How to sum value from a day to next day

Question

First, I provided the CREATE and INSERT sql statements for testing:
CREATE TABLE TBL_CALC
    "YEAR"  VARCHAR2(4),
    "MONTH" VARCHAR2(2),
    "DAY"   VARCHAR2(2),
    "HOUR"  VARCHAR2(2),
    "VALUE" VARCHAR2(20)
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','20','32')
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','21','33');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','22','53');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','1','23','28');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','0','37');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','1','35');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','2','39');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','3','57');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','13','42');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','2','14','12');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','21','32');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','22','52');
insert into tbl_calc (year,month,day,hour,value) values ('2000','1','31','23','29');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','0','27');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','1','45');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','2','69');
insert into tbl_calc (year,month,day,hour,value) values ('2000','2','1','3','68');I have this sql to get the period of time of a day:
         select year,month,day,hr,val,
                 sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by year,month,day) as new_value
                      from(
                             select year,month,day,to_number(hour) hr,to_number(value) val from tbl_calc
         order by year,month,day,hrHere's the output:
YEAR MONTH DAY HR VAL NEW_VALUE
2000 1     1   20  32       146
2000 1     1   21  33       146
2000 1     1   22  53       146
2000 1     1   23  28       146
2000 1     2    0  37       168
2000 1     2    1  35       168
2000 1     2    2  39       168
2000 1     2    3  57       168
2000 1     2   13  42       168
2000 1     2   14  12       168
2000 1     31  21  32       113
2000 1     31  22  52       113
2000 1     31  23  29       113
2000 2     1    0  27       209
2000 2     1    1  45       209
2000 2     1    2  69       209
2000 2     1    3  68       209
17 rows selected The above sql get the sum of time period which in 20-23 and 0-3 in every day.
The values are recorded by each hour. (sometimes there are missed hours)
My problem is how to get the sum of time period over each day?
For example, I need to get the sum of value of a day night time from 20-23 and the next day morning 0-3, to become a sum value in this period.
Let say, the sum from 1st Jan night time to 2nd Jan morning should be combined into 1 value (146+168)=314.
In addition, there is a tricky point is that from every month last day (31th Jan night time to 1st Feb morning time) are also need to be combined into 1 value.
And it appears the new problem is that how about if the last day is in a non-regular day (not 30,31,28,29), just say maybe March consist only 15 period records only and the last day is 19th March.
The expected output:
YEAR MONTH DAY HR VAL NEW_VALUE
2000 1     1   20  32       314
2000 1     1   21  33       314
2000 1     1   22  53       314
2000 1     1   23  28       314
2000 1     2    0  37       314
2000 1     2    1  35       314
2000 1     2    2  39       314
2000 1     2    3  57       314
2000 1     2   13  42       314
2000 1     2   14  12       314
2000 1     31  21  32       322
2000 1     31  22  52       322
2000 1     31  23  29       322
2000 2     1    0  27       322
2000 2     1    1  45       322
2000 2     1    2  69       322
2000 2     1    3  68       322
17 rows selected I think its quite complicated case, please ask me for more if you need to clarify for something.
Thanks so much!! :)
Edited by: 920575 on 2012/7/31 上午 1:09

Answer 1

Are you looking for something like this (partially tested)...
SQL> ed
Wrote file afiedt.buf
  1  select year
  2        ,month
  3        ,day
  4        ,hr
  5        ,val
  6        ,sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by year,month,day) as new_value
  7        ,sum(case when hr between 20 and 23 or hr between 0 and 3 then val else 0 end) over (partition by trunc(dt-(4/24),'DD')) as day_value
  8  from(
  9       select year,month,day,to_number(hour) hr,to_number(value) val
10             ,to_date(year||lpad(month,2,'0')||lpad(day,2,'0')||lpad(hour,2,'0')||'0000','YYYYMMDDHH24MISS') as dt
11       from tbl_calc
12      )
13* order by year,month,day,hr
SQL> /
YEAR MO DA         HR        VAL  NEW_VALUE  DAY_VALUE
2000 1  1          20         32        146        314
2000 1  1          21         33        146        314
2000 1  1          22         53        146        314
2000 1  1          23         28        146        314
2000 1  2           0         37        168        314
2000 1  2           1         35        168        314
2000 1  2           2         39        168        314
2000 1  2           3         57        168        314
2000 1  2          13         42        168          0
2000 1  2          14         12        168          0
2000 1  31         21         32        113        322
2000 1  31         22         52        113        322
2000 1  31         23         29        113        322
2000 2  1           0         27        209        322
2000 2  1           1         45        209        322
2000 2  1           2         69        209        322
2000 2  1           3         68        209        322
17 rows selected.This turns the values into a proper DATE datatype and then offsets that back by 4 hours to bring the 0-3 hours into the previous day, and then partitions the sum based on that day.