How to write a query to select a column where the column value ends with %

Question

Hii people!!
I want to select bag_code where bag_code ends with %, e.g. A2389% from the table bags using the following
query:
select bag_code from bags where bag_id in
(select bag_id from store where store_id = 3266)
and bag_code like '%_%'
Now the problem's it returns all the possible bag codes in the store with store_id 3266.
how should i write such a query?
Abhishek.

Answer 1

I could even imagine
SQL> create index r on emp(reverse(ename));
Index created.
SQL> select empno,ename from emp where reverse(ename) like 'T%';
     EMPNO ENAME     
      7788 SCOTT      It is too sad that we have to use fbi, since reverse index does exists, but it does not get use for range scan :-(
SQL> create index r on emp(ename) reverse;
SQL> select * from emp where ename like '%T';to tune thomas query, if you are only looking for %, then you could do
where ... decode(substr(bags.bag_code, -1),'%',1) is not null
and
create [bitmap] index fbi_pct on bags(decode(substr(bag_code, -1),'%',1));
Regards
Laurent