How to retrieve 5th highest salary in a single statement

Hi,
How can we retrieve 5th highest salary in a single statement

Another method
select top 1
OrderID
, Quantity
from
select top 5
OrderID
, Quantity = sum (Quantity)
from
[Order Details]
group by
OrderID
order by
2 desc
) q
order by
2 asc
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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2nd and 5th highest salary

hi, i am kind of new to sql. i have a table with employee name and salary.
i would like to find the name of the 2nd highest salary? also i like to get the name of the 5th highest salary
here is my data
INSERT INTO er4 VALUES('john', 1000, 123);
INSERT INTO er4 VALUES('john2', 3000, 234);
INSERT INTO er4 VALUES('john3', 1000, 223);
INSERT INTO er4 VALUES('john4', 4000, 123);
INSERT INTO er4 VALUES('john5', 8000, 023);
INSERT INTO er4 VALUES('john6', 9000, 023);
INSERT INTO er4 VALUES('john7', 8000, 723);
you can see in the data that there are two employee with highest second salary. i would like to get either one but i want my query to return one row
can somebody help me write a query to get the name and salary of 2nd highest and name and salary of 5th highest

Hi,
Part of learning about functions is learning what they are good for, and what they are not good for.
As Justin said, MAX is not good for this task.
If you were interested in just the 1st highest salary, you possibly could use MAX like this:
SELECT *
FROM    er4
WHERE   salary =      (
               SELECT     MAX (salary)
               FROM     er4
AND     ROWNUM     = 1     -- in case of a tie, pick one row arbitrarily
;But even if the goal was to find the highest salary, I would use ROW_NUMBER, like Justin did.
Why? The following scenario happens all the time in real life. The client for whom you wrote this comes back in 3 months and says: "That query you wrote for the highest salary works great! We've found it so useful, we'd like to do something similar to find the 2nd highest salary, or the 5th highest, or the top 5, or the next 5." ROW_NUMBER is flexible enough to do all these things. When you have to solve one problem, you'll save time (in the long run) if you can foresee, or just guess, what similar problems you might need to solve later, and write something for today's problem that can easily be adapted for tomorrow's potential problem.

How to concatenate all the fields in a single statement with tilda..

hi, i have 10 fields, i have to concatenate those fields seperated with tilda... and put into the application server...in a single statement,
kindly suggest me hw to write..?
Thanx in Advance.
Akshitha.

Hi.....
Just see the following code...
It solves your requirement.....
REPORT ZCSV_SPFLI_APP.
TABLES :
SPFLI.                               " Flight
FIELD-SYMBOLS : <FS>. "TYPE C.
DATA T_SPFLI LIKE STANDARD TABLE OF SPFLI .
DATA W_CHAR(20) TYPE C.
DATA W_TYPE .
DATA:
BEGIN OF T_TABLE OCCURS 0,
    LINE TYPE STRING,
END OF T_TABLE.
SELECT * FROM SPFLI INTO TABLE T_SPFLI.
LOOP AT T_SPFLI INTO SPFLI.
DO.
    ASSIGN COMPONENT SY-INDEX OF STRUCTURE SPFLI TO <FS>.
    IF SY-SUBRC NE 0.
      EXIT.
    ELSE.
      MOVE <FS> TO W_CHAR.
      IF SY-INDEX EQ 1.
        T_TABLE-LINE = <FS>.
      ELSE.
        CONCATENATE T_TABLE-LINE '~' W_CHAR INTO T_TABLE-LINE.
      ENDIF.
    ENDIF.
ENDDO.
CONDENSE T_TABLE-LINE.
APPEND T_TABLE.
ENDLOOP.
LOOP AT T_TABLE.
WRITE / T_TABLE-LINE.
ENDLOOP.
OPEN DATASET 'YH647_SPFLI' FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
IF SY-SUBRC NE 0.
MESSAGE ' File is Not Opend' TYPE 'S'.
ENDIF.
LOOP AT T_TABLE.
TRANSFER T_TABLE-LINE TO 'YH647_SPFLI'.
ENDLOOP.
CLOSE DATASET 'YH647_SPFLI'.
This reads flight detail and makes the separated by '~' and stores in the application server (<b>OPEN_DATASET, TRANAFER , CLOSE DATASET</b>)
Reward points if useful.........
Suresh........

Pls help me in finding highest salary of employee.

can anybody give me...
the general query...for finding out nth highest salary of the employee in a particular department.....
for example, if i want to find out 2nd highest salary or some 5th highest salary of the employee.....
i want query with a littlebit explanation also...

i
cannot do the sumation of those value then the
negative value that being re-enter become 0. how can
i make the value to become another positive value?Are you doing the `sumation' during the data entry (loop)? If so, make sure you only include valid value in the count (i.e. positive integers).

How to get highest salary from salary column in sharepoint list

Hello,
I have one custom list in which there is one salary column so I want to get the highest salary.Can we do this OOTB or by using custom code by adding webpart(using CAML query).
Thanks,

http://stackoverflow.com/questions/516073/max-query-using-caml
<Query>
<OrderBy>
<FieldRef Name="particularcolumn" Ascending="FALSE" />
</OrderBy>
</Query>
http://stackoverflow.com/questions/8383616/caml-query-on-a-sharepoint-2010-list
http://sharepoint.stackexchange.com/questions/16955/how-to-select-max-field-in-caml-query
If this helped you resolve your issue, please mark it Answered

How to find the third highest salary by distinct the salary from deptno20,from employee table

how to find the third highest salary by distinct the salary from deptno20,by using employee table

You already asked this question, a half hour earlier:
https://forums.oracle.com/thread/2569985
and received a reply.
Do not multi-post to the forums.
These are user-to-user forums and everyone is posting because they volunteer to post and not because they get paid to post. Everyone else is paid exactly the same as you are paid to post here. When you multi-post is makes you appear as impatient and expecting instantaneous answers.
That is poor forum etiquette, approaching behavior similar to spamming the forums.
This duplicate post is locked.

How to find the third highest salary from deptno20,from employee table

how to find the third highest salary from deptno20,from employee table

SELECT *
FROM emp;
EMPNO
ENAME
JOB
MGR
HIREDATE
SAL
COMM
DEPTNO
7369
SMITH
CLERK
7902
12/17/1980
1000
3
20
7499
FEDERAL
SALESMAN
7654
2/20/1981
2000
4
30
7521
WARD
SALESMAN
7698
2/22/1981
3000
4
30
7566
JONES
MANAGER
7839
4/2/1981
4000
3
20
7839
MARTIN
SALESMAN
7698
9/28/1981
5421
4
30
7698
BLAKE
MANAGER
7698
5/1/1981
6222
4
30
7782
CLARK
MANAGER
7839
6/9/1981
5222
2
10
7788
SCOTT
ANALYST
7566
12/9/1982
5463
3
20
7839
KING
PRESIDENT
7902
11/17/1981
8543
2
10
7844
TURNER
SALESMAN
7698
9/8/1981
2124
4
30
7876
ADAMS
CLERK
7788
1/12/1983
2125
3
20
7900
JAMES
CLERK
7698
12/3/1981
5462
4
30
7902
FORD
ANALYST
7566
12/3/1981
2132
3
20
7934
MILLER
CLERK
7782
1/23/1982
5165
2
10
SELECT sal, deptno
FROM (SELECT   a.*,
                 DENSE_RANK () OVER (PARTITION BY deptno ORDER BY sal DESC) r
            FROM emp a
      ---- ORDER BY sal DESC
WHERE r = 3;
SAL
DEPTNO
5421
30
5165
10
2132
20
Regards ,
Friend
Message was edited by: MostWanted!!!!

How to find record having second highest salary

Hello friends
I ve a table empsal
it has 2 columns name,salary
i need to find out name of employee with second highest salary.
how shud i ..pls help...
thks
sonal...

in the doc
create or replace type SecondMaxImpl as object
max NUMBER, -- highest value seen so far
secmax NUMBER, -- second highest value seen so far
static function ODCIAggregateInitialize(sctx IN OUT SecondMaxImpl)
    return number,
member function ODCIAggregateIterate(self IN OUT SecondMaxImpl,
    value IN number) return number,
member function ODCIAggregateTerminate(self IN SecondMaxImpl,
    returnValue OUT number, flags IN number) return number,
member function ODCIAggregateMerge(self IN OUT SecondMaxImpl,
    ctx2 IN SecondMaxImpl) return number
create or replace type body SecondMaxImpl is
static function ODCIAggregateInitialize(sctx IN OUT SecondMaxImpl)
return number is
begin
sctx := SecondMaxImpl(0, 0);
return ODCIConst.Success;
end;
member function ODCIAggregateIterate(self IN OUT SecondMaxImpl, value IN number) return number is
begin
if value > self.max then
    self.secmax := self.max;
    self.max := value;
elsif value > self.secmax then
    self.secmax := value;
end if;
return ODCIConst.Success;
end;
member function ODCIAggregateTerminate(self IN SecondMaxImpl,
    returnValue OUT number, flags IN number) return number is
begin
returnValue := self.secmax;
return ODCIConst.Success;
end;
member function ODCIAggregateMerge(self IN OUT SecondMaxImpl, ctx2 IN SecondMaxImpl) return number is
begin
if ctx2.max > self.max then
    if ctx2.secmax > self.secmax then
      self.secmax := ctx2.secmax;
    else
      self.secmax := self.max;
    end if;
    self.max := ctx2.max;
elsif ctx2.max > self.secmax then
    self.secmax := ctx2.max;
end if;
return ODCIConst.Success;
end;
end;
CREATE OR REPLACE FUNCTION SecondMax (input NUMBER) RETURN NUMBER
PARALLEL_ENABLE AGGREGATE USING SecondMaxImpl;
SELECT deptno,SecondMax(sal)
FROM emp
GROUP BY deptno;
    DEPTNO SECONDMAX(SAL)
        10           2450
        20           3000
        30           1600

How will i get the n'th highest salary????????

Hi
plz can anybody tell me the query to find nth highest salary from emp table???
Thanx
Gagan

try this
SELECT employee_name, salary,
       RANK() OVER (order by salary) AS ranking
FROM   employee) empor to get the particular ranking
SELECT emp.employee_name, emp.salary
FROM
     (SELECT employee_name, salary,
             RANK() OVER (order by salary) AS ranking
      FROM   employee) emp
WHERE emp.ranking = <rank number>

Nth Highest Salary from EMP table , need explaination

I am new to the database world and hence learning queries at the initial stages. I want to retrieve the nth highest salary from the EMP table. I was not able to find out the answer by myself , so I searched on google. The following was the answer i got :
SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Enter value for n: 2
SAL
3700
Suppose the table contains salary in the following order :
SAL
2000
3000
3700
4000
3700
2000
So how come I will get the correct answer with the abov query ? I am not able to understand the part --- WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Specially the condition WHERE a.sal<=b.sal is very confusing to me. Can anyone help me please to understand the same.

user12328699 wrote:
I am new to the database world and hence learning queries at the initial stages. I want to retrieve the nth highest salary from the EMP table. I was not able to find out the answer by myself , so I searched on google. The following was the answer i got :
SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Enter value for n: 2
SAL
3700
Suppose the table contains salary in the following order :
SAL
2000
3000
3700
4000
3700
2000
So how come I will get the correct answer with the abov query ? I am not able to understand the part --- WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Specially the condition WHERE a.sal<=b.sal is very confusing to me. Can anyone help me please to understand the same.There is many better way to get the nth highest salary
But still if you want to understand the same.
Assuming the data is sorted in ascending order, then
1) a.sal=2000, so a.sal<=b.sal results in count as 3 (not equal to user input)
2) a.sal=3700, so a.sal<=b.sal results in count as 2 (equal to user input)
3) a.sal = 4000 , so a.sal<=b.sal results in count as 1 (not equal to user input)
Hence the answer is 3700
Regards
Anurag

How to retrieve the max value from a cursor in procedure

Hi,
In a procedure, I defined a cursor:
cursor c_emp is select empno, ename, salary from emp where ename like 'J%';
but in the body part, I need to retrieve the max(salary) from the cursor.
could you please tell me how I can get the max value from the cursor in the procedure.
Thanks,
Paul

Here is one sample but you should just get the max directly. Using bulk processing should be a last resort.
DECLARE
CURSOR c1 IS (SELECT * FROM emp where sal is not null);
TYPE typ_tbl IS TABLE OF c1%rowtype;
v typ_tbl;
max_sal number;
BEGIN
OPEN c1;
max_sal := -9999999999999;
LOOP                                                 --Loop added
    FETCH c1 BULK COLLECT INTO v LIMIT 3; -- process 3 records at a time
        -- process the records
       DBMS_OUTPUT.PUT_LINE('Processing ' || v.COUNT || ' records.');
        FOR i IN v.first..v.last LOOP
             if v(i).sal > max_sal then
               max_sal := v(i).sal;
             end if;
            DBMS_OUTPUT.PUT_LINE(v(i).empno);
        END LOOP;
    EXIT WHEN c1%NOTFOUND;
END LOOP;
DBMS_OUTPUT.PUT_LINE('Max salary was: ' || max_sal);
END;
Processing 3 records.
7369
7499
7521
Processing 3 records.
7566
7654
7698
Processing 3 records.
7782
7788
7839
Processing 3 records.
7844
7876
7900
Processing 2 records.
7902
7934
Max salary was: 5000

I have lost all my notes data after restore. Anyone know how to retrieve notes after restore?

I have lost all my notes data after restore. Anyone know how to retrieve notes after restore?
I havent' took any backup of my notes in icloud. The moment I enter the password after restore my notes will be empty. The only option to get notes back is that after restore skip entering icloud password. But any time I enter icloud password anywhere again my notes will be empty. I have huge data saved in my notes. Apple need to look into this issues very seriously. This is the 5th time I restoring my iphone today just to get my note back.

I have the issue with losing all my notes and I don't even know why. I can't remember changing any email account info. What happened to them?
Ipad 3rd io7
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Thank you,
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How to retrieve the value of last identity has been updated in a database?

how to retrieve the value of last identity has been updated in a database

Hi,
Oracle 10g, FGA - Fine grained auditing, supports DML statements (9i only select).
Set up FGA using the DBMS_FGA.ADD_POLICY procudure:
sql> BEGIN
DBMS_FGA.ADD_POLICY (
policy_name => 'AUD_EMPLOYEE_SAL',
object_schema => 'HR',
object_name => 'EMPLOYEE',
audit_column => SALARY',
audit_condition => '',
statement_type => 'UPDATE');
END;
NEXT:
sql> SELECT dbuid, lsqltesxt FROM sys.fga_logs$;
The database inserts the audit record into the FGA_LOG$ table using an autonomous transaction; even if you roll back the update statement, the update action will still be logged in this table. The fga_log$ tracks the session, machine id, timestamp, schema, scn, etc:
SQL> desc fga_log$
Name Null? Type
SESSIONID NOT NULL NUMBER
TIMESTAMP# DATE
DBUID VARCHAR2(30)
OSUID VARCHAR2(255)
OSHST VARCHAR2(128)
CLIENTID VARCHAR2(64)
EXTID VARCHAR2(4000)
OBJ$SCHEMA VARCHAR2(30)
OBJ$NAME VARCHAR2(128)
POLICYNAME VARCHAR2(30)
SCN NUMBER
SQLTEXT VARCHAR2(4000)
LSQLTEXT CLOB
SQLBIND VARCHAR2(4000)
COMMENT$TEXT VARCHAR2(4000)
PLHOL LONG
STMT_TYPE NUMBER
NTIMESTAMP# TIMESTAMP(6)
PROXY$SID NUMBER
USER$GUID VARCHAR2(32)
INSTANCE# NUMBER
PROCESS# VARCHAR2(16)
XID RAW(8)
AUDITID VARCHAR2(64)
STATEMENT NUMBER
ENTRYID NUMBER
DBID NUMBER
LSQLBIND CLOB
SQL> spool off

ABAP Query to display top 5 employees who are having highest salary

How will you write a query in abap to display top 5 emplyeee records who are having Highest Salary Among all the employees.
Please Reply...

Hi Kush,
Before writing any Database Query, always keep 2 important thumb rules in your mind :
1. Keep the number of data base access small
2. Keep the amount of data transfer small.
As you mentioned the Database Table has only 100 records, you can locally buffer the Table. So, make a local buffering and then you can sort the table based on the salary.
Select *
from Table_name
into table gt_itab.
Sort gt_itab by salary descending.
Now you can read the entries one after the another based on the index.
Have a look at the following code for an efficient performance feature. Goto SE38 and have a look at the ABAP Examples.
demo_select_some_columns. Package : SABAPDEMOS
Hope this will help.
Thanks,
Samantak.

To find 2nd highest salary in employee table

Hi,
I want to know how to calculate the 2nd highest salaried employee details.
rownum "=" sign cannot be used i suppose and
with and without using orderby clause.
both the methods needed.
cheers,

With order by
select * from
   ( select q.*, rownum as rn from
      ( select * from emp order by sal desc ) q
where rn=2
/With analytics:
select empno , sal
from ( select empno , sal
              , dense_rank () over (order by sal desc) as sal_rank
       from emp )
where sal_rank = 2Notice that DENSE_RANK() might give us a different result compared to RANK() and both give us a different result from the first example.
Cheers, APC

How to retrieve 5th highest salary in a single statement

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