How to put a JPanel in a JTable

Question

I have been having problems with using a JPanel in each cell in a column of a JTable. I have a class "myPanel" which extends JPanel and has an overridden paint() function. In each row I want the "myPanel" to be displayed in the cell.
I've read all the documentation(that I could find online), and have searched for a while, but have not found the right way to do this.
I currently have defined myPanel like this:
class myPanel extends JPanel implements TableCellRenderer{
public Component getTableCellRendererComponent( ... ) {
repaint();
public void paint(Graphics g) { ... }
So, In my paint function I am not sure which cell(in the table) needs to be painted, but in the getTableCellRendererComponent, I know the cell to be rendered but I can't actually paint anything(I dont have a Graphics object to paint on).
SO either I get my graphics painted into every cell in the column identically, or I don't see anything in the cells. How do I paint differently in different cells.
Should I be using the object passed into getTableCellRendererComponent directly?
And I don't think there is a default renderer for a panel which would display the panel.
Any hints would be wonderful, as I can't get this to work.

Answer 1

You should use your myPanel with the params row and column as if the panel in that row and that column is the one to paint and return it from the method getCellRendererComponent, like in this code.
public Component getTableCellRendererComponent(...){
//....set the properties of your panel/CellRenderer as needed
//for displaiing the cell located in the row and column you get as //parameters,
//even adding or removing buttons or other stuffs from your panel
return this;
// you return the CEllRenderer itself !!! The table will do the painting work !!
That's it !!!
Do not use paint or repaint, you don't need it !!!
Bye Massimo