How to quickly clear an array used in a shift register?

Hello all,
I'm sure this is a quick one, but I'm missing the concept.
I have an array of boolean in a shift register. I have a case where I need to basically 'reset' the array rather than append to it....what is the best way to do this?
Thank you,
cayenne
Solved!
Go to Solution.

stevem181 wrote:
Of course, it is possible that my benchmark program is flawed.
Yup, disable debugging and you will see that the inner FOR loop is folded in both cases and the time drops to about zero.
Testing with debugging enabled is potentially unfair, because the reshaping will have more debugging code because there are more potential places to probe a wire, for example. All that said, I don't really know what's more efficient. That would require much more sophisticated testing. My point was just a reminder that there are always many ways to do things.
(This is under LabVIEW 2012. Constant folding and dead code elimination of course differ between compiler versions)
Granted, I typically don't use any of these two versions: I also omit the diagram constant, set the tunnel to "use default if unwired" and keep in unwired in the "clear" case. Less diagram clutter and quicker coding.
Here's how it would look like.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
Folding.png ‏13 KB
UseDefault.png ‏3 KB

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[email protected] wrote:
> Because I am very new to Labview and in fact, English is not my native
> language, I can not understand the sentence that "combine the current
> reading with the previous reading from the left shift register and save
> it back to the right shift register" means.
>
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>
> zhljh
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> > --
> > Michael Munroe Mailto:[email protected]
> > A Better Complete Development Engineering Firm
> > San Mateo, CA 94403 http://www.abcdefirm.com
> >
> > [email protected] wrote:
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> > > Any advice would be appreciated.
> > >
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