How to store data when it is dynamically generated

Hi,
I am designing a page in that dates get auto populated based on the selection of two dates.
if start date = 1-Jan-2011 and end date = 4-Jan-2011.
4 columns get generated based on the dates selected. columns like 1-Jan-2011, 2-Jan-2011. 3-Jan-2011, 4-Jan-2011. these are the columns generated. If dates are changed again dates will populated based on the start and end date.
Below these dates 3 rows are generated
Columns 1-jan-2011 2-jan-2011 3-jan-2011 4-jan-2011
rows null null null null
How can i store these data please suggest me
Thanks
Sudhir

Sudhir, Pls enclose your code within <b>{code}</b> tags, this makes it readable.
Some observations:
<li>1. SELECT ROWNUM,
..FROM STUDY S, COHART C WHERE S.ID = C.S_ID ORDER BY S.NAME would lead to errors since the rownum would be fetched before ordering and hence your rows will not be correct row number sequence.
Due to this f01(1) might fetch the 4th row's column instead of the first as u have wanted it.One method to avoid this, is by
SELECT ROWNUM,A.*
..FROM (SELECT * FROM STUDY S, COHART C WHERE S.ID = C.S_ID ORDER BY S.NAME ) A<li>2. I don't see any primary column which would used to identify the row in the DB
<li>3. The difference between 2 dates need not always be a perfect integer, So i hope u have kept this in mind while writing the code.
<li>Now to your question of accessing the dates for selected rows.(fix the issues mentioned above first)
Iterating over the F01 array(using i)
APEX_APPLICATION.G_f01(i) would contain the rownum of each checked row.
As per your code you can have multiple date columns in the same row with the array index(4)
I am not sure how to obtain the number of dynamic date columns in every row.
Anyway while processing u would have to do this calculation and suppose the variable l_no_of_days has this value.
So ur j'th date column(u can have j=1..l_no_of_days) for the i'th row can be obtained as
APEX_APPLICATION.G_f01(i) = actual row number
APEXAPPLICATION.G_f01(i) -1 )*l_no_of_days + j = column index of j'th column for this row_
APEX_APPLICATION.G_f04(APEX_APPLICATION.G_f01(i) -1 )*l_no_of_days + j) would have the date column value
As an example
<1> texxt <1> <2> <3> <4>..
<2> texxt <5> <6> <7> <8>..
<3> texxt <9> <10> <11> <12>..
<4> texxt <> <> <> <>..
<5> texxt <17> <18> <19> <20>..
In this case,l_no_of_days would be obtained as 4
If 2 and 4 was checked, i =1..2
f01(1) = 2
1st checked row's, 1st dynamic column = f04( (2 -1)*4 + 1 ) = f04(5)
1st checked row's, 3st dynamic column = f04( (2 -1)*4 + 3 ) = f04(7)
2nd checked row's 5th column = f04( (5 -1)*4 + 5 ) = f04(24)
Phew !!, feels like college mathematics ;) .
Hope it was clear.

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