I'm wondering..why does the outermost exception always catch the error?

Question

hi
why do sometimes (or everytime) i create a code which looks something like this..
try{
    try{
          //some error here
    } catch (Exception e){
           System.out.println("got it here: " + e.getMessage();
}catch (Exception e){
      System.out.println("got it here instead: " + e.getMessage();
}it's always the outermost catch block caughts the error. In this example the line got it here instead: some error messageis displayed.
I really thought for sure the inner exception is the one who should catch the error first, right? Furthermore they both catch the same thing (Exception).
Any information is greatly appreciated. thanks

Answer 1

No, you're wrong.I'm relieved to hear that. But why does my code always does what I mentioned above? here's my code (it's a partial code, actually. it takes too many lines to put all the codes here):
void generatePIN(String Date){
          char currentCodeChar;
          int seeder=0, serialNumber=0000000;
          int currentNumberInt=0, nextNumber=0, currentCodeInt=0;
          String voucherSerial=null, PINnumber=null, currentNumber=null, currentCode=null, nextCode=null, currentSerial=null, nextSerial=null;
          int PIN1=0,PIN2=0;
          String query=null;
          PreparedStatement ps=null;
          ResultSet rs=null;
          try{
               //this portion here is used for proper seeding random number
               SecureRandom sr1 = SecureRandom.getInstance("SHA1PRNG");
               seeder=sr1.nextInt();
               if (seeder<0){
                    seeder=seeder*-1;
          }catch (Exception e){
               System.out.println(e.getMessage());
               System.exit(1);
          random = new Random(seeder);
          PIN1 = random.nextInt(89999999)[phone];
          PIN2 = random.nextInt(89999999)[phone];
          PINnumber = "" + PIN1 + PIN2;
          System.out.println("PIN number: " + PINnumber);
          //check serial number first before storing the pin & serial number in database
          //if serial number exist, regenerate the serial number
          try{
               try{
               query = "select * from data1";
               ps = con.prepareStatement(query);     
               rs = ps.executeQuery();
                         while (rs.next()){
                         currentSerial = rs.getString("SerialNo");
               }catch (SQLException ex){
                    System.out.println("error here?" + ex.getMessage());
               while (currentNumberInt<=9999999){
                    currentNumberInt++;                    
          }catch (Exception e){
               JOptionPane.showMessageDialog(null,"Database error 1: " + e.getMessage());
               return;
     }the database is empty. hence it returns an error when i tried getting some data from it. but i expected the error message should be:
error here? some error message..instead of the
Database error 1: some error message pop-up being displayed.
Did i make any mistake in my code? I've spent hours on this..
thanks for helping