How to search and delete repeated elements in a vector

Question

Hi again,
In a class of my application, it needs to check in a vector (A), if there are repeated elements, if it founds one, then it is replaced for a *. then the elements different from * are copied into a new vector(Aa). the code is the following:
//here are defined the components Textfield, etc
public void Bconj_Action(Object target)
          int idx = 0;
          int tokenCount;
          String var="";
          String var2="";
          String A[] = new String [50];
          String Aa[] = new String [50];
          String message = (TxtA.getText());
          StringTokenizer st = new StringTokenizer(message,",");
          tokenCount = st.countTokens();
          while (st.hasMoreTokens())
               A[idx] = st.nextToken();
               idx++;
          //Recorre vector A en busca de repetidos     
          for(int n=0;n<tokenCount-1;n++)
          for(int m=n+1;m<tokenCount;m++)
          if (A[m]==A[n] && A[n]!="*")
               A[n]="*";
          //Recorre nuevamente el vector A buscando los diferente a * que seran copiados al vector Aa
          int o = 0;
          for (int n=1;n<tokenCount;n++)
          if(A[n]!="*")
          Aa[o]=A[n];
               o++;
          for (int i=0;i<tokenCount; i++)
                    if (i==0){
                    var=Aa;}
                              else{
                              var = var + "," + Aa[i];}
               TxtA.setText("");
               TxtU.setText(var);
when I run it, and I enter to the prog 1, it don't show me nothing, when I enter 1,1 it shows me 1,null and so on.
do you have any ideas of what is happening.
Thanks in advance.

Answer 1

Two things I would point out to you:
Its possible that the way you are comparing the Strings is causing a problem for you.
if (A[m]==A[n] && A[n]!="*")
A[n]="*";
}A[m] and A[n] are two Strings so you should compare them using
A[m].equals(A[n]).So the if statement should look like this:
if (A[m].equals(A[n]) && !A[n].equals("*"))
A[n]="*";
}And second:
When you copy the unique elements over to array Aa you may be copying less that tokenCount elements. You are actually copying o elements.
The final for loop could be modified like this:
for (int i=0;i<o; i++)
if (i==0){
var=Aa;}
else{
var = var + "," + Aa[i];}
TxtA.setText("");
TxtU.setText(var);
} Thus it prints only the unique elements found rather than the whole array which may contain nulls.