How to specify a parser? xml newbie

Hello
I am an XML newbie. I need to validate an XML using xerces 2.7.0. I do not want to use JAXP. (because it does not support xsd:unique).
xerces supports is. My problem is very simple. How do I force my parser to use xerces.
Please provide code sample.
Thank you

My other question is:
How do I verify what parser am I using?
Obviously, I have no clue what I am doing.

Similar Messages

How do you store parsed XML data in an array

Hi, i am trying to complete a small program which implements the SAX parser to parse an XML file. My problem is that i am writing a custom class to store the parsed data into an array, and then make the array available to the main program via a simple method which returns the array. I know this must be very simple to do, but i seem to have developed a mental block with this part of the program. I can parse the data and print all the elements to the screen, but i just cant figure out how to store all the data elements into the array. I will post the class which is supposed to do this, and ask anyone out there if they know what i'm doing wrong, and also, if there is a more effeicient way of achieving this ( i expect there definitely is!! but i have never used the SAX parser before and am getting confused by the API docs on it!!) Any help very much appreciated.
Here is my attempt at coding the class to handle the parsed XML data
class Sink extends org.xml.sax.helpers.DefaultHandler
 implements org.xml.sax.ContentHandler{
Customer[] customers = new Customer[20];
 int count = 1;
 int x = 0;
 int tagCount = 0;
 String name;
String custID;
 String username;
 String address;
 String phoneNum;
public void startElement(String uri, String localName, String rawName, final org.xml.sax.Attributes attributes)throws org.xml.sax.SAXException{
//count the number of <name> tags in the XML file
 if(rawName.equals("name")){
 tagCount++;
public void characters(char[] ch, int start, int len){
//get the current string
 String text = new String(ch, start, len);
 String text1 = text.trim();
//there are 5 elements for each customer found in the XML file so when the count reaches 6
// i reset this to 1
 if(count == 6){
 count = count - 5;
 if(text1.length()>0 && count == 1){
 name = text1;
 System.out.println(name);
 }else{
 if(text1.length()>0 && count == 2){
 custID = text1;
 System.out.println(custID);
 }else{
 if(text1.length()>0 && count == 3){
 username = text1;
 System.out.println(username);
 }else{
 if(text1.length()>0 && count == 4){
 address = text1;
 System.out.println(address);
 }else{
 if(text1.length()>0 && count == 5){
 phoneNum = text1;
 System.out.println(phoneNum);
 //add data to the customer array
 customers[x] = new Customer(name, custID, username, address, phoneNum);
// increment the array index counter
 x = x+1;
 }//end of if
 }//end else
 }//end else
 }//end else
 }//end else
}//end of characters method
public void endDocument(){
 System.out.println("There are " + tagCount +
 " <name> elements.");
}//end of class Sink
Before the end of this class i also need to make the array available to the calling program!!
Any help would be much appreciated
Thanks
Iain

Ok, yer going about this all the wrong way. You shouldn't have to maintain a count of all the elements. Basically you are locking yourself into the XML tags not only all being there but are assuming they are all in the same order. What you should do is in your characters() method, put all of the characters into a string buffer. Then, in endElement() (which you dont use btw, you should) you grab the information that is in the string buffer and store it into your Customer object depending on what the tagName is.
Also, you should probably use a List to store all the Customer objects and not an single array, it's more dynamic and you arent locked into a set number of Customers.
I wont do it all for you, but I'll give you a good outline to use.
public class CustomerHandler extends DefaultHandler {
 private java.util.List customerList; // List of Customer objects
 private java.util.StringBuffer buf; // StringBuffer to store the string of characters between the start and end tags
 private Customer customer; // Customer object that is initialized with each entry.
 public CustomerHandler() {
 customerList = new java.util.ArrayList(); // Initialize the List
 buf = new java.util.StringBuffer(); // Initialize the string buffer
 // Make your customer list available to other classes
 public java.util.List getCustomerList() {
 return customerList;
 public void startElement(String nsURI, String sName, String tagName, Attributes attributes) throws SAXException {
 // Clear the String Buffer
 // If the tagName is "Customer" then create a new Customer object
 public void characters(char[] ch, int start, int length) {
 // append the characters into the string buffer
 public void endElement(String nsURI, String sName, String tagName) throws SAXException {
 // If the tagName is "Customer" add your customer object to the List
 // Place the data from the String Buffer into a String
 // Depending on the tagName, call the appropriate set method on your customer object
}

How to compare after parsing xml file

Hi,
following code, parse the input.xml file, counts how many nodes are there and writes the node name and its value on screen.
1) i am having trouble writing only node name into another file instead of writing to screen.
2) after parsing, i like to compare each node name with another .xsd file for existence.
Please keep in mind that, input.xml is based on some other .xsd and after parsing i have comparing its tag with another .xsd
Need you help guys.
thanks
* CompareTags.java
import java.io.*;
import org.w3c.dom.*;
import org.xml.sax.*;
import javax.xml.parsers.*;
import javax.xml.transform.*;
import javax.xml.transform.dom.*;
import javax.xml.transform.stream.*;
/** This class represents short example how to parse XML file,
* get XML nodes values and its values. 
* It implements method to save XML document to XML file too
public class CompareTags {
private final static String xmlFileName = "C:/input.xml";
 int totalelements = 0;
/** Creates a new instance of ParseXMLFile */
public CompareTags() {
// parse XML file -> XML document will be build
Document doc = parseFile(xmlFileName);
// get root node of xml tree structure
Node root = doc.getDocumentElement();
// write node and its child nodes into System.out
System.out.println("Statemend of XML document...");
writeDocumentToOutput(root,0);
 System.out.println("totalelements in xyz tag " + totalelements);
 System.out.println("... end of statement");
/** Returns element value
* @param elem element (it is XML tag)
* @return Element value otherwise empty String
public final static String getElementValue( Node elem ) {
Node kid;
if( elem != null){
if (elem.hasChildNodes()){
for( kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling() ){
if( kid.getNodeType() == Node.TEXT_NODE ){
return kid.getNodeValue();
return "";
private String getIndentSpaces(int indent) {
StringBuffer buffer = new StringBuffer();
for (int i = 0; i < indent; i++) {
buffer.append(" ");
return buffer.toString();
/** Writes node and all child nodes into System.out
* @param node XML node from from XML tree wrom which will output statement start
* @param indent number of spaces used to indent output
public void writeDocumentToOutput(Node node,int indent) {
// get element name
String nodeName = node.getNodeName();
// get element value
String nodeValue = getElementValue(node);
// get attributes of element
NamedNodeMap attributes = node.getAttributes();
System.out.println(getIndentSpaces(indent) + "NodeName: " + nodeName + ", NodeValue: " + nodeValue);
for (int i = 0; i < attributes.getLength(); i++) {
Node attribute = attributes.item(i);
System.out.println(getIndentSpaces(indent + 2) + "AttributeName: " + attribute.getNodeName() + ", attributeValue: " + attribute.getNodeValue());
// write all child nodes recursively
NodeList children = node.getChildNodes();
 //int totalelements = 0;
for (int i = 0; i < children.getLength(); i++) {
Node child = children.item(i);
 // System.out.println("child value.."+child);
if (child.getNodeType() == Node.ELEMENT_NODE) {
writeDocumentToOutput(child,indent + 2);
 if(node.getNodeName() == "DATA"){
 totalelements = totalelements+1;}
 //System.out.println("totalelements in DATA tag " + totalelements);
/** Parses XML file and returns XML document.
* @param fileName XML file to parse
* @return XML document or null if error occured
public Document parseFile(String fileName) {
System.out.println("Parsing XML file... " + fileName);
DocumentBuilder docBuilder;
Document doc = null;
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
docBuilderFactory.setIgnoringElementContentWhitespace(true);
try {
docBuilder = docBuilderFactory.newDocumentBuilder();
catch (ParserConfigurationException e) {
System.out.println("Wrong parser configuration: " + e.getMessage());
return null;
File sourceFile = new File(fileName);
try {
doc = docBuilder.parse(sourceFile);
catch (SAXException e) {
System.out.println("Wrong XML file structure: " + e.getMessage());
return null;
catch (IOException e) {
System.out.println("Could not read source file: " + e.getMessage());
System.out.println("XML file parsed");
return doc;
/** Starts XML parsing example
* @param args the command line arguments
public static void main(String[] args) {
new CompareTags();
}

hi,
check out the following links
Check this blog to extract from XML:
/people/kamaljeet.kharbanda/blog/2005/09/16/xi-bi-integration
http://help.sap.com/saphelp_nw04/helpdata/en/fe/65d03b3f34d172e10000000a11402f/frameset.htm
Check thi link for Extract from any DB:
http://help.sap.com/saphelp_nw04s/helpdata/en/58/54f9c1562d104c9465dabd816f3f24/content.htm
regards
harikrishna N

How to get and parse xml input parameter?

Hi,
If one transaction input parameter is xml string, like as below.
<a>

 <c>1</c>
 <d>2</d>


 <c>3</c>
 <d>4</d>

</a>
If I would like to get each element (maybe by repeater action), how to do that?
Thanks!

Hi,
You must convert the string into xml with necessary action block. (XML Functions --> String to XML Parser)
Then you must put a repeater after converter action and you must set Xpath expression for repeater (configuration) like below:
String_To_XML_Parser_0.Output{/ARef/BRef}
after repeater you can use values like below:
Repeater.Output{/BRef/c}
Repeater.Output{/BRef/d}
Regards.

How to generate GUI code from parsed XML file?

hai,
I have to generate GUI code after parsing any configuration XML file as input.Now i have parsed my XML file and got its attributed and i want to get some idea of how to map the parsed XML attributes to the java code to build GUI code.

Hello,
1. I like to create data type from a XML file structure, which contains the data structure ?
XML fields will need to be taken note of to see which is repeating or not. You can also load the XML into a third-party tool such as Altova XML Spy and then generate an XSD from there. You will need to import the XSDs into PI under external definitions. However, this does not guarantee business interoperability, as such, it is always best to ask the provider for the XSDs or WSDL. It will also save you a lot of time from guessing which fields are needed or not.
2. How to create custom node function in graphical mapping editor ?
In your graphical mapping editor, on the lowest left corner, there is an icon there that says Create New Function. You must take into account their return types:
1. Single Values = String
2. Queue/Context (no return type) thus resultList is used.
Hope this helps,
Mark

How to Output Nodes from XML web service to a FLV?

Hi
I've used AS3 to query a web service and obtain the resulting XML. I need to parse the result down to just a few nodes for a given location. I can tackle that separately. I am wondering how I output the parsed XML to a flash video file (.flx)? The video has place holders for the XML node values. What do I need to do to place the XML results in the video?
Thanks,
Sid

Andrei1 wrote:
What is a content of XML nodes? I am not sure what you mean by "inserting nodes". Do you mean that you want to display some information over the video?
And yes, encoders do take XMLs to inject metadata into video. But this is metadata only.
OSML = Open Source Media Framework:
http://www.opensourcemediaframework.com/
By inserting nodes, I mean that the XML web service returns data for each city, which needs to be parsed to just high temp, low temp and current condition. Those 3 values needed to be dispalyed over, or woven into, the video at each city location. My thought was that AS3 could somehow recognize the 3 placeholders for each city and insert the high temp, low temp and condition icon into each placeholder. However, when I import the FLV file into Flash, there are no elements into which I can infuse this data.

How to specify page encoding for XML reports.

Hi,
Environment: Apps:11.5.10, Oracle Reports: 10g
I'm trying to generate XML tags by using a "rdf" report (10g).
Initially I generated the XML tags before moving the report to server. In the output file I got
<?xml version="1.0" encoding="WINDOWS-1252"?>
Then I moved the report to server and made the concurrent program output to XML.
In the concurrent program output the tag is
<?xml version="1.0" encoding="&Encoding"?>
The output shows error
===============
XML Parsing Error: XML declaration not well-formed
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
<?xml version="1.0" encoding="&Encoding"?>
Its clear that there is something wrong with page encoding format which has to get assigned while run time. But its not happening so.
How to specify the page encoding format?
Any help would be appreciated.
Thank you
BKR.
Edited by: BalaKrishna Reddy Avuthu on Aug 14, 2009 2:00 PM

Remove the encoding so it says:
<?xml version="1.0"?>
Also, you will get a similar error if your xml tags for fields contain any special characters like & or #.

How to specify URL in server.xml of Tomcat

Hi Everybody,
I need help.How to specify url in the server.xml.
I developed one application in the Tomcat 3.3.I want to access the by entering uri(like:http:test.com).
What are tags to enter in the server.xml.
Right now i am accessing like:http://localhost:8080/Test/Login.jsp
I want replace this with (www.test.com).
This site will access from anywhere means it is going to live.
So what are things have to do in the server.xml
Please provide the solution.
Regards
Sridhar

Hi Raktim:
I looked around on SDN and it seems that i have found what you have been looking for.
Kindly look at page number 24 and 25 of this page
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/4d46fb8a-0b01-0010-9fbe-e4b96533b222
P.S: Kindly assign points if your query is resolved, also close the question to assist other users narrow the search and find solutions

How to parse XML to Java object... please help really stuck

Thank you for reading this email...
If I have a **DTD** like:
<!ELEMENT person (name, age)>
<!ATTLIST person
 id ID #REQUIRED
>
<!ELEMENT name ((family, given) | (given, family))>
<!ELEMENT age (#PCDATA)>
<!ELEMENT family (#PCDATA)>
<!ELEMENT given (#PCDATA)>
the **XML** like:
<person id="a1">
<name>
 <family> Yoshi </family>
 <given> Samurai </given>
</name>
<age> 21 </age>
</person>
**** Could you help me to write a simple parser to parse my DTD and XML to Java object, and how can I use those objects... sorry if the problem is too basic, I am a beginner and very stuck... I am very confuse with SAXParserFactory, SAXParser, ParserAdapter and DOM has its own Factory and Parser, so confuse...
Thank you for your help, Yo

Hi, Yo,
Thank you very much for your help. And I Wish you are there...I'm. And I plan to stay - It's sunny and warm here in Honolulu and the waves are up :)
A bit more question for dear people:
In the notes, it's mainly focus on JAXB,
1. Is that mean JAXB is most popular parser for
parsing XML into Java object? With me, definitely. There are essentially 3 technologies that allow you to parse XML documents:
1) "Callbacks" (e.g. SAX in JAXP): You write a class that overrides 3 methods that will be called i) whenever the parser encounters a start tag, ii) an end tag, or iii) PCDATA. Drawback: You have to figure out where the heck in the document hierarchy you are when such a callback happens, because the same method is called on EACH start tag and similarly for the end tag and the PCDATA. You have to create the objects and put them into your own data structure - it's very tedious, but you have complete control. (Well, more or less.)
2) "Tree" (e.g. DOM in JAXP, or it's better cousin JDOM): You call a parser that in one swoop creates an entire hierarchy that corresponds to the XML document. You don't get called on each tag as with SAX, you just get the root of the resulting tree. Drawback: All the nodes in the tree have the same type! You probably want to know which tags are in the document, don't you? Well, you'll have to traverse the tree and ask each node: What tag do you represent? And what are your attributes? (You get only strings in response even though your attributes often represent numbers.) Unless you want to display the tree - that's a nice application, you can do it as a tree model for JTree -, or otherwise don't care about the individual tags, DOM is not of much help, because you have to keep track where in the tree you are while you traverse it.
3) Enter JAXB (or Castor, or ...): You give it a grammar of the XML documents you want to parse, or "unmarshall" as the fashion dictates to call it. (Actually the name isn't that bad, because "parsing" focuses on the input text while "unmarshalling" focuses on the objects you get, even though I'd reason that it should be marshalling that converts into objects and unmarshalling that converts objects to something else, and not vice versa but that's just my opinion.) The JAXB compiler creates a bunch of source files each with one (or now more) class(es) (and now interfaces) that correspond to the elements/tags of your grammar. (Now "compiler" is a true jevel of a misnomer, try to explain to students that after they run the "compiler", they still need to compile the sources the "compiler" generated with the real Java compiler!). Ok, you've got these sources compiled. Now you call one single method, unmarshall() and as a result you get the root node of the hierarchy that corresponds to the XML document. Sounds like DOM, but it's much better - the objects in the resulting tree don't have all the same type, but their type depends on the tag they represent. E.g if there is the tag <ball-game> then there will be an object of type myPackage.BallGame in your data structure. It gets better, if there is <score> inside <ball-game> and you have an object ballGame (of type BallGame) that you can simply call ballGame.getScore() and you get an object of type myPackage.Score. In other words, the child tags become properties of the parent object. Even better, the attributes become properties, too, so as far as your program is concerned there is no difference whether the property value was originally a tag or an attribute. On top of that, you can tell in your schema that the property has an int value - or another primitive type (that's like that in 1.0, in the early release you'll have to do it in the additional xjs file). So this is a very natural way to explore the data structure of the XML document. Of course there are drawbacks, but they are minor: daunting complexity and, as a consequence, very steep learning curve, documentation that leaves much to reader's phantasy - read trial and error - (the user's guide is too simplicistic and the examples too primitive, e.g. they don't even tell you how to make a schema where a tag has only attributes) and reference manual that has ~200 pages full of technicalities and you have to look with magnifying glas for the really usefull stuff, huge number of generated classes, some of which you may not need at all (and in 1.0 the number has doubled because each class has an accompanying interface), etc., etc. But overall, all that pales compared to the drastically improved efficiency of the programmer's efforts, i.e. your time. The time you'll spend learning the intricacies is well spent, you'll learn it once and then it will shorten your programming time all the time you use it. It's like C and Java, Java is order of magnitude more complex, but you'd probably never be sorry you gave up C.
Of course the above essay leaves out lots and lots of detail, but I think that it touches the most important points.
A word about JAXB 1.0 vs. Early Release (EA) version. If you have time, definitively learn 1.0, they are quite different and the main advantage is that the schema combines all the info that you had to formulate in the DTD and in the xjs file when using the EA version. I suggested EA was because you had a DTD already, but in retrospect, you better start from scratch with 1.0. The concepts in 1.0 are here to stay and once your surmounted the learning curve, you'll be glad that you don't have to switch concepts.
When parser job is done,
what kind of Java Object we will get? (String,
InputStream or ...)See above, typically it's an object whose type is defined as a class (and interface in 1.0) within the sources that JABX generates. Or it can be a String or one of the primitive types - you tell the "compiler" in the schema (xjs file in EA) what you want!
2. If we want to use JAXB, we have to contain a
XJS-file? Something like:In EA, yes. In 1.0 no - it's all in the schema.
I am very new to XML, is there any simpler way to get
around them? It has already take me 4 days to find a
simple parser which give it XML and DTD, then return
to me Java objects ... I mean if that kind of parser
exists....It'll take you probably magnitude longer that that to get really familiar with JAXB, but believe me it's worth it. You'll save countless days if not weeks once you'll start developing serious software with it. How long did it take you to learn Java and it's main APIs? You'll either invest the time learning how to use the software others have written, or you invest it writing it yourself. I'll take the former any time. But it's only my opinion...
Jan

How to parse XML Column and insert values into a table

Hello,
I am working on a simple project to demonstrate how to load and extract XML using SQL, I have already made a table that contains a column of XMLTYPE and loaded an XML file into it (code below)
create or replace directory XMLSRC as 'C:\XMLSRC';
drop table Inventory;
create table Inventory(Inv XMLTYPE);
INSERT INTO Inventory VALUES (XMLTYPE(bfilename('XMLSRC', 'Inventory.xml'),nls_charset_id('AL32UTF')));
select * from Inventory;
I now however need to get the XML data back out of that and loaded into a new table. Troubleshooting guides I have read online seem to only be dealing with parsing an external XML document and loading it into a table, and not what I need to do which is parse a column of XML data and load that into a table. The project trivial with simple tables containing only 3 columns.
The table that needs to be loaded is as follows:
create table InventoryOut(PartNumber Number(10), QTY Number(10), WhLocation varchar2(500));
The XML document is as follows:
<?xml version="1.0" encoding="UTF-8"?>
<dataroot xmlns:od="urn:schemas-microsoft-com:officedata" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Inventory.xsd" generated="2012-04-09T17:36:30">
<Inventory>
<PartNumber>101</PartNumber>
<QTY>12</QTY>
<WhLocation>WA</WhLocation>
</Inventory>
</dataroot>
Thank you for any help you can offer.

First of all, thank you for your help!! Still stunned that you actually took the time to write out an eample using my tables/names/etc. Thank you!!
Attached is the code, there seems to be an issue with referencing the other table, Inventory.Inv, I checked and that table and the Inv column are showing up in the database so I am not sure why it is having issues locating them, take a look at the code I wrote as well as the output (*I included the real version number for you this time :)
EDIT: In your code right here:
select xt.*
3 from Inventory inve,
4 XMLTable('/dataroot/Inventory'
5 PASSING inve.Inv
I think is where I am messing it up, perhaps not understanding fully what is going on, as you write "Inventory inve" and "inve.Inv" ---- Is inve a keyword that I am just not familiar with? I think this is where the issues lies in my code.
END EDIT
EDIT2: Well that looks like it was it, changed that to how you have it and it now works!!! Could you please explain what that few lines is doing, and what the xt.* and inve are doing? Thanks again!!!
END EDIT2
drop table InventoryOut;
create table InventoryOut (PartNumber number(10), QTY number(10), WhLocation varchar2(500));
insert into InventoryOut (PartNumber, QTY, WhLocation)
select xt.*
from Inventory Inv,
XMLTable('/dataroot/Inventory'
PASSING Inventory.Inv COLUMNS
PartNumber number path 'PartNumber',
QTY number path 'QTY',
WhLocation path 'WhLocation')xt;
select * from InventoryOut;
select * from v$version;
table INVENTORYOUT dropped.
table INVENTORYOUT created.
Error starting at line 4 in command:
insert into InventoryOut (PartNumber, QTY, WhLocation)
select xt.*
from Inventory Inv,
XMLTable('/dataroot/Inventory'
PASSING Inventory.Inv COLUMNS
PartNumber number path 'PartNumber',
QTY number path 'QTY',
WhLocation path 'WhLocation')xt
Error at Command Line:8 Column:12
Error report:
SQL Error: ORA-00904: "INVENTORY"."INV": invalid identifier
00904. 00000 - "%s: invalid identifier"
*Cause:
*Action:
PARTNUMBER QTY WHLOCATION
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
CORE 11.2.0.1.0 Production
TNS for 32-bit Windows: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
If this helps here is the code and output for the creation of the Inventory table itself:
create or replace directory XMLSRC as 'C:\XMLSRC';
drop table Inventory;
create table Inventory(Inv XMLTYPE);
INSERT INTO Inventory VALUES (XMLTYPE(bfilename('XMLSRC', 'Inventory.xml'),nls_charset_id('AL32UTF')));
select * from Inventory;
directory XMLSRC created.
table INVENTORY dropped.
table INVENTORY created.
1 rows inserted.
INV
<?xml version="1.0" encoding="WINDOWS-1252"?>
<dataroot xmlns:od="urn:schemas-microsoft-com:officedata" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Inventory.xsd" generated="2012-04-09T17:36:30">
<Inventory>
<PartNumber>101</PartNumber>
<QTY>12</QTY>
<WhLocation>WA</WhLocation>
</Inventory>
</dataroot>
Thanks again for your help so far! Hope we can get this working :)
Edited by: 926502 on Apr 11, 2012 2:47 PM
Edited by: 926502 on Apr 11, 2012 2:49 PM
Edited by: 926502 on Apr 11, 2012 2:54 PM
Edited by: 926502 on Apr 11, 2012 2:54 PM
Updated issue to solved - Edited by: 926502 on Apr 11, 2012 2:55 PM

How to parse xml

Hi All
I want to parse xml document which contains more then one occurrence of particular element.
I want to get some sub elements of that element and want take action on the basis of param tag inside this sub element.
for example :
<appender name="first" class="tempclass...">
<param name="File" value="d:/test.log" />
<filter class="">
<param name="LevelToMatch" value="sdsds" />
<param name="OtherParam" value="bla bla" />
</filter>
</appender>
<appender name="second" class="tempclass...">
</appender>
my problem is how do i differentiate all "<appender>".
I want values of "File" and "LevelToMatch" for each declaired appender
and depending upon the values i want to take some decision.
I dont know XML much
I am using DOM parser.
Please help me ASAP.
Thanks in advance,

hi,
i hope u need to get the attribute values, right...
if yes..create the DocumentBuilderFactory for the xml the uisng buildFactory method u will get the parser...from parser u cann go for anything....
if u r not clearly, reply where do u struck...
bye,
suryakant.

How to parse xml data into java component

hi
everybody.
i am new with XML, and i am trying to parse xml data into a java application.
can anybody guide me how to do it.
the following is my file.
//MyLogin.java
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.*;
class MyLogin extends JFrame implements ActionListener
     JFrame loginframe;
     JLabel labelname;
     JLabel labelpassword;
     JTextField textname;
     JPasswordField textpassword;
     JButton okbutton;
     String name = "";
     FileOutputStream out;
     PrintStream p;
     Date date;
     GregorianCalendar gcal;
     GridBagLayout gl;
     GridBagConstraints gbc;
     public MyLogin()
          loginframe = new JFrame("Login");
          gl = new GridBagLayout();
          gbc = new GridBagConstraints();
          labelname = new JLabel("User");
          labelpassword = new JLabel("Password");
          textname = new JTextField("",9);
          textpassword = new JPasswordField(5);
          okbutton = new JButton("OK");
          gbc.anchor = GridBagConstraints.NORTHWEST;
          gbc.gridx = 1;
          gbc.gridy = 5;
          gl.setConstraints(labelname,gbc);
          gbc.anchor = GridBagConstraints.NORTHWEST;
          gbc.gridx = 2;
          gbc.gridy = 5;
          gl.setConstraints(textname,gbc);
          gbc.anchor = GridBagConstraints.NORTHWEST;
          gbc.gridx = 1;
          gbc.gridy = 10;
          gl.setConstraints(labelpassword,gbc);
          gbc.anchor = GridBagConstraints.NORTHWEST;
          gbc.gridx = 2;
          gbc.gridy = 10;
          gl.setConstraints(textpassword,gbc);
          gbc.anchor = GridBagConstraints.NORTHWEST;
          gbc.gridx = 1;
          gbc.gridy = 15;
          gl.setConstraints(okbutton,gbc);
          Container contentpane = getContentPane();
          loginframe.setContentPane(contentpane);
          contentpane.setLayout(gl);
          contentpane.add(labelname);
          contentpane.add(labelpassword);
          contentpane.add(textname);
          contentpane.add(textpassword);
          contentpane.add(okbutton);
          okbutton.addActionListener(this);
          loginframe.setSize(300,300);
          loginframe.setVisible(true);
     public static void main(String a[])
          new MyLogin();
     public void reset()
          textname.setText("");
          textpassword.setText("");
     public void run()
          try
               String text = textname.getText();
               String blank="";
               if(text.equals(blank))
                  System.out.println("First Enter a UserName");
               else
                    if(text != blank)
                         date = new Date();
                         gcal = new GregorianCalendar();
                         gcal.setTime(date);
                         out = new FileOutputStream("log.txt",true);
                         p = new PrintStream( out );
                         name = textname.getText();
                         String entry = "UserName:- " + name + " Logged in:- " + gcal.get(Calendar.HOUR) + ":" + gcal.get(Calendar.MINUTE) + " Date:- " + gcal.get(Calendar.DATE) + "/" + gcal.get(Calendar.MONTH) + "/" + gcal.get(Calendar.YEAR);
                         p.println(entry);
                         System.out.println("Record Saved");
                         reset();
                         p.close();
          catch (IOException e)
               System.err.println("Error writing to file");
     public void actionPerformed(ActionEvent ae)
          String str = ae.getActionCommand();
          if(str.equals("OK"))
               run();
               //loginframe.setDefaultCloseOperation(DISPOSE_ON_CLOSE);
}

hi, thanks for ur reply.
i visited that url, i was able to know much about xml.
so now my requirement is DOM.
but i dont know how to code in my existing file.
means i want to know what to link all my textfield to xml file.
can u please help me out. i am confused.
waiting for ur reply

How to parse xml (kXML)

I have some problems when I try to parse xml with the kXML parser. My xml doc looks like this:
<?xml version="1.0" encoding="utf-8" ?>
- <dsGreenRoom>
- <Rooms>
- <RoomsInfo>
<ID>1</ID>
<Name>Rum 101</Name>
<Type>Dubbelrum</Type>
<NumberOfBeds>2</NumberOfBeds>
<Rate>980,00</Rate>
<Currency>SEK</Currency>
<Description>Ett genomtrevligt rum</Description>
</RoomsInfo>
- <RoomsInfo>
<ID>2</ID>
<Name>Mellanrummet</Name>
<Type>Enkelrum</Type>
<NumberOfBeds>1</NumberOfBeds>
<Rate>650,00</Rate>
<Currency>SEK</Currency>
<Description>Ett litet tr?ngt rum i mitten</Description>
</RoomsInfo>
- <RoomsInfo>
<ID>3</ID>
<Name>Rum 102</Name>
<Type>Flerb?ddsrum</Type>
<NumberOfBeds>3</NumberOfBeds>
<Rate>1250,00</Rate>
<Currency>SEK</Currency>
<Description>Ett ?nnu trevligare rum</Description>
</RoomsInfo>
</Rooms>
</dsGreenRoom>
And my code looks like this:
KXmlParser parser = new KXmlParser();
 parser.setInput(is, null);
 Document doc = new Document();
 doc.parse(parser);
 int child_count = root.getChildCount();
 System.out.println("child = " + child_count + "\n");
 for (int i=0; i < child_count; i++) {
 if (root.getType(i) == Node.ELEMENT) {
 Element kid = root.getElement(i);
 System.out.println("kid = " + kid.getName());
 int babies = kid.getChildCount();
 System.out.println("babies = " + babies);
 for (int j=0; j < babies; j++) {
 if (kid.getType(j) == Node.ELEMENT) {
 Element room = kid.getElement(j);
 System.out.println("room.getType() = " + room.getType(j));
 if (room.getName().equals("ID")) {
 System.out.println("elName.getName() = " + room.getName());
 System.out.println("elName.geText() = " + room.getText(j));
 else if (room.getName().equals("Name")) {
 System.out.println("elName.getName() = " + room.getName());
 System.out.println("elName.geText() = " + room.getText(j));
 } // end for(int j...)
 } // end if (root.getType(i)
 } //for (int i...)
The problem is that I don't know how to get the values out of the tags:
<ID>1</ID>
<Name>Rum 101</Name>
<Type>Dubbelrum</Type>
<NumberOfBeds>2</NumberOfBeds>
<Rate>980,00</Rate>
<Currency>SEK</Currency>
<Description>Ett genomtrevligt rum</Description>
It's no problem to get the value from the firsts i.e. <ID> but I don't know how to get the value from <Name> ... <Description>. I have looked att examples but I don't understand how to do this. Can someone please help me =)

okay, sorry, I only read the half of your problem ;-)
You can read the content using the getText(0) method. the 0 indicates the number of the children which you want to get. That is always a 0 because you have always just one text-children in your text-tags. The content is again a children of type text!
hth
Kay

How to parse XML for internal table

hi guys, I would like to know how to parse xml for an internal table. I explain myself.
Let's say you have a purchase order form where you have header data & items data. In my interactive form, the user can change the purchase order quantity at the item level. When I received back the pdf completed by mail, I need to parse the xml and get the po qty that has been entered.
This is how I do to get header data from my form
lr_ixml_node = lr_ixml_document->find_from_name( name = ''EBELN ).
lv_ebeln = lr_ixml_node->get_value( ).
How do we do to get the table body??
Should I used the same method (find_from_name) and passing the depth parameter inside a do/enddo?
thanks
Alexandre Giguere

Alexandre,
Here is an example. Suppose your internal table is called 'ITEMS'.
lr_node = lr_document->find_from_name('ITEMS').
lv_num_of_children = lr_node->num_children( ).
lr_nodechild = lr_node->get_first_child( ).
do lv_num_of_children times.
    lv_num_of_attributes = lr_nodechild->num_children( ).
    lr_childchild = lr_nodechild->get_first_child( ).
   do lv_num_of_attributes times.
      lv_value = lr_childchild->get_value( ).
      case sy-index.
         when 1.
           wa_item-field1 = lv_value
         when 2.
           wa_item-field2 = lv_value.
      endcase.
      lr_childchild = lr_childchild->get_next( ).
   enddo.
   append wa_item to lt_item.
   lr_nodechild = lr_nodechild->get_next( ).
enddo.

How to parse XML against XSD,DTD, etc.. locally (no internet connection) ?

i've searched on how to parse xml against xsd,dtd,etc.. without the needs of internet connection..
but unfortunately, only the xsd file can be set locally and still there needs the internet connection for the other features, properties.
XML: GML file input from gui
XSD: input from gui
javax.xml
package demo;
import java.io.File;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;
import javax.xml.XMLConstants;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
import org.xml.sax.SAXException;
public class Sample1WithJavaxXML {
 public static void main(String[] args) {
 URL schemaFile = null;
 try {
 //schemaFile = new URL("http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd");
 File file0 = new File("AppSchema-C01-v1_0.xsd");
 schemaFile = new URL(file0.toURI().toString());
 } catch (MalformedURLException e1) {
 // TODO Auto-generated catch block
 e1.printStackTrace();
 //Source xmlFile = new StreamSource(new File("web.xml"));
 Source xmlFile = new StreamSource(new File("C01.xml"));
 SchemaFactory schemaFactory = SchemaFactory
 .newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
 //File file1 = new File("XMLSchema.dtd");
 //SchemaFactory schemaFactory = SchemaFactory
 //.newInstance("javax.xml.validation.SchemaFactory:XMLSchema.dtd");
 Schema schema = null;
 try {
 schema = schemaFactory.newSchema(schemaFile);
 } catch (SAXException e1) {
 // TODO Auto-generated catch block
 e1.printStackTrace();
 Validator validator = schema.newValidator();
 try {
 validator.validate(xmlFile);
 System.out.println(xmlFile.getSystemId() + " is valid");
 } catch (SAXException e) {
 System.out.println(xmlFile.getSystemId() + " is NOT valid");
 System.out.println("Reason: " + e.getLocalizedMessage());
 } catch (IOException e) {
 // TODO Auto-generated catch block
 e.printStackTrace();
}Xerces
package demo;
import java.io.File;
import java.util.Date;
import org.apache.xerces.parsers.DOMParser;
public class SchemaTest {
 private String xmlFile = "";
 private String xsdFile = "";
 public SchemaTest(String xmlFile, String xsdFile) {
 this.xmlFile = xmlFile;
 this.xsdFile = xsdFile;
 public static void main (String args[]) {
 File file0 = new File("AppSchema-C01-v1_0.xsd");
 String xsd = file0.toURI().toString();
 SchemaTest testXml = new SchemaTest("C01.xml",xsd);
 testXml.process();
 public void process() {
 File docFile = new File(xmlFile);
 DOMParser parser = new DOMParser();
 try {
 parser.setFeature("http://xml.org/sax/features/validation", true);
 parser.setFeature("http://apache.org/xml/features/validation/schema", true);
 parser.setProperty("http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation",
 xsdFile);
 ErrorChecker errors = new ErrorChecker();
 parser.setErrorHandler(errors);
 System.out.println(new Date().toString() + " START");
 parser.parse(docFile.toString());
 } catch (Exception e) {
 System.out.print("Problem parsing the file.");
 System.out.println("Error: " + e);
 System.out.println(new Date().toString() + " ERROR");
 return;
 System.out.println(new Date().toString() + " END");
}

Thanks a lot Sir DrClap..
I tried to use and implement the org.w3c.dom.ls.LSResourceResolver Interface which is based on the SAX2 EntityResolver.
please give comments the way I implement it. Here's the code:
LSResourceResolver Implementation
import org.w3c.dom.ls.LSInput;
import org.w3c.dom.ls.LSResourceResolver;
import abc.xml.XsdConstant.Path.DTD;
import abc.xml.XsdConstant.Path.XSD;
public class LSResourceResolverImpl implements LSResourceResolver {
 public LSResourceResolverImpl() {
 * {@inheritDoc}
 @Override
 public LSInput resolveResource(String type, String namespaceURI, String publicId, String systemId, String baseURI) {
 ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
 LSInput input = new LSInputImpl(publicId, systemId, baseURI);
 if ("http://www.w3.org/2001/xml.xsd".equals(systemId)) {
 input.setByteStream(classLoader.getResourceAsStream(XSD.XML));
 } else if (XsdConstant.PUBLIC_ID_XMLSCHEMA.equals(publicId)) {
 input.setByteStream(classLoader.getResourceAsStream(DTD.XML_SCHEMA));
 } else if (XsdConstant.PUBLIC_ID_DATATYPES.equals(publicId)) {
 input.setByteStream(classLoader.getResourceAsStream(DTD.DATATYPES));
 return input;
}I also implement org.w3c.dom.ls.LSInput
import java.io.InputStream;
import java.io.Reader;
import org.w3c.dom.ls.LSInput;
public class LSInputImpl implements LSInput {
 private String publicId;
 private String systemId;
 private String baseURI;
 private InputStream byteStream;
 private String stringData;
 public LSInputImpl(String publicId, String systemId, String baseURI) {
 super();
 this.publicId = publicId;
 this.systemId = systemId;
 this.baseURI = baseURI;
 //getters & setters
}Then, here's the usage/application:
I create XMLChecker class (SchemaFactory implementation is Xerces)
import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import javax.xml.XMLConstants;
import javax.xml.stream.FactoryConfigurationError;
import javax.xml.transform.Source;
import javax.xml.transform.stream.StreamSource;
import javax.xml.validation.Schema;
import javax.xml.validation.SchemaFactory;
import javax.xml.validation.Validator;
import org.xml.sax.ErrorHandler;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import abc.xml.XsdConstant.Path.XSD;
public class XMLChecker {
 private ErrorMessage errorMessage = new ErrorMessage();
 public boolean validate(String filePath){
 final ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
 List<Source> schemas = new ArrayList<Source>();
 schemas.add(new StreamSource(classLoader.getResourceAsStream(XSD.XML_SCHEMA)));
 schemas.add(new StreamSource(classLoader.getResourceAsStream(XSD.XLINKS)));
 schemas.add(new StreamSource(classLoader.getResourceAsStream("abc/xml/AppSchema.xsd")));
 SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
 schemaFactory.setResourceResolver(new LSResourceResolverImpl());
 try {
 Schema schema = schemaFactory.newSchema(schemas.toArray(new Source[schemas.size()]));
 Validator validator = schema.newValidator();
 validator.setErrorHandler(new ErrorHandler() {
 @Override
 public void error(SAXParseException e) throws SAXException {
 errorMessage.setErrorMessage(e.getMessage());
 errorMessage.setLineNumber(e.getLineNumber());
 errorMessage.setColumnNumber(e.getLineNumber());
 throw e;
 @Override
 public void fatalError(SAXParseException e) throws SAXException {
 errorMessage.setErrorMessage(e.getMessage());
 errorMessage.setLineNumber(e.getLineNumber());
 errorMessage.setColumnNumber(e.getLineNumber());
 throw e;
 @Override
 public void warning(SAXParseException e) throws SAXException {
 errorMessage.setErrorMessage(e.getMessage());
 errorMessage.setLineNumber(e.getLineNumber());
 errorMessage.setColumnNumber(e.getLineNumber());
 throw e;
 StreamSource source = new StreamSource(new File(filePath));
 validator.validate(source);
 } catch (SAXParseException e) {
 return false;
 } catch (SAXException e) {
 errorMessage.setErrorMessage(e.getMessage());
 return false;
 } catch (FactoryConfigurationError e) {
 errorMessage.setErrorMessage(e.getMessage());
 return false;
 } catch (IOException e) {
 errorMessage.setErrorMessage(e.getMessage());
 return false;
 return true;
 public ErrorMessage getErrorMessage() {
 return errorMessage;
}Edited by: erossy on Aug 31, 2010 1:56 AM

How to specify a parser? xml newbie

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