How to replace string containing special characters by another string

Hi all,
I have to Search for a pattern and replace it by a substitute pattern [Eg: Replace methodOrig (a,b) with SessTime = getSessionParameter(time); methodNew(a,b,SessTime) ] in files.
i tried this using replace(),but it din't work since string1 contains special characters.
can anyone help me asap.
thanks in advance.

Double-post: http://forum.java.sun.com/thread.jspa?threadID=599211&tstart=0

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please let me know the best way to replace all the special characters in a string with space.
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with regards.
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please let me know the best way to replace all the special characters in a string with space.
other than alphabets and numbers
>
Sumanth Nag Kristam wrote:
> actually i need to replace hexa decimal char 0X1A in a string.... that is 'substitue' as per the chart
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>
> chk the link for the ASCII codes
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I am new to Data Services.I took excel sheet as a data source .Now i have do some validation functions like vendorgroup should not contain special characters ,name cleansing operations etc.. So,please anyone help me redarding this.
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Anonymous,
No this is not a bug. Working with multi-select lists or any item which stores colon delimited values can be tricky to work with in APEX. There are a few work arounds for this. One is to replace the colons with something else like you described and then replace the colons on the landing page. Another solution is to send the primary key for that record and have an automatic row fetch or a computation pull the colon delimited value.
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Helvetica abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ 
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</nowiki></pre>
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<?xml version="1.0" encoding="utf-8"?>

<s:Application xmlns:fx="http://ns.adobe.com/mxml/2009"
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 <![CDATA[
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 if (eventObj.type == ValidationResultEvent.VALID) {
 // For valid events, the results Array contains
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 var xResult:RegExpValidationResult;
 reResults.text = "";
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 xResult = eventObj.results[i];
 reResults.text=reResults.text + xResult.matchedIndex + " " + xResult.matchedString + "\n";
 } else {
 reResults.text = "";
 ]]>
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Hi,
I need to identify special characters in a string.... could anybody send me some code please.......
Thanks,
Best regards,
Karen

data: str(100) type c.
data: str_n type string.
data: str_c type string.
data: len type i.
data: ofst type i.
str = '#ABCD%'.
len = strlen( str ).
do.
if ofst = len.
 exit.
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Function module SF_SPECIALCHAR_DELETE DX_SEARCH_STRING
l_address1 = i_adrc-street.
CHECK NOT L_ADDRESS1 IS INITIAL.
len = STRLEN( l_address1 ).
do len times.
if not l_address1+l(1) ca
'ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789 '.
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exit.
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data :gv_char .
data:inp(20) type c.
take the string length .
len = strlen (i/p).
do len times
MOVE FNAME+T(1) TO GV_CHAR.
IF gv_char CA spchar.
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T = T + 1.
enddo.
REPORT ZEX4 .
PARAMETERS: fname LIKE rlgrap-filename .
DATA: len TYPE i,
T TYPE I VALUE 0,
inp(20) TYPE C,
inp1(20) type c,
inp2(20) type c,
inp3(20) type c.
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START-OF-SELECTION.
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Minal

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I am using oracle 10g.......
Need to know what should be the query to check whether a special character exists or not in a column value....used the following query like.....
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Edited by: Dave on Jun 6, 2012 5:17 AM
Edited by: Dave on Jun 6, 2012 5:18 AM

Hi Dave,
example below:
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SELECT COUNT (*)
INTO emp_no_count_special_char
FROM DUAL
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{code}
Regards.
Al

How to replace string containing special characters by another string

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