How to run a do-while loop on the 2nd execution after a stop on failure occurs?

I am trying to use the Stop on Failure process model callback from the TestStand Examples.
If a step fails within a Do-While loop and the test is terminated, the second time the test is run (continuing to the Next UUT in the process model), the condition for the do-while loop is checked first before it ever enters the loop. This is incorrect because the Do-While loop should execute once and then check the "while" condition.
Also, If I was to stop the execution altogether and then restart the test (instead of continuing with the Next UUT), it runs the loop once, then checks the "while" condition.
I'm not sure if I am describing this clearly enough. The execution seems to flow like this:
Start test
Do
NumericTest step FAILS -> terminate
Next UUT starts
While (condition is false and skips over Numeric Test step).
So it seems that TestStand thinks it's still within that Do-While loop on the second execution and whatever runtime variables are not reset correctly.
Is this a TestStand bug? It happens in both TestStand 3.1 and 3.5.
Is there any way around this?
Thanks for any help.

If it is what I think it is, it is a bug. Try unchecking Sequence Properties>>Optimize Non-Reentrant Calls to This Sequence and please tell me if that fixes it.

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pg22aw wrote:
I have a question about a while loop. Currently, I have 4 or 5 dynamic data lines that I would like to run through a while loop that will tell me if the data is within a certain range or not. However, the ranges are different for each piece of data, and I dont know how to do each one separately. Do I have to make 5 different while loops? Thanks!
Do you want to compare the value with a defined value and also the ranges for the 5 data is different?. What are you doing in the while loop. If the data is in an array of dynamic data you can seperate the amplitude value and check the whole array of value with the ranges that is also build same as the data theh you will get the output as a boolean array.
The best solution is the one you find it by yourself

How to code a parallel 'for loop' and 'while loop' where the while loop cannot terminate until the for loop has finished?? (queues also present)

I've attached a sample VI that I just cannot figure out how to get working the way that I want. I've labeled the some sections with black-on-yellow text boxes for clarity during the description that follows in the next few sentences. Here's what I want:
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Attachments:
daq01v1.vi ‏59 KB

I'd actually like to add a little more, since I thought about it a bit and I'm still not quite certain I understand the sequence of events...
altenbach wrote:
zskillz wrote:
So i read a bit more about the 'dequeue element' function, and as I understand it, since there is no timeout wired to the dequeue element function, it will wait forever, thus the race condition I suggested above can never happen!
Yes, you got it!
As I've thought about it a bit more, there's a few things that surprise me... first, the reason the 'dequeue element while loop' errors is not because there's nothing in the queue, it's becaues the queue has been released and it's trying to access that released queue... However the problem I have is this --- Even though there's no timeout wired to the dequeue element, I still would think that the while loop that contains it would continue to run at whatever pace it wanted -- and as i said before.. most of the time, it would find that there is nothing to dequeue, but once in a while, something is there. however, it seems that this loop only runs when something has been enqueued. the reason I say this is illustrated in the next code sample MODv2 that's attached below. I've added a stop button to the "queue size while loop" so the program runs until that is pressed. I've also added a simple conditional in the "dequeue while loop" that generates a random number if it a button is pressed... but this button is totally non-responsive... which means to me that the "dequeue while loop" isn't actually continuously running, but only when an element is added to the queue. this still seems almost like the 'dequeue while loop" waits for a notifier from the queue telling it to run. can you explain this to me? because it is different from what I expect to be happening.
rasputin wrote:
I tried to open your VIs but it doesn't work. LV
is launched, the dialog box (new, open, configure...) opens and then...
nothing. Not even an error message. I guess it isn't a problem of LV
version or a dialog box would appear saying this. Could you, please,
send a image of the code?
Thanks,
Hi Rasputin, I'm using LV8. I assume that was your problem, but who knows. I've attached a pic of of altenbach's solution since it's what I needed.
thanks
-Z
Message Edited by zskillz on 10-20-2006 11:49 AM
Attachments:
daq01v1MODv2.vi ‏63 KB
daq01v1MODpic.JPG ‏116 KB

How to out from infinite while loop in sub VI

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Attachments:
stop_subVI_frm_main.JPG ‏36 KB

Asking how to get out of an infinite loop is like asking how to find the end of a circle. I'm not trying to be sarcastic but by definition, if there is a way out of the loop, then it is not infinite. I think what you are asking is how to avoid creating an infinite loop. Is there something about the suggestions you have been given that you do not like? My favorite suggestion is the notifier but maybe you just need an example. Turn on context help and read about the notifier functions in the code below.
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=====================
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Hi.
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Polar coord assignment1.vi ‏142 KB

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Hello from Apple!
Charles at Apple Service & Support thought that you might find this article useful. We hope that it helps resolve your technical issue.
Link: http://www.info.apple.com/kbnum/n306965
Mac OS X 10.5, iMac (Late 2007): Stuck in a "loop" at the login window after upgrading to Leopard
Issue or symptom
After installing Mac OS X 10.5 Leopard on a 20-inch or 24-inch iMac (Late 2007) computer, you may not be able to log in at the login window. Your login name and password are apparently accepted, but after a blue screen appears for a few seconds, the login window reappears instead of your desktop.
Products affected
20-inch or 24-inch iMac (Late 2007) computer with 2.0, 2.4, or 2.8 GHz processors
Mac OS X 10.5 Leopard
Solution
If Leopard is installed
Start up from the Leopard Install DVD and perform an Archive and Install installation (and select Preserve Users and Network Settings).
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How to run a do-while loop on the 2nd execution after a stop on failure occurs?

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