How to truncate xml element to 10 characters

Hello frenz,
I've an xml element like description which is too long... I want to truncate it to some 10 characters.... please let me know how

You can use substring function to get the 10 characters like this: <?substring(element_name,1,10)?>
replace element_name with your xml element.
Thanks!

Similar Messages

How to access XML elements by name in Extendscript??

I'm almost done the script that I've been working on, but something has been nagging me since I started. When I did start, I looked at the JS Tools Guide CS5 that comes with the extendscript ide to check how to access XML elements, children, attributes etc. It says this:
The XML object represents an XML element node in an XML tree. The topmost XML object for an XML file
represents the root node. It acts as a list, which contains additional XML objects for each element. These in
turn contain XML objects for their own member elements, and so on.
The child elements of an element tree are available as properties of the XML object for the parent. The
name of the property corresponds to the name of the element. Each property contains an array of XML
objects, each of which represents one element of the named type.
So basically it converts the XML into JSON. And you can access the properties like so:
<book category="COOKING">
     <title lang="en">The Boston Cooking-School Cookbook</title>
     <author>Fannie Merrit Farmer</author>
     <year>1896</year>
     <price>49.99</price>
</book>
The Javascript statement bookstoreXML.book; returns the entire list of books.
The statement bookstoreXML.book[0]; returns the XML object for the first book.
The statement bookstoreXML.book[0].author; returns all authors of the first book.
A couple pages down it talks about Retrieving contained elements using children(), elements(), descendants().
So now I look through the XML Object properties and I see that I can use:
xmlObj.child (which) which A String, the element name, or a Number, a 0-based index into this node’s child array.
or
xmlObj.descendants ([name])
name Optional. A String, the element name to match. If not provided, matches all
elements.
or
xmlObj.elements (name);
name Optional. A String, the element name to match. If not provided, matches all
elements.
This is an excerpt of an XML I was working with:
<ROW xmlns="http://www.filemaker.com/fmpdsoresult"
     MODID="16"
     RECORDID="11128">
   <Sign_Type>251.dr</Sign_Type>
   <fm:Location xmlns:fm="http://www.filemaker.com/fmpdsoresult" xmlns="">5-5024</fm:Location>
   <Line1>Zone
Floor
3
Patient Rooms
R532 - R436 even
Patient Rooms
R522 - R446 even
Xavier Elevators
Zone
Patient Rooms
R537 - 5757 odd
Main Elevators
Zone</Line1>
</ROW>
Extendscript will not give me an anything when I try to access elements by name. Instead I have to access by index, which works, but I'd rather search for names!
Actually the console log returns: <![CDATA[]]>
What am I doing wrong!?

First, those E4X XML objects are definitely no JSON (plain data) - they have a multitude of methods, even for tasks that would easily be implemented as property (e.g. the length() function), and they also bind xml element and attribute names onto the objects, allowing to target a multitude of XML nodes with a single statement. Or did you mean your script with that "it"?
Anyway, as you found out the ExtendScript XML object handles namespaces mostly by hiding them from you.
You could play around with global namespace settings, see the JavaScript tools guide.
You could also explicitly specify a namespace. This works for me:
$.writeln(myXML["fm:Location"]);
For simple use I had most success with a brute force approach that just strips the namespaces.
function removeAllNamespace(xml)
          var ns =new Namespace();
          var d=xml.descendants();
          for (var i=0;i<d.length();i++)
    d[i].setNamespace(ns);

How to separate XML element content

Hi All,
How can i separate XML element content in to two strings, where each string will be copied into new variables.
For ex:
The input I get is
<XmLElement>C:/documents/sharedFiles/apple.pdf</XMLElement>
now I want to break the content into two parts like
<aaaa>C:/documents/sharedFiles/</aaaaa>
<bbbbb>apple.pdf</bbbbbb> ( I want to separate file name from the string)
and now I want to copy this into two other variables. How can I achieve this in BPEL. Appreciate your help.
Thanks,
Edited by: kameshb on Mar 25, 2013 11:16 AM

I am getting the following error
<bpelFault><faultType>0</faultType><subLanguageExecutionFault xmlns="http://schemas.oracle.com/bpel/extension"><part name="summary"><summary>XPath expression failed to execute. An error occurs while processing the XPath expression; the expression is substring(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),1, oraext:last-index-within-string(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),'/') -1) . The XPath expression failed to execute; the reason was: internal xpath error. Check the detailed root cause described in the exception message text and verify that the XPath query is correct. </summary></part><part name="code"><code>XPathExecutionError</code></part></subLanguageExecutionFault></bpelFault>
This is the code inside XPATH
<assign name="BreakURL">
<copy>
<from expression="substring(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),1, oraext:last-index-within-string(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),'/') -1) "/>
<to variable="outputVariable" part="payload"
query="/ns1:Toutput/ns1:Location"/>
</copy>
<copy>
<from expression="substring(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),1, oraext:last-index-within-string(bpws:getVariableData('inputVariable','payload','/ns1:Tinput/ns1:URL'),'/'),) "/>
<to variable="outputVariable" part="payload"
query="/ns1:Toutput/ns1:Filename"/>
</copy>
</assign>

[AS][CS4] How to get XML element of grep find result?

Hi,
Does anyone know how to get the xml element of a grep find result?
I have multiple text frames, each containing multiple paragraphs. Each paragraph can contain one or more different xml tagged pieces of text.
Using a simple search function I can locate the text I need, but how do I retreive the xml element applied to that piece of text.
Using the "associated XML element" property, it doesn't work.
set find what of find grep preferences to "€( )*(\\d)*"
tell active document
          set myResult to find grep
          set myItem to item 1 of myResult
          set myElement to associated XML element of myItem
          -- The last line throws an error
end tell
The find result will return a collection of text objects.
Thanks
John

Well I found this post that answered my question
http://forums.ni.com/t5/LabVIEW/how-to-get-recordset-from-database/m-p/1471374?requireLogin=False

How to create XML element with out creating a document

I ve been looking for hours for a method to create an XML element without the need for the Document. I am trying to create objects that access the database, and I need in each of these objects a method that returns only an element (ie. getXMLData()). And in the class that created these object, I nee to call the getXML() methods and construct a document. However, I am not looking to create the document if I am not going to use it. In the component class I need to be able to traverse the xml element and read and modify the values. Is there a way to do so with sun's JDK ?

I ve been looking for hours for a method to create an
XML element without the need for the Document.
... I am not looking to create the document if I
am not going to use it.Hi M-A,
Though you have been told the solution, let's stick to your original issue, just for the sake of interest. I gather what you have in mind is finding the answer to the following question: is there a way of creating a document without having to bind it to any data source? The answer is yes. What you might need is the createDocument() method of the DOMImplementation interface which offers lightwight document handling by obviating the need to construct a particular DOM instance. (You could also use the getDOMImplementation() method of the DOMImplementationRegistry interface, but it has bugs.) Here's a sample code:DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder parser = factory.newDocumentBuilder();
DOMImplementation domImpl = parser.getDOMImplementation();
Document doc = domImpl.createDocument(null, "rootnode", null);The above code produces the following document:<?xml version="1.0" encoding="UTF-8"?>
<rootnode/>You can make this document even skinnier if you pass null values to all three parameters of the createDocument() method, in which case the document will only contain the prolog. I think both the creation and the structure of this document are simple enough for you to use it as some sort of utility (e.g. by putting the code in a separate class) for creating elements.

How to make XML element used in RTF PRIVATE/PUBLIC ? I know how to hide columns in RTF, but dont know how to generate the xml in below way. Please help.

Hi
I am following below link to hide/show my columns dynamically. See "Column Formatting"
http://docs.oracle.com/cd/E12844_01/doc/bip.1013/e12187.pdf
As per doc, element can be made private/public.
<items type="PUBLIC">
<item>
<name>Plasma TV</name>
<quantity>10</quantity>
<price>4000</price>
</item>
<item>
And same can be used to hide the column using condition
<?if@column:/items/@type="PUBLIC"?>
MY QUESTION IS HOW TO DO THIS IN MY XML BELOW?
Below is part of my XML code which I am using in Data Definition for RTF.
<group name="GH3" source="QH3">
<element name="COLUMN_HEAD3" value="COLUMN_NAME" />
</group>
<group name="GH4" source="QH4">
<element name="COLUMN_HEAD4" value="COLUMN_NAME" />
</group>
I am getting output like this.
<LIST_GH3>
<GH3>
<COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
</GH3>
</LIST_GH3>
<LIST_GH4>
<GH4>
<COLUMN_HEAD4>XYZ</COLUMN_HEAD4>
</GH4>
</LIST_GH4>
In order to use logic as per oracle document I want output like this.
<LIST_GH3 type="PUBLIC">
<GH3>
<COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
</GH3>
</LIST_GH3>
<LIST_GH4 type="PRIVATE">
<GH4>
<COLUMN_HEAD4>BLANK</COLUMN_HEAD4>
</GH4>
</LIST_GH4>
What changes I need to make in my XML code to get the runtime output as above? Please help. Where do i need to make changes in the above xml? Group name? Element name?
I am planning to use below condition in RTF template to hide the column, but dont know how to set the type of column as PRIVATE/PUBLIC in the XML output used to populate data in the RTF at runtime.
<?if@column:/BTSPIEXP/LIST_GH3/@type=”PUBLIC”?>COLUMN_HEAD3<?end if?>
Regards,
Swapnil K.

Hi,
Issue has been resolved. I used the value of the element to determine to display it or not.
Regards,
Swapnil K.

How to read xml elements in Bpel

Hi,
I had created an empty Bpel Process and configured file adapter to a directory, In my text file i have 3 records with four columns, each column seperated by ',' and each record seperated by "EOL(end of line)", Below is the xsd file generated by the native format xsd builder, taken a recieve activity to recieve the contents of file from file adapter.
So all the data which is in the file will be there in recieve activity.
FileContents
55555,rgfdgsd,gfdgfdg,23
66666,retretret,trtertg,21
77777,rtrttreter,trtter,23
My Question is
I want to compare whether value of C1 = '55555' and if the value is equal to 55555 then that record with c1=55555 has to be inserted into database
How to compare the value of c1 through bpel functions.
with java i have to use the logic similar to this by using Xpath
getElement by tagname(c1);- it will give all the elements with tagname c1, three records are there with tagname c1 (c1=55555,c1=66666,c1=77777), we have to iterate through the elemnts and check whether the value iof c1='55555' and get the whole parent block which contains values of c1,c2,c3,c4 and insert that to database
What variables we have to use to get the Similar logic in bpel
<?xml version="1.0" encoding="UTF-8" ?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:nxsd="http://xmlns.oracle.com/pcbpel/nxsd"
targetNamespace="http://TargetNamespace.com/FileAdapter"
xmlns:tns="http://TargetNamespace.com/FileAdapter"
elementFormDefault="qualified"
attributeFormDefault="unqualified" nxsd:encoding="ASCII" nxsd:stream="chars" nxsd:version="NXSD">
<xsd:element name="Associates">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="Associate" minOccurs="1" maxOccurs="unbounded">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="C1" type="xsd:double" nxsd:style="terminated" nxsd:terminatedBy="," nxsd:quotedBy=""">
</xsd:element>
<xsd:element name="C2" type="xsd:string" nxsd:style="terminated" nxsd:terminatedBy="," nxsd:quotedBy=""">
</xsd:element>
<xsd:element name="C3" type="xsd:string" nxsd:style="terminated" nxsd:terminatedBy="," nxsd:quotedBy=""">
</xsd:element>
<xsd:element name="C4" type="xsd:double" nxsd:style="terminated" nxsd:terminatedBy="${eol}" nxsd:quotedBy=""">
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
Please Look into this and suggest me the solution.
Regards

Hello,
Create a transform between the out variable of you receive activity and in variable of your db adatpter.
The use an IF in you tranformation file.
Sample code
<xsl:template match="/">
<ns0:TestRahulCollection>
<xsl:for-each select="/tns:Root-Element/tns:element">
*<xsl:if test="xp20:matches(tns:C1,'55555')">*
<ns0:TestRahul>
<ns0:a1>
<xsl:value-of select="tns:C1"/>
</ns0:a1>
<ns0:a2>
<xsl:value-of select="tns:C2"/>
</ns0:a2>
<ns0:a3>
<xsl:value-of select="tns:C3"/>
</ns0:a3>
<ns0:a4>
<xsl:value-of select="tns:C4"/>
</ns0:a4>
</ns0:TestRahul>
</xsl:if>
</xsl:for-each>
</ns0:TestRahulCollection>
</xsl:template>
Thanks
Rahul

How to iterate xml elements using PL/SQL

Hello,
Let's say I have the following xml:
<A>
<B name="b1">
</B>
<B name="b2">
</B>
</A>
I would like to iterate over the B and sub-B elements using PL/SQL?
Any help will be appreciated.

Hi,
You can use 'PL/SQL DOM API for XMLType (DBMS_XMLDOM)'
to work with XML. You can check the example present at
http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96620/xdb08pls.htm#1041419
to check how it does.
The API for the package DBMS_XMLDOM is given on the same page(http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96620/xdb08pls.htm#1040676)
You can use them for your requirement.
Regards,
Anupama

How to get xml Element , data and its Childs

hi,
I am trying to get entire Element and its childs depending on condition.
suppose
   if(doc.element.name== "despatch"){
               // here i want entire despatch element with data and childs and copy into one string like
               // eg: String dsp = <despatch><name>body1</name> <value>value1<value>
</despatch>
<?xml version="1.0">
<handler>
     <name>header1</name>
     <value>value1</value>
</handler>
<despatch>
     <name>body1</name>
     <value>value1<value>
</despatch>
<gov>
     <name>env</name>
     <value>value1</value>
</gov>I managed to get number of elements depending on the Element name but i need to get the entire block.
nodeList = document.getElementsByTagName("despatch").item(0).getChildNodes();
                    for(int i=0;i<nodeList.getLength();i++){
                         System.out.println("i :"+document.getElementsByTagName("m:Security").item(i));
                    }any kind of help is appreciated.
Han.
Edited by: HANRAM on Apr 24, 2008 2:48 AM

Hi Kartik,
This one is similar to my question to print and email invoice at same time. I pass itcpo-tdgetotf = 'X' in order to get otfdata and send email with the attachment of otfdata.
Now I have data in otfdata, but when I call print_otf function, I clear out itcpo-tdgetotf, and passed
itcpo-tddest = device_type but I still get error message said 'Handler not valid for open spool request'.
Can you give me a working example that you have otfdata table and print data from that table. I also post my question on other thread
submit report and export to memory
thanks

How to replace XML elements using java

I have been usint SAX 2.0 and DOM Level 2 api's to represent XML documents, which i parse with apache's Xerces parser... I am trying to delete certain elements and replace them with others, but none of the api's allow this the closes i have come is replacing attributes of elements....

Answered in crosspost.
http://forum.java.sun.com/thread.jspa?threadID=638156

SAX, incor. data for XML element, XML 1.1 doc (1.0 ok) in JRE 6 (JRE 5 ok)

Hello,
for some reason, the test case below fails when driven with Java 6. Looks like, when long string data is stored in a XML element, DocumentHandler's characters() method will be provided with incorrect data.
With XML 1.0, parsing works fine in all my tests, Apache Xerces, JRE 5, JRE 6.
With XML 1.1., parsing works fine with Apache Xerces, JRE5 but not with JRE6.
I've checked it with latest JRE 6 update 4.
Anyone else xperiencing such problems with XML1.1 parsing when using JAXP bundled with Java 6?
I've tried to file a bug at bugdatabase, but for some reason I got no response for my issue - so I'm trying the forum now ;-)
Thanx for comments
Merten
import java.io.StringReader;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
import junit.framework.TestCase;
import junit.framework.TestResult;
import junit.framework.TestSuite;
/** snippet to demonstrate problem in SAXParser */
public class ProblemWithSAXParser extends TestCase
public static void main(String[] args)
TestResult result=junit.textui.TestRunner.run(suite());
System.exit(result.wasSuccessful() ? 0 : 1);
private static junit.framework.Test suite()
final TestSuite ts=new TestSuite();
ts.addTestSuite(ProblemWithSAXParser.class);
return (ts);
/** small DocumentHandler, just waiting for one and only XML element <c></c> */
class MySAXDocumentHandler extends DefaultHandler
boolean listening=false;
public void startElement(final String uri, final String localName, final String qName, final Attributes attributes)
throws SAXException
System.out.println("startElement uri " + uri + " localName " + localName + " qName " + qName);
if("c".equals(qName))
listening=true;
public void endElement(final String uri, final String localName, final String qName) throws SAXException
System.out.println("endElement uri " + uri + " localName " + localName + " qName " + qName);
if("c".equals(qName))
listening=false;
public void characters(final char ch[], final int start, final int length) throws SAXException
if(listening)
final String str=new String(ch, start, length);
System.out.println("<c> element, start==" + start + " length==" + length + " ch.length==" + ch.length + " ch=="
+ str);
sb.append(str);
private final StringBuffer sb=new StringBuffer();
/** return what I got for XML element <c></c> */
public String toString()
return (sb.toString());
/** test an XML document with an element <c>, use XML 1.0 and XML 1.1 and some (more)
* content in the XML element */
public void testWithSunAndApache() throws Exception
// test XML element content for <c> element
final StringBuffer plain_str=new StringBuffer("");
for(int i=0; i < 500; i++)
plain_str.append("0123456789 This is some text ").append(i).append(". ");
final String xml_orig=plain_str.toString();
// SAX parsers, one Sun, one (original) Apache Xerces
// accept that Apache Xerces is not in path ...
final String prop_name="javax.xml.parsers.SAXParserFactory";
final String prop_val_sun="com.sun.org.apache.xerces.internal.jaxp.SAXParserFactoryImpl";
final String prop_val_apache="org.apache.xerces.jaxp.SAXParserFactoryImpl";
System.setProperty(prop_name, prop_val_sun);
final SAXParser sax_sun=SAXParserFactory.newInstance().newSAXParser();
System.out.println("SaxParser Sun= " + sax_sun);
assertTrue(("" + sax_sun).indexOf("com.sun.") >= 0);
System.setProperty(prop_name, prop_val_apache);
SAXParser sax_apache;
try
sax_apache=SAXParserFactory.newInstance().newSAXParser();
catch(final Throwable t)
System.err.println("no Apache Xerces in path? " + t);
sax_apache=null;
System.out.println("SaxParser Apache= " + sax_apache);
assertTrue(sax_apache==null || ("" + sax_apache).startsWith("org.apache."));
// i==0: XML 1.0, i==1: XML 1.1
for(int i=0; i <= 1; i++)
assert i == 0 || i == 1;
final String xml_version=(i == 0 ? "1.0" : "1.1");
final StringBuffer sb=new StringBuffer("<?xml version=\"" + xml_version + "\" encoding=\"UTF-8\"?><c>");
sb.append(xml_orig);
sb.append("</c>");
final String xml=sb.toString();
// parse it!
final StringReader string_reader_sun, string_reader_apache;
string_reader_sun=new StringReader(xml);
final InputSource input_source_sun=new InputSource(string_reader_sun);
string_reader_apache=new StringReader(xml);
final InputSource input_source_apache=new InputSource(string_reader_apache);
final MySAXDocumentHandler my_handler_sun, my_handler_apache;
my_handler_sun=new MySAXDocumentHandler();
my_handler_apache=new MySAXDocumentHandler();
sax_sun.parse(input_source_sun, my_handler_sun);
if(sax_apache!=null)
sax_apache.parse(input_source_apache, my_handler_apache);
final String xml_sun=my_handler_sun.toString();
final String xml_apache=my_handler_apache.toString();
assertNotNull(xml_sun);
assertNotNull(xml_apache);
System.out.println("xml version " + xml_version);
System.out.println("xml " + xml);
System.out.println("xml_orig " + xml_orig);
System.out.println("xml_sun " + xml_sun);
System.out.println("xml_apache " + xml_apache);
// test the data returned from DocumentHandler
if(sax_apache!=null)
assertEquals(xml_orig, xml_apache);
assertEquals(xml_orig.length(), xml_sun.length()); // length seems to be okay
assertEquals(xml_orig, xml_sun); // content seems to be not okay for XML 1.1
}

thanx, DrClap, haven't seen the "code" button for some reason, code is attached again
The output of my test is like this for JRE6 (truncated)
xml_sun 456789 This is is some text 0. 0123456789 This is some text 1.
xml_apache 0123456789 This is some text 0. 0123456789 This is some text 1.
Notice, xml_sun not only starts wrong ("0123" missing) - for some reason, the text there is not "This is some text" but "This is is some text" - very interesting in a way. I guess there's an issue with repeated text chunks ...
So, the data in my XML element is kind of changed, the length of the string is okay but the characters are "misplaced" or so :-) I thought about a problem with StringBuffer first, but the StringBuffer works fine for Apache ... so I really think there's an issue with JRE 6's parser for XML 1.1
Merten
import java.io.StringReader;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
import junit.framework.TestCase;
import junit.framework.TestResult;
import junit.framework.TestSuite;
/** snippet to demonstrate problem in SAXParser */
public class ProblemWithSAXParser extends TestCase
public static void main(String[] args)
TestResult result=junit.textui.TestRunner.run(suite());
System.exit(result.wasSuccessful() ? 0 : 1);
private static junit.framework.Test suite()
final TestSuite ts=new TestSuite();
ts.addTestSuite(ProblemWithSAXParser.class);
return (ts);
/** small DocumentHandler, just waiting for one and only XML element <c></c> */
class MySAXDocumentHandler extends DefaultHandler
boolean listening=false;
public void startElement(final String uri, final String localName, final String qName, final Attributes attributes)
    throws SAXException
   System.out.println("startElement uri " + uri + " localName " + localName + " qName " + qName);
   if("c".equals(qName))
    listening=true;
public void endElement(final String uri, final String localName, final String qName) throws SAXException
   System.out.println("endElement uri " + uri + " localName " + localName + " qName " + qName);
   if("c".equals(qName))
    listening=false;
public void characters(final char ch[], final int start, final int length) throws SAXException
   if(listening)
    final String str=new String(ch, start, length);
    System.out.println("<c> element, start==" + start + " length==" + length + " ch.length==" + ch.length + " ch=="
      + str);
    sb.append(str);
private final StringBuffer sb=new StringBuffer();
/** return what I got for XML element <c></c> */
public String toString()
   return (sb.toString());
/** test an XML document with an element <c>, use XML 1.0 and XML 1.1 and some (more)
* content in the XML element */
public void testWithSunAndApache() throws Exception
// test XML element content for <c> element
final StringBuffer plain_str=new StringBuffer("");
for(int i=0; i < 500; i++)
   plain_str.append("0123456789 This is some text ").append(i).append(". ");
final String xml_orig=plain_str.toString();
// SAX parsers, one Sun, one (original) Apache Xerces
// accept that Apache Xerces is not in path ...
final String prop_name="javax.xml.parsers.SAXParserFactory";
final String prop_val_sun="com.sun.org.apache.xerces.internal.jaxp.SAXParserFactoryImpl";
final String prop_val_apache="org.apache.xerces.jaxp.SAXParserFactoryImpl";
System.setProperty(prop_name, prop_val_sun);
final SAXParser sax_sun=SAXParserFactory.newInstance().newSAXParser();
System.out.println("SaxParser Sun= " + sax_sun);
assertTrue(("" + sax_sun).indexOf("com.sun.") >= 0);
System.setProperty(prop_name, prop_val_apache);
SAXParser sax_apache;
try
   sax_apache=SAXParserFactory.newInstance().newSAXParser();
catch(final Throwable t)
   System.err.println("no Apache Xerces in path? " + t);
   sax_apache=null;
System.out.println("SaxParser Apache= " + sax_apache);
assertTrue(sax_apache==null || ("" + sax_apache).startsWith("org.apache."));
// i==0: XML 1.0, i==1: XML 1.1
for(int i=0; i <= 1; i++)
   assert i == 0 || i == 1;
   final String xml_version=(i == 0 ? "1.0" : "1.1");
   final StringBuffer sb=new StringBuffer("<?xml version=\"" + xml_version + "\" encoding=\"UTF-8\"?><c>");
   sb.append(xml_orig);
   sb.append("</c>");
   final String xml=sb.toString();
   // parse it!
   final StringReader string_reader_sun, string_reader_apache;
   string_reader_sun=new StringReader(xml);
   final InputSource input_source_sun=new InputSource(string_reader_sun);
   string_reader_apache=new StringReader(xml);
   final InputSource input_source_apache=new InputSource(string_reader_apache);
   final MySAXDocumentHandler my_handler_sun, my_handler_apache;
   my_handler_sun=new MySAXDocumentHandler();
   my_handler_apache=new MySAXDocumentHandler();
   sax_sun.parse(input_source_sun, my_handler_sun);
   if(sax_apache!=null)
    sax_apache.parse(input_source_apache, my_handler_apache);
   final String xml_sun=my_handler_sun.toString();
   final String xml_apache=my_handler_apache.toString();
   assertNotNull(xml_sun);
   assertNotNull(xml_apache);
   System.out.println("xml version " + xml_version);
   System.out.println("xml        " + xml);
   System.out.println("xml_orig   " + xml_orig);
   System.out.println("xml_sun    " + xml_sun);
   System.out.println("xml_apache " + xml_apache);
   // test the data returned from DocumentHandler
   if(sax_apache!=null)
    assertEquals(xml_orig, xml_apache);
   assertEquals(xml_orig.length(), xml_sun.length()); // length seems to be okay
   assertEquals(xml_orig, xml_sun); // content seems to be not okay for XML 1.1
}

Create XML element without closing tag using Visual C++

I know how to create xml element with closing tag (using WriteStartElement and WriteEndElement methods)
<tag id="1234">
</tag>
but is there a way in Visual C++ to produce xml element like this
<tag id="1234"/>
i.e. without closing tag?

Hi adamay,
Please refer to this thread.
http://stackoverflow.com/questions/8182245/create-xml-element-without-closing-tag-using-xslt
I think you could try the way of write your own class derived from XmlWriter.
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How to delete xml tags Urgent

on release function i am inserting this value
"(&-box*&", "&*box-&
" in to my text box,
in text box will display like this (squarebox), when i am
trying to delete
squarebox ,
box deleting but
(&-box*&", "&*box-&
these xml elements are showing , what i have to
do ? it has to delete,
it amy have multipule box in my equation. how do delete xml
elements in this case, this is my xml code. how to delete? any one
can help me?

Then you should provide more details on what you want this new script should do.
To "delete XML tags in already tagged text", all you need is use the "untag" command on an XML Element. But how would the script "know" what XML Element should be untagged?
Disclaimer: This reply is in no way enforceable, legally binding, a promise or contract, an agreement (written, verbal, or otherwise), a commitment, obligation, or free or paid-for offer of any kind to further help, guide, aid, tip, or not hinder you, or contribute to, correct, investigate, comment on or assist with any existing, forthcoming, or planned project.

How to escape or remove the special characters in the xml element by regula

Hi members,
How to escape or remove the special characters in the xml element by regular expression in java??
For Example ,
<my:name> aaaa </my:name>
<my:age> 27 </my:age>
In the above example , i have to retrieve the value of the <my:name> Element(For examlpe -- i have to get "aaaa" from <my:name> tag)...
How to retreive this value by using DOM with XPATH in java
Thanks in Advance

Hi members,
I forget to paste my coding for the above question....This is my coding......In this display the error...... Pls reply ASAP.......
PROGRAM:
import java.io.IOException;
import java.util.Hashtable;
import java.util.Map;
import org.w3c.dom.*;
import org.xml.sax.SAXException;
import javax.xml.parsers.*;
import javax.xml.xpath.*;
public class DOMReaderForXMP {
     static Document doc;
     static XPath xpath;
     static Object result;
     static NodeList nodes;
     public DOMReaderForXMP() throws ParserConfigurationException, SAXException,
               IOException, XPathExpressionException {
          DocumentBuilderFactory domFactory = DocumentBuilderFactory
                    .newInstance();
          domFactory.setNamespaceAware(true);
          DocumentBuilder builder = domFactory.newDocumentBuilder();
          doc = builder.parse("d:\\XMP.xml");
          XPathFactory factory = XPathFactory.newInstance();
          xpath = factory.newXPath();
     public static void perform(String path) throws Exception {
          result = xpath.evaluate(path, doc, XPathConstants.NODESET);
          nodes = (NodeList) result;
     public void check() throws Exception {
          perform("//my:name/text()");
          if (!nodes.item(0).getNodeValue().equals("application/pdf")) {
               System.out.println("Mathces....!");
ERROR:
Exception in thread "main" net.sf.saxon.trans.StaticError: XPath syntax error at char 9 in {/my:name}:
Prefix aas has not been declared

How to move some xml element and its content to a new frame

Hi All,
How to move some xml element and its content to a new frame.

Hi Chinnadk,
Sorry my code its comment some lines. Now only I check the forum thread, you just try one more time.
#target InDesign;
#include "/Program Files (x86)/Adobe/Adobe InDesign CS5.5/Scripts/XML Rules/glue code.jsx"
var myDoc = app.activeDocument;
//____________________ XML RULE SET
var myRuleSet = new Array (new margintag);
with(myDoc){
    var elements = xmlElements;
    __processRuleSet(elements.item(0), myRuleSet);
function margintag(){
    this.name = "margintag";
    //this.xpath = "//margintag[@type='mn2']";
    this.xpath = "//margintag";
    this.apply = function(myElement, myRuleProcessor){
        with(myElement){
            app.select(myElement);
            try{
                var myPrePara = app.selection[0].paragraphs[-1].parentTextFrames[0].paragraphs.previousItem(app.selection[0].paragraphs[-1]);
                if(myPrePara.characters[-1].contents=="\r"){
                    myPrePara.characters[-1].remove();
                var myTextframe = myElement.placeIntoInlineFrame(["7p9","6p"]);
                myTextframe.appliedObjectStyle= myDoc.objectStyles.item("MN1");
                myTextframe.fit(FitOptions.FRAME_TO_CONTENT);
                myTextframe.parentStory.paragraphs.everyItem().appliedParagraphStyle = app.activeDocument.paragraphStyles.itemByName("MN1");
                }catch(e){}
            app.selection = null;
        return true;
thx,
csm_phil

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