How to switch two buttons at same place?

Question

Hi everyone,
I'm changing the GUI of my project. The following is a test program. It want to switch jButton2 and jButton3 at same place when you click jButton1. But it cannot display jButton3. What's problem? Who can help me?
Thank you very much.
CODE ----------------------------------------------
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class Test extends JFrame {
JPanel jPanel1 = new JPanel();
JButton jButton1 = new JButton();
JButton jButton2 = new JButton();
BorderLayout borderLayout1 = new BorderLayout();
JButton jButton3 = new JButton();
public Test() {
try {
jbInit();
catch(Exception e) {
e.printStackTrace();
private void jbInit() throws Exception {
jButton1.setText("jButton1");
jButton1.addActionListener(new Test_jButton1_actionAdapter(this));
jButton2.setText("jButton2");
jPanel1.setLayout(borderLayout1);
jButton3.setText("jButton3");
jPanel1.add(jButton1, BorderLayout.NORTH);
jPanel1.add(jButton3, BorderLayout.CENTER);
jPanel1.add(jButton2, BorderLayout.CENTER);
getContentPane().add(jPanel1);
protected void processWindowEvent(WindowEvent e) {
super.processWindowEvent(e);
if (e.getID() == WindowEvent.WINDOW_CLOSING) {
System.exit(0);
public static void main(String[] args)
Test t = new Test();
t.setSize(100,100);
t.show();
void jButton1_actionPerformed(ActionEvent e) {
if (jButton2.isVisible())
jButton2.setVisible(false);
jButton3.setVisible(true);
else
jButton3.setVisible(false);
jButton2.setVisible(true);
class Test_jButton1_actionAdapter implements java.awt.event.ActionListener {
Test adaptee;
Test_jButton1_actionAdapter(Test adaptee) {
this.adaptee = adaptee;
public void actionPerformed(ActionEvent e) {
adaptee.jButton1_actionPerformed(e);
}

Answer 1

Try this:
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class Test extends JFrame {
JPanel jPanel1 = new JPanel();
JButton jButton1 = new JButton();
JButton jButton2 = new JButton();
BorderLayout borderLayout1 = new BorderLayout();
public Test() {
try {
jbInit();
catch(Exception e) {
e.printStackTrace();
private void jbInit() throws Exception {
jButton1.setText("jButton1");
jButton1.addActionListener(new Test_jButton1_actionAdapter(this));
jButton2.setText("jButton2");
jPanel1.setLayout(borderLayout1);
jPanel1.add(jButton1, BorderLayout.NORTH);
jPanel1.add(jButton2, BorderLayout.CENTER);
getContentPane().add(jPanel1);
protected void processWindowEvent(WindowEvent e) {
super.processWindowEvent(e);
if (e.getID() == WindowEvent.WINDOW_CLOSING) {
System.exit(0);
public static void main(String[] args)
Test t = new Test();
t.setSize(100,100);
t.show();
void jButton1_actionPerformed(ActionEvent e) {
if (jButton2.getText().equals("jButton2")) jButton2.setText("jButton3"); else jButton2.setText("jButton2");
class Test_jButton1_actionAdapter implements java.awt.event.ActionListener {
Test adaptee;
Test_jButton1_actionAdapter(Test adaptee) {
this.adaptee = adaptee;
public void actionPerformed(ActionEvent e) {
adaptee.jButton1_actionPerformed(e);
The idea is to change the appearance of a single button instead of dealing with two separate buttons. If you want the second button to perform different task, you can use the getText() method and check to see whether is says jButton2 or jButton3.
;o)
V.V.
PS: If this helps, don't for get the Dukes.