How to read contents of the Super Block ext2

Question

there I'm working on traversing an ext2 filesystem to read from it and I'm stumped at the first hurdle. The filesystem has a block size of 1024 bytes, so I need to read from the first 1024 bytes into an array to get Block Group 0. From there I need to go to the position of the super block, but I don't know how to go through the following first steps:
1 Find the Group Descriptor 2 Read the Inode Table Pointer value to find the block containing the first inode 3 Read Inode 2 (the root directory/ top of the filesystem) -- the length of each inode is given in the Group Descriptor 4 Traverse the filesystem as shown above to locate the file and its contents/ data blocks
I have some code below that reads the file in one go.
   try { aFile = new RandomAccessFile("ext2fs", "r"); FileChannel fileChannel = aFile.getChannel(); long fsize = fileChannel.size(); ByteBuffer buff=ByteBuffer.allocate(1024); fileChannel.read(buff,1024L); buff.flip(); byte[] data = buff.array(); System.out.format("%s\n", new String(data)); buff.clear(); fileChannel.close(); aFile.close(); }  catch (IOException e) { System.out.println("File not found"); } here
Thanks

Answer 1

The best solution is that you redesign your program so that it does not depend on the order of the entries in the properties file.
If you really want to stay with your design, you will have to read the properties file yourself, line by line, just like you would read any other text file, and parse the content of each line yourself.
BufferedReader in = new BufferedReader(new FileReader("stuff.properties"));
String line;
while ((line = in.readLine()) != null) {
    // Parse the line, use e.g. String.split() to split it around the '='
in.close();