How to replace XML elements using java

I have been usint SAX 2.0 and DOM Level 2 api's to represent XML documents, which i parse with apache's Xerces parser... I am trying to delete certain elements and replace them with others, but none of the api's allow this the closes i have come is replacing attributes of elements....

Answered in crosspost.
http://forum.java.sun.com/thread.jspa?threadID=638156

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How to modify the content of a xml element using java?

Hi all,
In my usecase I need to export some data from the database to the external file (Ms Word) using java.
The data which I get from the database will be in the form of a xml file. In that xml file
I got to modify the content of an attribute of a xml element in the java class. Kindly comeup with your help
to achieve this.
Thanks,
Phanindra.
Edited by: 887737 on Dec 5, 2011 5:52 AM

Why don't you try Xerces2?Why don't you tell him to use the javax.xml APIs that are already built in? And that use Xerces2 under the hood? Instead of throwing out a suggestion that might lead to him adding another copy of Xerces into his application?
@OP there are several techniques:
- string replacement as suggested by jschell
- XML parsing to a DOM and then use the DOM API
- XSLT
Which you should use depends on the complexity of your requirement.

How replace XML Elements with java

I have been usint SAX 2.0 and DOM Level 2 api's to represent XML documents, which i parse with apache's Xerces parser... I am trying to delete certain elements and replace them with others, but none of the api's allow this the closes i have come is replacing attributes of elements....

-jverd
You might also want to look into jdom or dom4j.Thanks jdom worked for replaceing the elements and attributes...but when i tried to store the changes in a new file, the text nodes were processed. for e.g. if i had &#8217 the char ( ' ) appeared in the new file. how do i keep the unicode...

How to make XML element used in RTF PRIVATE/PUBLIC ? I know how to hide columns in RTF, but dont know how to generate the xml in below way. Please help.

Hi
I am following below link to hide/show my columns dynamically. See "Column Formatting"
http://docs.oracle.com/cd/E12844_01/doc/bip.1013/e12187.pdf
As per doc, element can be made private/public.
<items type="PUBLIC">
<item>
<name>Plasma TV</name>
<quantity>10</quantity>
<price>4000</price>
</item>
<item>
And same can be used to hide the column using condition
<?if@column:/items/@type="PUBLIC"?>
MY QUESTION IS HOW TO DO THIS IN MY XML BELOW?
Below is part of my XML code which I am using in Data Definition for RTF.
<group name="GH3" source="QH3">
<element name="COLUMN_HEAD3" value="COLUMN_NAME" />
</group>
<group name="GH4" source="QH4">
<element name="COLUMN_HEAD4" value="COLUMN_NAME" />
</group>
I am getting output like this.
<LIST_GH3>
<GH3>
<COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
</GH3>
</LIST_GH3>
<LIST_GH4>
<GH4>
<COLUMN_HEAD4>XYZ</COLUMN_HEAD4>
</GH4>
</LIST_GH4>
In order to use logic as per oracle document I want output like this.
<LIST_GH3 type="PUBLIC">
<GH3>
<COLUMN_HEAD3>REBILL_TO_OTHER_BUSINESS_UNIT</COLUMN_HEAD3>
</GH3>
</LIST_GH3>
<LIST_GH4 type="PRIVATE">
<GH4>
<COLUMN_HEAD4>BLANK</COLUMN_HEAD4>
</GH4>
</LIST_GH4>
What changes I need to make in my XML code to get the runtime output as above? Please help. Where do i need to make changes in the above xml? Group name? Element name?
I am planning to use below condition in RTF template to hide the column, but dont know how to set the type of column as PRIVATE/PUBLIC in the XML output used to populate data in the RTF at runtime.
<?if@column:/BTSPIEXP/LIST_GH3/@type=”PUBLIC”?>COLUMN_HEAD3<?end if?>
Regards,
Swapnil K.

Hi,
Issue has been resolved. I used the value of the element to determine to display it or not.
Regards,
Swapnil K.

How to iterate xml elements using PL/SQL

Hello,
Let's say I have the following xml:
<A>
<B name="b1">
</B>
<B name="b2">
</B>
</A>
I would like to iterate over the B and sub-B elements using PL/SQL?
Any help will be appreciated.

Hi,
You can use 'PL/SQL DOM API for XMLType (DBMS_XMLDOM)'
to work with XML. You can check the example present at
http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96620/xdb08pls.htm#1041419
to check how it does.
The API for the package DBMS_XMLDOM is given on the same page(http://otn.oracle.com/docs/products/oracle9i/doc_library/release2/appdev.920/a96620/xdb08pls.htm#1040676)
You can use them for your requirement.
Regards,
Anupama

How to read XML Values using JAVA

Hi FRNDS,
I uploaded one XML File in imported Archieves, i have to read the value form XML uisng JAVA code,
using XSL able to read like xsl variable name='TimeZone' select =$linkDoc//...........*
But using java i have to read the value from XML,is it possible to read the value??
please give me some sample code.
regards,
Raja Sekhar

But using java i have to read the value from XML,is it possible to read the value??
Check the below JAVA code from help:
http://help.sap.com/saphelp_nwpi71/helpdata/en/55/7ef3003fc411d6b1f700508b5d5211/content.htm
you can ignore the XSLT part and configure only the JAVA code...check if this suits your needs.
Regards,
Abhishek.

Search and Replace XML TAG using JAVA

Hi All,
I have an XML file, say RESULT.XML Which has about 30000 Lines (yes Thirty Thousand ). For some reason i need to replace an existing tag with a different tag(not the value inside the tag, But the tag itself) . I am facing a challenge. I will explain it as below.
I have a csv file which has 2 values as given below
<VALUE A> , <VALUE B>
where <VALUE A> is an existing node in the RESULT.XML and <VALUE B> is the node that should replace <VALUE A> in the RESULT.XML
i have 500 such entries in the file.
Now i need to write a program to read the csv file, Search <VALUE A> in the RESULT.XML and Replace it with <VALUE B> of the csv file.
please let me know how do i start with this.
I really want to fix this issue.
Existing Node = <Product ID="role (contact) 3" UserTypeID="Product Number">_
To be changed to = <Product ID= role (contact)3" UserTypeID="Product Number">_
please reply if you need any further information
Thanks in Advance
Manzoor

Sounds like a job for XSLT or Perl not Java though it can be done in Java. In Java I would initially try
1) Read the csv file using one of the many free CSV parsers and build a Map<String,String>.
2) Create a Rewriter using the map keys as targets and use the map values as replacements.
3) Read the XML file line by line and process each line with the Rewriter.
4) Save each line to an output file.
For a one-off task this would probably serve but it could prove very slow if you need to run this on a daily basis.

How to read the data from Excel file and Store in XML file using java

Hi All,
I got a problem with Excel file.
My problem is how to read the data from Excel file and Store in XML file using java excel api.
For getting the data from Excel file what are all the steps i need to follow to get the correct result.
Any body can send me the code (with java code ,Excel sheet) to this mail id : [email protected]
Thanks & Regards,
Sreenu,
[email protected],
india,

If you want someone to do your work, please have the courtesy to provide payment.
http://www.rentacoder.com

How to write as XML file using java 1.5

hi all,
i am trying to create an XML file using java 1.5. I took a XML creating java file which was working with java 1.4 and ported same file into java 1.5 with changes according to the SAX and DOM implmentation in java 1.5 and tried to compile. But while writing as a file it throws error "cannot find the symbol."
can any body help me out to solve this issue.......
thankx in advance
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.w3c.dom.NamedNodeMap;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.DocumentHandler;
import org.xml.sax.InputSource;
import org.xml.sax.helpers.ParserFactory;
import java.io.*;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
               dbf.setNamespaceAware(true);
DocumentBuilder db = dbf.newDocumentBuilder();
Document xmlDoc = db.newDocument();
// this creates the xml document ref
// parent node reference
Element rootnd = (Element) xmlDoc.createElement("ALL_TABLES");
// root node
xmlDoc.appendChild(rootnd);
Element rownd = (Element) xmlDoc.createElement("ROW");
rootnd.appendChild(rownd);
Element statusnd = (Element) xmlDoc.createElement("FILE_STATUS");
rownd.appendChild(statusnd);
statusnd.appendChild(xmlDoc.createTextNode("Y")
FileOutputStream outpt = new FileOutputStream(outdir + "//forbranch.xml");
Writer outf = new OutputStreamWriter(outpt, "UTF-8");
//error is occuring here Since write method is not available in the Document class
xmlDoc.write(outf);
outf.flush();

Hi,
when I look in the JDK1.4.2 specification I don't see any write method in the Document interface.
However, your solution is the Transformer class. There you transform your DOM tree into any output you need. Your code sould look something like this:     TransformerFactory tf = TransformerFactory.newInstance();
     // set all necessary features for your transformer -> see OutputKeys
     Transformer t = tf.newTransformer();
     t.transform(new DOMSource(xmlDoc), new StreamResult(file));Then you have your XML file stored in the file system.
Hope it helps.

How to read XML files from java

i need a sugession that how to read a xml file using java code
and i need to parse using some parsers and display attributes and entity seperately
as a string.......

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.io.SAXReader;
import java.io.File;
import java.text.AttributedCharacterIterator.Attribute;
import java.util.Iterator;
import java.util.StringTokenizer;
public class XmlParser
private String Result="";
private String Final="";
private String Delim="";
public void bar1(Document document) throws DocumentException
org.dom4j.Element root = document.getRootElement();
// System.out.println(root.getName());
bar2(root);
System.out.println(this.Result);
process();
public void bar2(org.dom4j.Element e)
for(Iterator i = e.elementIterator();i.hasNext();)
org.dom4j.Element Element = (org.dom4j.Element) i.next();
Result += Element.getName()+"\t"+Element.getText()+"\n";
bar2(Element);
public void process()
StringTokenizer Tokenizer = new StringTokenizer(this.Result,"\n");
String element;
while(Tokenizer.hasMoreTokens())
element = Tokenizer.nextToken();
StringTokenizer Tokenizer2 = new StringTokenizer(element,"\t");
// Do what ever String Process here Example
this.Final += element.getName();
this.Final += this.Delim;
System.out.println(this.Final);
public static void main(String s[])throws Exception
Document document = null;
SAXReader reader = new SAXReader();
File f1= new File("D:/Rajesh/EDI to XML/EDI.xml");
document = reader.read(f1);
Demo obj = new Demo();
obj.bar1(document);
i think this will hep full.......

[CS5-5.5][JS] Replace xml element content with user selection

Hi,
I'm trying to write a script that replaces xml element content with a user selection.
I have document containing a textframe with a "root" tag attached. In this frame I have 2 paragraphs, each tagged with a different tag.
I would like to replace the content of one of the paragraphs with the content of a text selection.
This piece of code doesn't seem to work:
myXMLElement.xmlContent = app.selection[0];
The problem is that almost all properties of the xmlelement (paragraphs, words, etc) are read-only.
Does anyone have any suggestion?
Thanx

It depends on whether you want to maintain formatting. You can use
myXMLElement.contents = app.selection[0].contents;
in the (unlikely?) event that you don't mind blowing away the formatting. Otherwise you'll want to use something like:
myXMLElement.xmlContent.remove();
app.selection[0].duplicate(LocationOptions.AT_BEGINNING, myXMLElement.xmlContent);
Jeff

How to access XML elements by name in Extendscript??

I'm almost done the script that I've been working on, but something has been nagging me since I started. When I did start, I looked at the JS Tools Guide CS5 that comes with the extendscript ide to check how to access XML elements, children, attributes etc. It says this:
The XML object represents an XML element node in an XML tree. The topmost XML object for an XML file
represents the root node. It acts as a list, which contains additional XML objects for each element. These in
turn contain XML objects for their own member elements, and so on.
The child elements of an element tree are available as properties of the XML object for the parent. The
name of the property corresponds to the name of the element. Each property contains an array of XML
objects, each of which represents one element of the named type.
So basically it converts the XML into JSON. And you can access the properties like so:
<book category="COOKING">
     <title lang="en">The Boston Cooking-School Cookbook</title>
     <author>Fannie Merrit Farmer</author>
     <year>1896</year>
     <price>49.99</price>
</book>
The Javascript statement bookstoreXML.book; returns the entire list of books.
The statement bookstoreXML.book[0]; returns the XML object for the first book.
The statement bookstoreXML.book[0].author; returns all authors of the first book.
A couple pages down it talks about Retrieving contained elements using children(), elements(), descendants().
So now I look through the XML Object properties and I see that I can use:
xmlObj.child (which) which A String, the element name, or a Number, a 0-based index into this node’s child array.
or
xmlObj.descendants ([name])
name Optional. A String, the element name to match. If not provided, matches all
elements.
or
xmlObj.elements (name);
name Optional. A String, the element name to match. If not provided, matches all
elements.
This is an excerpt of an XML I was working with:
<ROW xmlns="http://www.filemaker.com/fmpdsoresult"
     MODID="16"
     RECORDID="11128">
   <Sign_Type>251.dr</Sign_Type>
   <fm:Location xmlns:fm="http://www.filemaker.com/fmpdsoresult" xmlns="">5-5024</fm:Location>
   <Line1>Zone
Floor
3
Patient Rooms
R532 - R436 even
Patient Rooms
R522 - R446 even
Xavier Elevators
Zone
Patient Rooms
R537 - 5757 odd
Main Elevators
Zone</Line1>
</ROW>
Extendscript will not give me an anything when I try to access elements by name. Instead I have to access by index, which works, but I'd rather search for names!
Actually the console log returns: <![CDATA[]]>
What am I doing wrong!?

First, those E4X XML objects are definitely no JSON (plain data) - they have a multitude of methods, even for tasks that would easily be implemented as property (e.g. the length() function), and they also bind xml element and attribute names onto the objects, allowing to target a multitude of XML nodes with a single statement. Or did you mean your script with that "it"?
Anyway, as you found out the ExtendScript XML object handles namespaces mostly by hiding them from you.
You could play around with global namespace settings, see the JavaScript tools guide.
You could also explicitly specify a namespace. This works for me:
$.writeln(myXML["fm:Location"]);
For simple use I had most success with a brute force approach that just strips the namespaces.
function removeAllNamespace(xml)
          var ns =new Namespace();
          var d=xml.descendants();
          for (var i=0;i<d.length();i++)
    d[i].setNamespace(ns);

How to set proxy authentication using java properties at run time

Hi All,
How to set proxy authentication using java properties on the command line, or in Netbeans (Project => Properties
=> Run => Arguments). Below is a simple URL data extract program which works in absence of firewall:
import java.io.*;
import java.net.*;
public class DnldURLWithoutUsingProxy {
   public static void main (String[] args) {
      URL u;
      InputStream is = null;
      DataInputStream dis;
      String s;
      try {
          u = new URL("http://www.yahoo.com.au/index.html");
         is = u.openStream();         // throws an IOException
         dis = new DataInputStream(new BufferedInputStream(is));
         BufferedReader br = new BufferedReader(new InputStreamReader(dis));
      String strLine;
      //Read File Line By Line
      while ((strLine = br.readLine()) != null)      {
      // Print the content on the console
          System.out.println (strLine);
      //Close the input stream
      dis.close();
      } catch (MalformedURLException mue) {
         System.out.println("Ouch - a MalformedURLException happened.");
         mue.printStackTrace();
         System.exit(1);
      } catch (IOException ioe) {
         System.out.println("Oops- an IOException happened.");
         ioe.printStackTrace();
         System.exit(1);
      } finally {
         try {
            is.close();
         } catch (IOException ioe) {
}However, it generated the following message when run behind the firewall:
cd C:\Documents and Settings\abc\DnldURL\build\classes
java -cp . DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:452)
at java.net.Socket.connect(Socket.java:402)
at sun.net.NetworkClient.doConnect(NetworkClient.java:139)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:402)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:618)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:306)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:267)
at sun.net.www.http.HttpClient.New(HttpClient.java:339)
at sun.net.www.http.HttpClient.New(HttpClient.java:320)
at sun.net.www.http.HttpClient.New(HttpClient.java:315)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:510)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:487)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:615) at java.net.URL.openStream(URL.java:913) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
I have also tried the command without much luck either:
java -cp . -Dhttp.proxyHost=wwwproxy -Dhttp.proxyPort=80 DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.io.IOException: Server returned HTTP response code: 407 for URL: http://www.yahoo.com.au/index.html
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1245) at java.net.URL.openStream(URL.java:1009) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
All outgoing traffic needs to use the proxy wwwproxy (alias to http://proxypac/proxy.pac) on port 80, where it will prompt for valid authentication before allowing to get through.
There is no problem pinging www.yahoo.com from this system.
I am running jdk1.6.0_03, Netbeans 6.0 on Windows XP platform.
I have tried Greg Sporar's Blog on setting the JVM option in Sun Java System Application Server (GlassFish) and
Java Control Panel - Use browser settings without success.
Thanks,
George

Hi All,
How to set proxy authentication using java properties on the command line, or in Netbeans (Project => Properties
=> Run => Arguments). Below is a simple URL data extract program which works in absence of firewall:
import java.io.*;
import java.net.*;
public class DnldURLWithoutUsingProxy {
   public static void main (String[] args) {
      URL u;
      InputStream is = null;
      DataInputStream dis;
      String s;
      try {
          u = new URL("http://www.yahoo.com.au/index.html");
         is = u.openStream();         // throws an IOException
         dis = new DataInputStream(new BufferedInputStream(is));
         BufferedReader br = new BufferedReader(new InputStreamReader(dis));
      String strLine;
      //Read File Line By Line
      while ((strLine = br.readLine()) != null)      {
      // Print the content on the console
          System.out.println (strLine);
      //Close the input stream
      dis.close();
      } catch (MalformedURLException mue) {
         System.out.println("Ouch - a MalformedURLException happened.");
         mue.printStackTrace();
         System.exit(1);
      } catch (IOException ioe) {
         System.out.println("Oops- an IOException happened.");
         ioe.printStackTrace();
         System.exit(1);
      } finally {
         try {
            is.close();
         } catch (IOException ioe) {
}However, it generated the following message when run behind the firewall:
cd C:\Documents and Settings\abc\DnldURL\build\classes
java -cp . DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.net.ConnectException: Connection refused
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:305)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:171)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:158)
at java.net.Socket.connect(Socket.java:452)
at java.net.Socket.connect(Socket.java:402)
at sun.net.NetworkClient.doConnect(NetworkClient.java:139)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:402)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:618)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:306)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:267)
at sun.net.www.http.HttpClient.New(HttpClient.java:339)
at sun.net.www.http.HttpClient.New(HttpClient.java:320)
at sun.net.www.http.HttpClient.New(HttpClient.java:315)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:510)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:487)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:615) at java.net.URL.openStream(URL.java:913) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
I have also tried the command without much luck either:
java -cp . -Dhttp.proxyHost=wwwproxy -Dhttp.proxyPort=80 DnldURLWithoutUsingProxy
Oops- an IOException happened.
java.io.IOException: Server returned HTTP response code: 407 for URL: http://www.yahoo.com.au/index.html
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1245) at java.net.URL.openStream(URL.java:1009) at DnldURLWithoutUsingProxy.main(DnldURLWithoutUsingProxy.java:17)
All outgoing traffic needs to use the proxy wwwproxy (alias to http://proxypac/proxy.pac) on port 80, where it will prompt for valid authentication before allowing to get through.
There is no problem pinging www.yahoo.com from this system.
I am running jdk1.6.0_03, Netbeans 6.0 on Windows XP platform.
I have tried Greg Sporar's Blog on setting the JVM option in Sun Java System Application Server (GlassFish) and
Java Control Panel - Use browser settings without success.
Thanks,
George

How many web.xml in a java application

Hi,
can anyone give tell the answer for this question "How many web.xml in a java application?"

1Why ?Because the Web container refers to only one web.xml for one web application.
I havent heard of an application having more than 1 web.xml
How?It reads all the definitions of servlet mappings, filters, welcome-file etc from this file itself.
Where?From the following folder ...
/WEB-INF
By the way ..... the way you questioned me was amuzing ... Why? How ?Where ? Its funny :D
I actually wanted to reply as below ..
Why ?Why not
How?
Wait lemme think ....ummm... What do you mean how??
Where ?
Inside the web ;-)
-Rohit

How to replace XML elements using java

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