How to pull videos from xml AS 3.0

Question

Hello all,
I am pulling  videos form an 'video API' called 5min which is in xml format.
using the below code :
naming my video player instance as = videocontainer
XML.ignoreComments = false;
XML.ignoreProcessingInstructions = false;
import flash.events.TimerEvent;
import fl.transitions.Tween;
import fl.transitions.easing.*;
import flash.events.MouseEvent;
import flash.ui.Mouse;
import fl.motion.MotionEvent;
import flash.net.URLRequest;
import flash.display.Shape;
import flash.net.URLLoader;
import flash.net.URLRequest;
import flash.events.Event;
import flash.net.URLRequestMethod;
import flash.display.Loader;
import flash.net.URLRequest;
import flash.events.Event;
import flash.media.*;
var url:String = "http://api.5min.com/search/videos.JSON?q=";
var req:URLRequest = new URLRequest(url);
var loader:URLLoader = new URLLoader();
loader.load(req);
loader.addEventListener(Event.COMPLETE, completeHandler);
var myxml:XML;
function completeHandler(evt:Event):void{
myxml = new XML(evt.target.data);
var fl_NC_2:NetConnection = new NetConnection();
fl_NC_2.connect(null);
// starts a connection; null is used unless using Flash Media Server;
var fl_NS_2:NetStream = new NetStream(fl_NC_2);
fl_NS_2.client = {};
var fl_Vid_2:Video = new Video();
fl_Vid_2.attachNetStream(fl_NS_2);
addChild(fl_Vid_2);
//videocontainer.play("http://avideos.5min.com//423/5180423/518042244_2.mp4");
var media:Namespace = myxml.namespace("media");
videocontainer.play(myxml.channel.item[0].media::content.@url);
out put:
TypeError: Error #1009: Cannot access a property or method of a null object reference.
          at tesvideo2_fla::MainTimeline/frame1()
TypeError: Error #1088: The markup in the document following the root element must be well-formed.
          at tesvideo2_fla::MainTimeline/completeHandler()
          at flash.events::EventDispatcher/dispatchEventFunction()
          at flash.events::EventDispatcher/dispatchEvent()
          at flash.net::URLLoader/onComplete()
Can some one kindly help, where i am making the mistake. thank you

Answer 1

could it be sth as simple as having two slashes in an URL:
http://avideos.5min.com//423/5180423/518042244_2.mp4
If i give link, i wud end up displaying only preticular video. in fact i tried it and commented on my code since it will not help with my requirment.
yeah a videoservice called 5min, which is a property of my office here is the link to "5min API" 
http://api.5min.com/search/videos.JSON?q=
this API will be updated everytime we upload a new video same as RSS.
So I wanna display latest video same as like how we do RSS feed.
Hope i am clear this time atleast.