How you search through arrays ?
Hey, how is it that you search through an array of ojects to find a specific value?
Eg
class Buildings
String name;
building [ ] build;
public Buildings ( String name, int max)
name = nam
maximum = max
build = new building[max]
in an abstract class i have an abstract public double getInsuredValue() as a method, so in the
class Flat and House, they both have their own getInsuredValue() method and in another method in the Buildings class I have made a method called
public Building createBuilding()
int type = 0;
for (int i = 0, i< maximum, i++)
if (type = 1)
build = new Flat(address, name, status and others- these are in the construct of the Flat extends Building class)
if (type = 2)
build = new House( address, name, money and others - these are in constuctor of House extends Build class)
Now what I want to be able to do, is search for the highest getInsuredValue() for a particular type of building, eg I know to find it for say all the types were just one building type
eg if it was just
build = new Building() and not ( build = new Flat() aswell as build = new House() you would go
--method name i have to use except ill take out parameter i have to use
public Building findHighestInsuredProperty()
Building highest = build[0]
double highestValue = highest.getInsuredValue()
for (int i = 0; i< maximum, i++)
if(build.getInsuredValue() > highestValue
highest = build[i]
highestValue = highest.getInsuredValue()
return highest;
but the method has a parameter in it called (int buildtype)
so for example if it was int = 1, i want it to just search through the array, look at the Flats and bring back highest, and if int = 2, i want it to look through the House ones and bring back value ? How do I do this? Thanks.
well maybe ive done something wrong before hand
the array is Building [ ] build;
in the class i have a method that adds building to array
public void addProperty (Property leftover)
if (extra == null || numberofBuilids > maximum)
return;
build[numberOfBuilds] = extra;
numberof Builds++
}the next method i want to create a Building instance and return a reference to it
public Building createBuilding()
String name;
double type;
double insu;
Building build;
for (int i = 0; i < maximum; i ++)
name = Keyboard.readString ("Name: ")
insu = Keyboard.readDouble("Insurance
type = Keyboard.readBuilding ("type")
if (type == 1)
build = new House(name, type)
if (type == 2)
buid = new Flat (name, type)
return build;
Is this right and does it add these instance to the array ?
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Unofficial Forum Rules and Guidelines - Hooovahh - LabVIEW Overlord
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Attachments:
Filter Subarray - DBL.vi 18 KB -
Searching through arrays part 3
* The moveTile method
* After the grid has been read and stored, the moveTile method
* takes in a single integer value that indicates a tile to move,
* and moves that tile into the blank tile's position, if it is a
* legal move. A move is only legal if the specified number exists
* in the grid, and if the specified tile's position is adjacent to
* the blank tile's position. The method returns a boolean value to
* indicate whether the move was made.
* @param tileToMove The tile that is to be moved.
* @return moveTile The boolean value which represents whether
* or not the move was made.
public boolean moveTile(int tileToMove){
//set default boolean value to false
boolean moveTile = false;
//scans through the rows of the puzzle
for(int scanRow=0;scanRow<grid.length;scanRow++){
//scans through the columns of the puzzle
for(int scanColumn=0;scanColumn<grid[0].length;scanColumn++){
//scans through and checks if the desired tile exists
//if it does exist, check if the '*' tile is beside it
if(grid[scanRow][scanColumn]==tileToMove){
//scans the tiles to the right of the tile being moved
for(int besideRow=scanRow;besideRow<grid.length;besideRow++){
//scans the tiles above the tile being moved
for(int besideColumn = scanColumn;
besideColumn < grid[0].length;
besideColumn++){
//scans the tile to the left of the tile being moved
for(int besideRow2 = scanRow;
besideRow2 < grid.length && besideRow2 > 0;
besideRow2--){
//scans the tile under the tile being moved
for(int besideColumn2 = scanColumn;
besideColumn2 < grid[0].length && besideColumn2 > 0;
besideColumn2--){
//if the '*' tile is above or to the right of the tile
//being moved, then swap the files
if(grid[besideRow][besideColumn]== -1){
//create a temporary storage variable to store the
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//if the '*' tile was above or to the right of the
//tile being moved
int temp;
//sets the value of the temporary storage variable
//to the value of the '*' tile
temp = grid[besideRow][besideColumn];
//sets the value of the '*' tile to the value of the
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grid[besideRow][besideColumn] = grid[scanRow][scanColumn];
//sets the value of the tile being moved to the value of
//the '*' tile
grid[scanRow][scanColumn] = temp;
//return the boolean value true since the tile was moved
moveTile = true;
//if the '*' tile is above or to the right of the tile
//being moved, then swap the files
if(grid[besideRow2][besideColumn2]== -1){
//create a temporary storage variable to store the
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//if the '*' tile was above or to the right of the
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int temp2;
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//sets the value of the tile being moved to the value of
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grid[scanRow][scanColumn] = temp2;
//return the boolean value true since the tile was moved
moveTile = true;
//returns the boolean true if the tile was moved and false if the tile
//was not moved.
//the default value is false
return moveTile;
}This is my code.... it works when the reference point of [0][0] is at the bottom left but when i changed my to string method to set the reference point of [0][0] at the top left.... it stopped swapping the tiles... it did give the correct boolean howeverThis is my code.... ... and quite a lot of code I might say (nicely documented though). I
strongly (sic) suggest that you strengthen your preconditions a bit, i.e.
don't just fill your grid[][] but keep track of the blank position also (just two
member variables).
Since you're dealing with a two dimensional thing, both a row and
column index are more appropriate than a single index number, although
the latter can easily be converted to the former. Let's denote the index
pair of the blank cell as bx, by.
Here's a simple method that determines whether or not an (x,y) pair
denotes a valid index pair in the grid:boolean isValid(int x, int y, char v) {
try {
return grid[x][y] == v;
} catch (ArrayIndexOutOfBoundsException aioobe) { }
return false;
}... this method not just tests the validity of the (x,y) index values: it also
checks whether or not the (x,y) cell contains a 'v', whatever 'v' may be.
Now suppose you want to move a tile at position (x,y) to the blank
position (xb, yb). Here's how you swap those two positions:boolean swap(int x, int y) {
if (isValid(x, y, grid[xb][yb]) {
char tmp= grid[xb][yb];
grid[xb][yb]= grid[x][y];
grid[x][y]= tmp;
xb= x; yb= y; // update the blank cell position
return true;
return false;
}The four neighbours of a cell (x,y) are easily found and a bit of logic
operator hacking yields:boolean move(int x, int y) {
return swap(x-1, y) || swap(x+1, y) || swap(x, y-1) || swap(x, y+1);
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cell, all you have to do is this:public boolean moveTile(int x, int y) {
return isValid(x, y, '*') && move(x, y);
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Also note that a bit of functional decomposition and factoring results in
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kind regards,
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1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
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woohoo! thx to jos for helping me finish the first method
now that i can swap the tiles
1 2 3 4
5 6 7 8
9 10 11 -1
how would i check to see if they are in sequential order with -1 being the last elementpackage com.allmycode.first;
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