HTTP error 302: response.sendRedirect()

Question

Hi everybody,
I have a first servlet (AGSenderServlet) sending a file to a second one (AGReceiverServlet). This second servlet I'm receiving a file and then redirect to a JSP page. But I'm getting the following exception:
13-Sep-2010 13:20:42 org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet AGSenderServlet threw exception
java.io.IOException: Received HTTP status code 302
        at AGSenderServlet.doGet(AGSenderServlet.java:43)
        at javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
        at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
        at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
        at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
....I've looked on internet and apparently the error 302 is linked to response.sendRedirect().
Here is my code:
public class AGReceiverServlet extends HttpServlet {
     public void doGet(HttpServletRequest request,
            HttpServletResponse response)
     throws ServletException, IOException {
         // Create a factory for disk-based file items
          DiskFileItemFactory factory = new DiskFileItemFactory();
         // Create a new file upload handler
          ServletFileUpload upload = new ServletFileUpload(factory);
          String realPath = this.getServletContext().getRealPath("sync/in");
          List items = null;
                    try {
                         items = upload.parseRequest(request);
                    } catch (FileUploadException e) {
                         e.printStackTrace();
                    // Process the uploaded items
                    Iterator iter = items.iterator();
                    try {
                         String fileName = "blabla";
                         while (iter.hasNext()) {
                              FileItem item = (FileItem) iter.next();
                              // Process a file upload
                              if (!item.isFormField()) {                         
                                   fileName = item.getName();
                                   long sizeInBytes = item.getSize();
                                   //Write to File
                                   if (fileName != null) {
                                      fileName = FilenameUtils.getName(fileName);
                                   File uploadedFile = new File(realPath);
                                   if (!uploadedFile.exists())
                                        uploadedFile.mkdirs();
                                   uploadedFile = new File(realPath+"/"+fileName);
                                   item.write(uploadedFile);
                         System.out.println("http://"+request.getServerName()+':'+request.getServerPort()+"/upTool/filereceived.jsp?filename="+fileName);
                         String redirectURL = "http://"+request.getServerName()+':'+request.getServerPort()+"/upTool/filereceived.jsp?filename="+fileName;
                         response.sendRedirect(redirectURL);                         
                    } catch (Exception e) {
                         e.printStackTrace();
     public void doPost(HttpServletRequest request,
            HttpServletResponse response)
     throws ServletException, IOException {
               doGet(request, response);
}The file received is saved properly and is ok.
Using print out I have discovered that it was the running the whole code but not the code in filereceived.jsp (the JSP of the sendRedirect() ).
I have tried the url used in the sendRedirect() and it works ok.
Any idea?
Cheers.

Answer 1

The AGSenderServlet is sending a file to the AGReceiverServlet using multipart and Postmethod object. Here is the code.
public class AGSenderServlet extends HttpServlet {
     public void doGet(HttpServletRequest request,
            HttpServletResponse response)
     throws ServletException, IOException {
          String filename = request.getParameter("filename");
          String ext = request.getParameter("ext");
          String serverName = request.getParameter("serverName");
          String port = request.getParameter("port");
          String path = null;
          String uri = "http://"+serverName+":"+port+"/AGReceiverServlet";
          File file = new File((this.getServletContext().getRealPath("/sync/out"))+"\\"+filename+'.'+ext);
          System.out.println("Test = "+file.getAbsolutePath());
          PostMethod post = new PostMethod(uri);
        Part[] parts = new Part[] {
            new FilePart(file.getName(), file) // File you want to upload
        post.setRequestEntity(new MultipartRequestEntity(parts, post.getParams()));
        // Now perform the POST and check for errors
        HttpClient http = new HttpClient();
        int status = http.executeMethod(post);
        if (status != HttpStatus.SC_OK) {
            throw new IOException("Received HTTP status code " + status);
     public void doPost(HttpServletRequest request,
            HttpServletResponse response)
     throws ServletException, IOException {
               doGet(request, response);
}Line 43 is just throw new IOException("Received HTTP status code " + status);What do you mean by " then you should handle it." ? I think I handle it. It redirects to the JSP filereceived.jsp which is hosted and available on the server (tried to access it directly by entering the url and it works).
Edited by: Foobrother on Sep 13, 2010 7:38 AM