HOW TO USE SUBSTR IN PARTITIONING

HEY ALL,
CAN I USE SUBSTR IN PARTITIONING
LIKE DIS
create table test
process_id number(19),
name varchar2(15))
partition by range(process_id)
partition p1 values less than (substr(process_oid,-1))
tablespace test,
partition p2 values less than (substr(process_oid,-1))
tablespace test,
partition p3 values less than (maxvalue)
tablespace test
)

No. You cannot use like that.
Why don't you run your CREATE statement and check it for yourself. You will get the below error
ORA-14019: partition bound element must be one of: string, datetime or interval
literal, number, or MAXVALUE

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please see the HTML Business documentation on <http://help.sap.com/saphelp_nw04/helpdata/en/5f/1fb5174aee11d189740000e8322d00/frameset.htm>:
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row_number() over (partition by)
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http://download-uk.oracle.com/docs/cd/B10501_01/server.920/a96540/functions105a.htm
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Hi All,
Im using oracle 11g. I have an external table which is reading data from a file. For one of the column, i need to get only the first 250 characters. My external table defnition looks like this
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( col1 varchar2(20),
col2 varchar2(250)
organization external
( type oracle_loader
default directory XXXX
access parameters (
records delimited by newline
FIELDS TERMINATED BY '|'
missing field values are null
( col1 ,
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reject limit unlimited
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You need to play with COLUMN_TRANSFORMS
http://download.oracle.com/docs/cd/B19306_01/server.102/b14215/et_params.htm#sthref1792
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Hello Everyone,
I have one requirement where I have to use substring function on the field for report criteria.
E.G.
I have Branch Name Field where I have all branch names information, Now some of the branch names are too big with some extension after the name .
now i want to substing it but the character length varies for each branch.
so is there any way where we can use case statement where we can define that if branch name character are exceeding some value then substing it with this length.

Try something like this:
CASE WHEN LENGTH(tablename.Branch_Name) > n THEN SUBSTRING(...) ELSE tablename.Branch_Name END
where n is the number of characters you want to start the break.

How to use substring ?

guys,
i have to get last 3 char. of the char. string.
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what shoud i use ?

Hi Honar,
Try this
//<varname>- value whose last 3 character you want to read
Data : v_length type n length 3,
v_value_last3 like <varname> .
*****read the length of value
v_length = STRLEN( <varname> ) .
*****subtract string length index by 3 character
v_length = v_length - 3 .
*****read last 3 character of value
v_value_last3 = <varname>+v_length(3) .
v_value_last3 will have last 3 character
Please follow spaces as in code .
This will work .
Regards,
Jaya Tiwari

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Hi
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Apologies if this is a dumb question - I'm just familiarizing myself with Powershell.
I have an existing script which queries groups in AD. It outputs some attributes of the groups to a CSV file.
I'm trying to modify it a little bit - one of the attributes it returns is the distinguishedname of each group. I'm trying to get it to chop off the first part ("CN=groupname,"), leaving the OU path of each group.
Here is the original line that I think needs to be modified:
$AllGroups = $GroupAccounts | select -Expand Properties | select @{n='GroupName';e={$_.name}}, @{n='Description';e={$_.description}}, @{n='DN';e={$_.distinguishedname}}
Based on what I've gleaned so far about Powershell, I figured I would use the substring function, along with the length of the group's name (plus 4 to account for the "CN=" and the first comma). But every variation that I've tried returns nothing
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Hi,
Here's an example:
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Don't retire TechNet! -
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How to use substr?

Hi,
I have strings like abc.x.02 or abc.x, and I want to get the x right after abc. and before next ., this is what I tried and failed:
select substr('abcd.x.02', instr('abcd.x.02', '.', 1)+1, instr('abcd.x.02', '.', 1)+1 ) as Rev_ID from dual ;
how to fix this?
Thanks

This should work
select substr('abcd.x',
instr('abcd.x', '.', 1)+1,
(decode( (instr('abcd.x', '.', 1, 2)),
0, length('abcd.x'),
( (instr('abcd.x', '.', 1, 2)-1) - (instr('abcd.x', '.', 1)))
from dual ;
S
x
select substr('abcd.x.2',
instr('abcd.x.2', '.', 1)+1,
(decode( (instr('abcd.x.2', '.', 1, 2)),
0, length('abcd.x.2'),
( (instr('abcd.x.2', '.', 1, 2)-1) - (instr('abcd.x.2', '.', 1)))
from dual;
S
x
I came up with a similar solution at first too but it only works for the case abcd.x.02. The other requirement was that
it work for strings like abc.x too. This statement returns a null value in that case.
How about this.....
select substr('abcd.x.02', instr('abcd.x.02', '.', 1)+1, ((instr('abcd.x.02', '.', 1, 2)-1) - (instr('abcd.x.02', '.', 1))))
from dual

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hi i have a Scenario
i am getting a file like this
1,20,ram,sales
i am getting a file like this data as a column
i want to split this data in 4 different column like
1     20      ram     Sales

Hi,
this query will help you.
select
     SUBSTR(C1,0,INSTR(C1,',')-1),
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     SUBSTR(C1,INSTR(C1,',',1,2)+1,INSTR(C1,',',1,3)-INSTR(C1,',',1,2)-1),
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Message was edited by: DecaXD

How to Split the string using Substr and instr using loop condition

Hi every body,
I have below requirement.
I need to split the string and append with single quotes('') followed by , (comma) and reassign entire values into another variable. so that i can use it where clause of update statement
for example I am reciveing value as follows
ALN varchar2(2000):=(12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434);
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after modification i need above transactions should in below format
ALTR Varchar2(2000):=('12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434');
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Edited by: user627525 on Dec 15, 2011 11:49 AM

Try this - may not be the best way but...:
create or replace type myTableType as table of varchar2(255)
declare
v_array mytabletype;
v_new_str varchar2(4000);
function str2tbl
         (p_str   in varchar2,
          p_delim in varchar2 default '.')
         return      myTableType
    as
        l_str        long default p_str || p_delim;
         l_n        number;
         l_data     myTableType := myTabletype();
    begin
        loop
            l_n := instr( l_str, p_delim );
            exit when (nvl(l_n,0) = 0);
            l_data.extend;
            l_data( l_data.count ) := ltrim(rtrim(substr(l_str,1,l_n-1)));
            l_str := substr( l_str, l_n+length(p_delim) );
        end loop;
        return l_data;
   end;
begin
v_array := str2tbl ('12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434', ',');
      FOR i IN 1 .. v_array.COUNT LOOP
         v_new_str := v_new_str || ''''||v_array(i)||'''' || ',';
      END LOOP;
   dbms_output.put_line(RTRIM(v_new_str, ','));
end;
OUTPUT:
=======
'12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434'HTH
Edited by: user130038 on Dec 15, 2011 12:11 PM

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Hi there,
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How to use partition by instead of group by?

Hi,
I am having trouble using partition by clause in following case,
column other_number with null values contains 10 records in 'some_table'
5 records with date 11-01-2009, item_code = 1
5 records with date 10-01-2009, item_code = 2
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TO_char(a.some_date,'MM')
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Hi,
Almost all of the aggregate functions (the ones you use in a GROUP BY query) have analytic counterparts.
You seem to have already discovered that whatever values are returned by
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Aggregate queries collapse the result set.
The aggregate COUNT function:
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HOW TO USE SUBSTR IN PARTITIONING

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