl());
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                         errorMessage.setErrorMessage(e.getMessage());
                         errorMessage.setLineNumber(e.getLineNumber());
                         errorMessage.setColumnNumber(e.getLineNumber());
                         throw e;
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                    public void fatalError(SAXParseException e) throws SAXException {
                         errorMessage.setErrorMessage(e.getMessage());
                         errorMessage.setLineNumber(e.getLineNumber());
                         errorMessage.setColumnNumber(e.getLineNumber());
                         throw e;
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                    public void warning(SAXParseException e) throws SAXException {
                         errorMessage.setErrorMessage(e.getMessage());
                         errorMessage.setLineNumber(e.getLineNumber());
                         errorMessage.setColumnNumber(e.getLineNumber());
                         throw e;
               StreamSource source = new StreamSource(new File(filePath));
               validator.validate(source);
          } catch (SAXParseException e) {
               return false;
          } catch (SAXException e) {
               errorMessage.setErrorMessage(e.getMessage());
               return false;
          } catch (FactoryConfigurationError e) {
               errorMessage.setErrorMessage(e.getMessage());
               return false;
          } catch (IOException e) {
               errorMessage.setErrorMessage(e.getMessage());
               return false;
          return true;
     public ErrorMessage getErrorMessage() {
          return errorMessage;
}Edited by: erossy on Aug 31, 2010 1:56 AM

How to Parse XML with SAX and Retrieving the Information?

Hiya!
I have written this code in one of my classes:
/**Parse XML File**/
          SAXParserFactory factory = SAXParserFactory.newInstance();
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               e.printStackTrace();
          catch(java.io.IOException e)
               e.printStackTrace();
          catch(org.xml.sax.SAXException e)
               e.printStackTrace();
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          games = gameCH.getGames();And here is the content handler:
import java.util.ArrayList;
import org.xml.sax.*;
import org.xml.sax.helpers.DefaultHandler;
class GameContentHandler extends DefaultHandler
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          System.out.println("End document.");
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     public void endElement(String namespaceURI, String localName, String qualifiedName) throws SAXException
     public void characters(char[] ch, int start, int length) throws SAXException
          /**for (int i = start; i < start+length; i++)
               System.out.print(ch);
     public ArrayList<Game> getGames()
          return games;
}And here is the xml i am trying to parse:<?xml version="1.0" encoding="ISO-8859-1" standalone="yes"?>
<Database>
     <Name></Name>
     <Description></Description>
     <CurrentGameID></CurrentGameID>
     <Game>
          <gameID></gameID>
          <name></name>
          <publisher></publisher>
          <platform></platform>
          <type></type>
          <subtype></subtype>
          <genre></genre>
          <serial></serial>
          <prodReg></prodReg>
          <expantionFor></expantionFor>
          <relYear></relYear>
          <expantion></expantion>
          <picPath></picPath>
          <notes></notes>
          <discType></discType>
          <owner></owner>
          <location></location>
          <borrower></borrower>
          <numDiscs></numDiscs>
          <discSize></discSize>
          <locFrom></locFrom>
          <locTo></locTo>
          <onLoan></onLoan>
          <borrowed></borrowed>
          <manual></manual>
          <update></update>
          <mods></mods>
          <guide></guide>
          <walkthrough></walkthrough>
          <cheats></cheats>
          <savegame></savegame>
          <completed></completed>
     </Game>
</Database>I have been trying for ages and just can't get the content handler class to extract a gameID and instantiate a Game to add to my ArrayList! How do I extract the information from my file?
I have tried so many things in the startElement() method that I can't actually remember what I've tried and what I haven't! If you need to know, the Game class instantiates with asnew Game(int gameID)and the rest of the variables are public.
Please help someone...

OK, how's this?
public void startElement(String namespaceURI, String localName, String qualifiedName, Attributes atts) throws SAXException
          current = "";
     public void endElement(String namespaceURI, String localName, String qualifiedName) throws SAXException
          try
               if(qualifiedName.equals("Game") || qualifiedName.equals("Database"))
                    {return;}
               else if(qualifiedName.equals("gameID"))
                    {games.add(new Game(Integer.parseInt(current)));}
               else if(qualifiedName.equals("name"))
                    {games.get(games.size()-1).name = current;}
               else if(qualifiedName.equals("publisher"))
                    {games.get(games.size()-1).publisher = current;}
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     public void characters(char[] ch, int start, int length) throws SAXException
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How to parse xml string

Hi! I'm having problems parsing an xml string. I've done DOM and SAX parsing before. But both of them either parse a file or data from an input source. I don't think they handle strings. I also don't want to write the string into a file just so I can use DOM or SAX.
I'm looking for something where I could simply do:
Document doc = documentBuilder.parse( myXMLString );
So the heirarchy is automatically established for me. Then I could just do
Element elem = doc.getElement();
String name = elem.getTagName();
These aren't the only methods I would want to use. Again, my main problem is how to parse xml if it is stored in a string, not a file, nor comming from a stream.
thanks!

But both of them either parse a file or data from an input source. I don't think they handle strings.An InputSource can be constructed with a Reader as input. One useful subclass of Reader is StringReader, so you'd use something likeDocument doc = documentBuilder.parse(new InputSource(new StringReader(myXMLString)));

How to send XML file to https server using POST

Hi, I am having an requirement, that I have to connect to https server and I have to pass an input XML file as a response server will give me output XML file.
The certificate validation part is over, I am using FileInputStream to read the XML file and attaching this to connection.getOutputStream(); but server is throwing me DTD does n't match.
Can any body tell me how to send XML file, I have to use any DOM parser to send the XML file, suggest me and give me sample code.
Thanks,

Can anybody give me the solution

How to open XML file in Netscape

How to open XML file in Netscape.....
XML file is opening correctly in IE, but giving error in Netscape.Error is
Error loading stylesheet: Parsing and XSLT stylesheet failed....
Reply me soon..............

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Parse XML files

Hi
Anyone know about support for parsing XML files in LabVIEW?
(I mean specific XML support, I'm familiar with LabVIEWs file functions)
regards
Jan
Sent via Deja.com http://www.deja.com/
Before you buy.

I assume you are referring to:
http://www.savarese.org/oro/software/OROMatcher1.1.html
Have you considered asking Savarese?
Peace,
Cameron Purdy
Tangosol, Inc.
http://www.tangosol.com
+1.617.623.5782
WebLogic Consulting Available
"Laurent Mentek" <[email protected]> wrote in message
news:[email protected]..
Hi all,
I'm started to develop with BEA WebLogic and I use ORACLE 8.1.6
database.
We need to map some XML tags as metadata in the database.
Here is a concrete example with part of our XML files:
XML files :
<target>EDU</target>
<question>
<para>
Please could you provide some references on nutritional status in
the frail elderly?
</para>
</question>
I use OROMatcher to parse xml files and it work fine.
I can extract every element in line with success , but don't extract the
value in <para> tag, for example.
I don't no how to use the MULTILINE_MASK option and the ^ or $ to get
this line.
Anyone could give me an example of metadatas extaction using or no the
MULTILINE_MASK option?
Thanks a lot for your help.
Laurent.

How to parse xml file in midlet

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