How to upload a file to the server using ajax and struts

With the following code iam able to upload a file ato the server.
But my problem is It is working fine if iam doing in my system nd when iam trying to
access theis application from someother system in our office which are connected through lan
iam getting an error called 500 i,e internal server error.
Why it is so???????
Plz help me????????
It is required in my project.
I want the code to access from every system.
My exact requirement is i have to upload a file to the server and retrive its path and show it in the same page from which we
have uploaded a file.
Here the file has to be uploaded to the upload folder which is present in the server.Iam using Tomcat server.
Any help highly appreciated.
Thanks in Advance
This is my input jsp
filename.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
<script type="text/javascript">
alertflag = true;
var xmlHttp;
function startRequest(file1)
     if(alertflag)
     alert("file1");
     alert(file1);
xmlHttp=createXmlHttpRequest();
var video=document.getElementById("filepath").value;
xmlHttp.open("POST","FilePathAction.do",true);
xmlHttp.onreadystatechange=handleStateChange;
xmlHttp.setRequestHeader('Content-Type', application/x-www-form-urlencoded');
xmlHttp.send("filepath="+file1);
function createXmlHttpRequest()
     //For IE
if(window.ActiveXObject)
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
     //otherthan IE
else if(window.XMLHttpRequest)
xmlHttp=new XMLHttpRequest();
return xmlHttp;
//Next is the function that sets up the communication with the server.
//This function also registers the callback handler, which is handleStateChange. Next is the code for the handler.
function handleStateChange()
var message=" ";
if(xmlHttp.readyState==4)
     if(alertflag)
          alert(xmlHttp.status);
if(xmlHttp.status==200)
if(alertflag)
                                   alert("here");
                                   document.getElementById("div1").style.visibility = "visible";
var results=xmlHttp.responseText;
          document.getElementById('div1').innerHTML = results;
else
alert("Error loading page"+xmlHttp.status+":"+xmlHttp.statusText);
</script></head><body><form >
<input type="file" name="filepath" id="filepath" onchange="startRequest(this.value);"/>
</form>
<div id="div1" style="visibility:hidden;">
</div></body></html>
The corresponding action class is FIlePathAction
package actions;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.*;
public class FilePathAction extends Action{
     public ActionForward execute(ActionMapping mapping, ActionForm form,
               HttpServletRequest request, HttpServletResponse response)
               throws IOException, ServletException
          String contextPath1 = "";
          String uploadDirName="";
          String filepath="";
                    System.out.println(contextPath1 );
                    String inputfile = request.getParameter("filepath");
                    uploadDirName = getServlet().getServletContext().getRealPath("/upload");
                    File f=new File(inputfile);
FileInputStream fis=null;
FileOutputStream fo=null;
File f1=new File(uploadDirName+"/"+f.getName());
fis=new FileInputStream(f);
     fo=new FileOutputStream(f1);
                    try
     byte buf[] = new byte[1024*8]; /* declare a 8kB buffer */
     int len = -1;
     while((len = fis.read(buf)) != -1)
     fo.write(buf, 0, len);
                    catch(Exception e)
                              e.printStackTrace();
                    filepath=f1.getAbsolutePath();
                    request.setAttribute("filepath", filepath);
                    return mapping.findForward("filepath");
Action-mappings in struts-config.xml
<action path="/FilePathAction"
               type="actions.FilePathAction">
               <forward name="filepath" path="/dummy.jsp"></forward>
          </action>
and the dummy.jsp code is
<%=request.getAttribute("filepath")%>

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Similar Messages

Uploading a file to server using ajax and struts

My problem is i wrote a program to upload a file to the server using Ajax.
Here iam used Struts and Ajax.
The problem is when iam uploaded a file from my PC the file is uploading to the server in the upload folder located in the server my system.
Iam using Tomcat server 5.0
But when iam trying to access it through other system it is not doing so
Giving an internal server error i,e 500.
Iam putting the necessary documents for ur reference.
Plz help me soon .
My exact requirement is i have to upload a file to the upload folder located in the server.
And i have to get the path of that file and display the file path exactly below the browse button from where iam uploaded a file.
That should be done without page refresh and submit thats y iam used Ajax
Any help would greatly appreciated
Thanks and Regards
Meerasaaheb.
The action class is FilePathAction
package actions;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.*;
public class FilePathAction extends Action{
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
String contextPath1 = "";
String uploadDirName="";
String filepath="";
System.out.println(contextPath1 );
String inputfile = request.getParameter("filepath");
uploadDirName = getServlet().getServletContext().getRealPath("/upload");
File f=new File(inputfile);
FileInputStream fis=null;
FileOutputStream fo=null;
File f1=new File(uploadDirName+"/"+f.getName());
fis=new FileInputStream(f);
fo=new FileOutputStream(f1);
try
byte buf[] = new byte[1024*8]; /* declare a 8kB buffer */
int len = -1;
while((len = fis.read(buf)) != -1)
fo.write(buf, 0, len);
catch(Exception e)
e.printStackTrace();
filepath=f1.getAbsolutePath();
request.setAttribute("filepath", filepath);
return mapping.findForward("filepath");
the input jsp is
filename.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
<script type="text/javascript">
alertflag = false;
var xmlHttp;
function startRequest()
if(alertflag)
alert("meera");
xmlHttp=createXmlHttpRequest();
var inputfile=document.getElementById("filepath").value;
xmlHttp.open("POST","FilePathAction.do",true);
xmlHttp.onreadystatechange=handleStateChange;
xmlHttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlHttp.send("filepath="+inputfile);
function createXmlHttpRequest()
//For IE
if(window.ActiveXObject)
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
//otherthan IE
else if(window.XMLHttpRequest)
xmlHttp=new XMLHttpRequest();
return xmlHttp;
//Next is the function that sets up the communication with the server.
//This function also registers the callback handler, which is handleStateChange. Next is the code for the handler.
function handleStateChange()
var message=" ";
if(xmlHttp.readyState==4)
if(alertflag)
alert(xmlHttp.status);
if(xmlHttp.status==200)
if(alertflag)
alert("here");
document.getElementById("div1").style.visibility = "visible";
var results=xmlHttp.responseText;
document.getElementById('div1').innerHTML = results;
else
alert("Error loading page"+xmlHttp.status+":"+xmlHttp.statusText);
</script></head><body><form name="thumbs" enctype="multipart/form-data" method="post" action="">
<input type="file" name="filepath" id="filepath" onchange="startRequest();"/>
</form>
<div id="div1" style="visibility:hidden;">
</div></body></html>
The ajax response is catching in a dummy.jsp
<%=(String)request.getAttribute("filepath")%>
corresponding action mapping
<action path="/FilePathAction" type="actions.FilePathAction">
<forward name="filepath" path="/dummy.jsp"/>
</action>
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Iam searched alot but didnt get any solution.

Plz help me soon if it possible so
Iam in great need.
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Message was edited by:
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How to upload a file in application server to an internal table

Hi,
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*& Report ZUPLOAD1
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type-pools: truxs.
parameters: p_upl_ps radiobutton group g1 default 'X', "upload from pres. server
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constants: c_x value 'X',
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types: ty_data(1000) type c.    "structure to hold legacy data
data: i_data type standard table of ty_data. "internal table of ty_data
types: begin of stritab,
      land1 type v_t604-land1, "structure of legacy file.
      stawn type v_t604-stawn,
      bemeh type v_t604-bemeh,
      impma type v_t604-impma,
      minol type v_t604-minol,
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data: gi_itab type standard table of stritab, "internal table of legacy file
      gw_itab type stritab. "work area
data: i_raw type truxs_t_text_data,
      v_fullpath type string.
at selection-screen on value-request for p_path.
if p_upl_ps = c_x. "if presentation server is selected
perform get_file.
else.            "if application server is selected
perform set_file_path.
perform upload_from_server.
perform split_data.
endif.
form get_file.
CALL FUNCTION 'F4_FILENAME'
EXPORTING
PROGRAM_NAME        = SYST-CPROG
DYNPRO_NUMBER       = SYST-DYNNR
FIELD_NAME          = ' '
IMPORTING
   FILE_NAME           = p_path.     "getting the file name of pres server
CALL FUNCTION 'TEXT_CONVERT_XLS_TO_SAP'
EXPORTING
I_FIELD_SEPERATOR          =
    I_LINE_HEADER              = 'X'              "converting excel to sap and filling in
    I_TAB_RAW_DATA             = i_raw      "internal table
    I_FILENAME                 = p_path
TABLES
    I_TAB_CONVERTED_DATA       = gi_itab
EXCEPTIONS
   CONVERSION_FAILED          = 1
   OTHERS                     = 2
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
endform.
form set_file_path.                 "Getting the file path of application server
data: lv_file type p_file.
      lv_file = p_file.
      CALL FUNCTION 'FILE_GET_NAME_USING_PATH'
        EXPORTING
        CLIENT                           = SY-MANDT
          LOGICAL_PATH                     = p_dir
        OPERATING_SYSTEM                 = SY-OPSYS
        PARAMETER_1                      = ' '
        PARAMETER_2                      = ' '
        PARAMETER_3                      = ' '
        USE_BUFFER                       = ' '
          FILE_NAME                        = lv_file
        USE_PRESENTATION_SERVER          = ' '
        ELEMINATE_BLANKS                 = 'X'
       IMPORTING
         FILE_NAME_WITH_PATH              = v_fullpath
       EXCEPTIONS
         PATH_NOT_FOUND                   = 1
         MISSING_PARAMETER                = 2
         OPERATING_SYSTEM_NOT_FOUND       = 3
         FILE_SYSTEM_NOT_FOUND            = 4
         OTHERS                           = 5
      IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
      ENDIF.
endform.
form upload_from_server.
data: lv_msg type string,
      lw_data type ty_data.
open dataset v_fullpath for input message lv_msg in text mode encoding default.
if sy-subrc <> 0.
message lv_msg type 'i'.
stop.
endif.
do.
read dataset v_fullpath into lw_data.
if sy-subrc <> 0.
write:/5 'Error in processign data set'.
exit.
endif.
append lw_data to i_data.
enddo.
close dataset v_fullpath.
if sy-subrc <> 0.
write: /5 'Error closing dataset'.
endif.
endform.
form split_data.
data: lw_data type ty_data.
data: lw_itab type stritab.
data: begin of ty_itab,
      land1 type v_t604-land1,
      stawn type v_t604-stawn,
      bemeh type v_t604-bemeh,
      impma type v_t604-impma,
      minol type v_t604-minol,
      end of ty_itab.
loop at i_data into lw_data.
split lw_data at c_tab into
      ty_itab-land1
      ty_itab-stawn
      ty_itab-bemeh
      ty_itab-impma
      ty_itab-minol.
lw_itab-land1 = ty_itab-land1.
lw_itab-stawn = ty_itab-stawn.
lw_itab-bemeh = ty_itab-bemeh.
lw_itab-impma = ty_itab-impma.
lw_itab-minol = ty_itab-minol.
append lw_itab to gi_itab.
endloop.
endform.
start-of-selection.
loop at gi_itab into gw_itab.
write: /5 'COUNTRY', 'IMPORT CODE', 'SUP UNIT', 'FIRST UOM', 'SECOND UOM',
       /5 gw_itab-land1, gw_itab-stawn,gw_itab-bemeh,gw_itab-impma,gw_itab-minol.
endloop.
end-of-selection.
I hope problem must be in p_dir and p_file which are in bold.. Kindly help me out. Thanks in advance.

see the following ex:
*&      Form SUB_GET_FILEPATH
      text
--> p1        text
<-- p2        text
FORM SUB_GET_FILEPATH .
    GFILE = 'D:\SAP_INT\INBOUND\INBOX'. "Path
ENDFORM.                    " SUB_GET_FILEPATH
*&      Form SUB_GET_FILE
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--> p1        text
<-- p2        text
FORM SUB_GET_FILE .
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P_FDIR = GFILE.
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LOOP AT IT_FILEDIR.
    IF IT_FILEDIR-NAME(4) = 'ZINC' OR IT_FILEDIR-NAME(4) = 'zinc'.
      MOVE IT_FILEDIR-NAME TO IT_FILEDIR1-NAME.
      APPEND IT_FILEDIR1.
    ENDIF.
ENDLOOP.
IF IT_FILEDIR1[] IS INITIAL.
    STOP.
ENDIF.
LOOP AT IT_FILEDIR1.
    REFRESH: I_TAB.
    CLEAR: I_TAB.
    NAME = IT_FILEDIR1-NAME.
    CONCATENATE: GFILE '\' NAME INTO G_FILE.
    OPEN DATASET G_FILE FOR INPUT IN TEXT MODE
                                     ENCODING DEFAULT
                                     IGNORING CONVERSION ERRORS.
    IF SY-SUBRC EQ 0.
      CONCATENATE 'FILENAME : ' G_FILE INTO I_MSG1.
      APPEND I_MSG1.
      DO.
        READ DATASET G_FILE INTO RECORD.
        IF SY-SUBRC = 0.
          SPLIT RECORD AT ',' INTO I_TAB-BUKRS I_TAB-EBELN
              I_TAB-BLDAT I_TAB-XBLNR I_TAB-LIFNR I_TAB-AMOUNT
              I_TAB-CURR I_TAB-BUSAREA
              I_TAB-BKTXT I_TAB-DMBTR I_TAB-MENGE I_TAB-SRNO.
          MOVE-CORRESPONDING I_TAB TO I_TAB1.
        ELSE.
          EXIT.
        ENDIF.
        APPEND I_TAB1.
        CLEAR: I_TAB, I_TAB1.
      ENDDO.
    ENDIF.
    CLOSE DATASET G_FILE.

How to upload a File in the Enterprise Portal (JAVA)

Hi,
i have a Question.
We test the SAPNW2004sJavaSP9 Trial Version and we will upload a File in the SAP Database via the Enterprise Portal user interface.
Where should I just to click...?
How i can create a new Repository in the Folder Management ?
Thanks for your help.
Greetings,
Steve Neubert

Hi Steve,
welcome to SDN and to the KM forums.
Have a look at the KM Wiki section for introduction guides and frequently asked questions:
https://wiki.sdn.sap.com/wiki/display/KMC
This page is dealing with your specific question:
https://wiki.sdn.sap.com/wiki/x/DV
Come back if you need more information,
Robert

How to create a file in the server?

Hi,
I'm making a webservice that has to generate a XML file, sign it using another webservice and return this XML. The problem is that i don't know how to create the file in the server throught webservice.
I use this code in the webservice to generate the XML and after I return the XML to client in a byte[]
     static void outputDocumentToFile(Document myDocument, String path) {
        //setup this like outputDocument
          try {
               // XMLOutputter outputter = new XMLOutputter(" ", true);
               XMLOutputter outputter = new XMLOutputter();
               //output to a file
               FileWriter writer = new FileWriter(path);
               outputter.output(myDocument, writer);
               writer.close();
          } catch(java.io.IOException e) {
               e.printStackTrace();
    }But the file is generated in the client-side, how can I generate the file in the server-side?
Thanks very much.

Well the File object doesn't create a file it's simply an abstract representation of file and directory pathnames.
You can try something like this:
<%
try
// get the path to the web server root
// I read somewhere not to use 'getRealPath' for some reason which I
// can't seem to remember :S Hopefull someone can enlighten us :)
String path = application.getRealPath("/project/jsp/demo.txt");
File file = new File(path);
PrintWriter writer = new PrintWriter(new BufferedWriter(new FileWriter(file)));
writer.println("Hello World!");
writer.close();
catch (Exception e)
System.err.println(e.getMessage());
%>
Hope this helps :)

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