How to run this query to get the minutes between two hours?

Hi all,
Hope doing well,
sir i am running one query which is:
v_TotalHrsMin1 := LPAD((extract(minute from TO_TIMESTAMP (v_Temphrs,'HH24:mi:ss')) - extract(minute from TO_TIMESTAMP (v_Outtime1,'HH24:mi:ss'))), 2, '0');--select to_date(v_temphrs,'YYYY-MM-DD HH:mi:ss')-to_date(v_OutPunch,'YYYY-MM-DD HH:mi:ss')*1440;
in this v_TotalHrsMin1 is number datatype and v_Temphrs is varchar2 which is storing this value: 12:00:00
and v_Outtime1 is varchar2 which is storing 06:00:00
now i want the minute difference between both times
and insert into v_Totalmin1.
but getting null value in v_totalmin1.
thanks

952646 wrote:
Hi Sir,
i used query like this: v_TotalHrsMin1 := extract(hour from time_interval) * 60 + extract(minute from time_interval) from (select to_timestamp(v_temphrs,'HH24:MI:SS')-to_timestamp(v_outtime1,'HH24:MI:SS') time_interval from dual);That is not a query - that is a PL/SQL assignment expression. You should learn the differences between SQL and PL/SQL and how they work together ;-)
When doing it in PL/SQL, you do not need a query at all. Why would you do a select from dual in the PL/SQL assignment.
But you should be able to take the SQL example I gave you and write the equivalent PL/SQL code.
We do not want to do your work for you - we want to teach you how to do it yourself.
You should try and understand the examples we give you - not just cut-and-paste it and cry for help when you are cut-and-pasting a SQL example into PL/SQL code.
Anyway - here's a way to do it in PL/SQL:
declare
   v_outtime1 varchar2(8);
   v_temphrs   varchar2(8);
   v_interval interval day to second;
   v_totalhrsmin1 number;
begin
   v_outtime1 := '06:00:00';
   v_temphrs := '12:00:00';
   v_interval := to_timestamp(v_temphrs,'HH24:MI:SS')-to_timestamp(v_outtime1,'HH24:MI:SS');
   v_totalhrsmin1 := extract(hour from v_interval) * 60 + extract(minute from v_interval);
end;
/What's so difficult about taking my SQL example, understanding what the differenct functions do, and then write that piece of PL/SQL? ;-)

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How to modify this query to get the desired output format

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AND AC.R_CONSTRAINT_NAME IS NOT NULL);
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TAKE THE CASE OF SCOTT.EMP(AS INPUT TO YOUR QUERY)
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Try this query
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Need a sql query to get the difference between two timestamp in the format of hh:mm:ss.msec

I have a database table where it keeps record of the transaction when it starts at StartTime and when it ends at EndTime. Both these entries are having the timestamp entries. Say for example, I have a tuple with Entries like 'Transaction A' starts at '2014-05-07
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Hi,
You can use below script which calculates difference as DD:HH:MM:SS. You can modify the same:
DECLARE @startTime DATETIME
DECLARE @endTime DATETIME
SET @startTime = '2013-11-05 12:20:35'
SET @endTime = '2013-11-10 01:22:30'
SELECT [DD:HH:MM:SS] =
CAST((DATEDIFF(HOUR, @startTime, @endTime) / 24) AS VARCHAR)
+ ':' +
CAST((DATEDIFF(HOUR, @startTime, @endTime) % 24) AS VARCHAR)
+ ':' +
CASE WHEN DATEPART(SECOND, @endTime) >= DATEPART(SECOND, @startTime)
THEN CAST((DATEDIFF(MINUTE, @startTime, @endTime) % 60) AS VARCHAR)
ELSE
CAST((DATEDIFF(MINUTE, DATEADD(MINUTE, -1, @endTime), @endTime) % 60)
AS VARCHAR)
END
+ ':' + CAST((DATEDIFF(SECOND, @startTime, @endTime) % 60) AS VARCHAR),
[StringFormat] =
CAST((DATEDIFF(HOUR , @startTime, @endTime) / 24) AS VARCHAR) +
' Days ' +
CAST((DATEDIFF(HOUR , @startTime, @endTime) % 24) AS VARCHAR) +
' Hours ' +
CASE WHEN DATEPART(SECOND, @endTime) >= DATEPART(SECOND, @startTime)
THEN CAST((DATEDIFF(MINUTE, @startTime, @endTime) % 60) AS VARCHAR)
ELSE
CAST((DATEDIFF(MINUTE, DATEADD(MINUTE, -1, @endTime), @endTime) % 60)
AS VARCHAR)
END +
' Minutes ' +
CAST((DATEDIFF(SECOND, @startTime, @endTime) % 60) AS VARCHAR) +
' Seconds '
Reference:
http://sqlandme.com/2013/12/23/sql-server-calculating-elapsed-time-from-datetime/
- Vishal
SqlAndMe.com

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want to see the result similar to this *(please ignore the column names here this is just a plain exemple:)
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I am looking for only column compare for making my target table same as source table.
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select case when column_name_s is null and column_name_t is not null
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from (select s.column_name column_name_s,t.column_name column_name_t,
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          from (select column_id,column_name,data_type
                  from all_tab_cols@database
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                  from all_tab_cols@database
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LETTER_GRADE
VARCHAR2(2)
GRADE_POINT
NUMBER(3,2)
MAX_GRADE
NUMBER(3)
MIN_GRADE
NUMBER(3)
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LETTER_GRADE
VARCHAR2(2)
GRADE_POINT
NUMBER(3,2)
MAX_GRADE
NUMBER(3)
MIN_GRADE
NUMBER(3)
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VARCHAR2(30)
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If you have any questions, please feel free to ask.
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Katherine Xiong
Katherine Xiong
TechNet Community Support

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============================================
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regards,
Prashanth

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http://joda-time.sourceforge.net/faq.html
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Hi, You can use the following function module to calculate the diffrence between to dates in the unit that you want.
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Message was edited by:
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I have a problem with methods that involves objects such as:
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How to run this query to get the minutes between two hours?

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