How to show different templates in one column
Hello friends,
I've a data like this one:
var aData = [
{name: "Dente", company: "http://www.sap.com"},
{name: "Friese", company: "Google"},
{name: "Mann", company: "http://www.sap.com"},
{name: "Schutt", company: "SAP"}
and want to be showed in the table :
if the 'company' begin with "http" , it should be a link,
else, shows as a text
How to do this ?
Could you help me ?
Thank you
Here is a short demo can run in https://openui5.hana.ondemand.com/#test-resources/sap/ui/table/demokit/Table.html
but is not completed.
Demo for test:
var aData = [
{name: "Dente", company: "http://www.sap.com"},
{name: "Friese", company: "Google"},
{name: "Mann", company: "http://www.sap.com"},
{name: "Schutt", company: "SAP"}
//Create an instance of the table control
var oTable2 = new sap.ui.table.Table({
title: "Table with fixed columns Example",
visibleRowCount: 7,
firstVisibleRow: 3,
selectionMode: sap.ui.table.SelectionMode.Single,
navigationMode: sap.ui.table.NavigationMode.Paginator,
fixedColumnCount: 2
//Define the columns and the control templates to be used
oTable2.addColumn(new sap.ui.table.Column({
label: new sap.ui.commons.Label({text: "Name"}),
template: new sap.ui.commons.TextField().bindProperty("value", "name"),
sortProperty: "name",
filterProperty: "name",
width: "200px"
oTable2.addColumn(new sap.ui.table.Column({
label: new sap.ui.commons.Label({text: "Company"}),
template: new sap.ui.commons.Link().bindProperty("text", "company").bindProperty("href", "company"),
sortProperty: "linkText",
filterProperty: "linkText",
width: "400px"
//Create a model and bind the table rows to this model
var oModel2 = new sap.ui.model.json.JSONModel();
oModel2.setData({modelData: aData});
oTable2.setModel(oModel2);
oTable2.bindRows("/modelData");
//Initially sort the table
oTable2.sort(oTable2.getColumns()[0]);
//Bring the table onto the UI
oTable2.placeAt("sample2");
HI Sihao
will this work?
Example
Thanks
-D
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