Image stacking (z-index) flex 3.5

Hi
This is probably a really simple question, well I hope so, but I cant figure out how to have an image over top of another.
The senario is Im making a banner. I want the left image to be layered over top of the right image.
Thanks for any advice.

So now I am using the following, but the images are not being positioned left and right. One completely obsurecs the other (on the left) and there is nothing on the right.
What am I doing wrong?
<mx:ViewStack id="viewstack1" >
<mx:Canvas label="View 1" width="100%" height="100%">
<mx:Image id="rightImg" source="
com/esri/solutions/flexviewer/assets/images/bgTopRight.png" maintainAspectRatio="
true" horizontalAlign="
right" verticalAlign="
top" visible="
true" includeInLayout="
true" autoLoad="true" />
<mx:Image id="imgLogo" source="
com/esri/solutions/flexviewer/assets/images/Commission-Eurostat-GISCO-gradient.png" maintainAspectRatio="
true" horizontalAlign="
left" verticalAlign="
top" visible="
true" includeInLayout="
true" autoLoad="true" />
</mx:Canvas>
</mx:ViewStack>

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JPEGEncoder is only useful for converting BitmapData to ByteArray, not the other way around.
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I have CS2 and would like to do Image Stacking. I understand CS3 allows this. correct? Am I wiser to purchase CS3 upgrade. Am I going to run into issues with install?

I have CS2 and would like to do Image Stacking. I understand CS3 allows this. correct? Am I wiser to purchase CS3 upgrade. Am I going to run into issues with install?

Well, I refuse to sign up to pay Adobe a monthly tribute for life too, but that doesn't mean we are limited to CS3.
I'm staying with CS6.
Adobe still sells a perpetual-license to Photoshop CS6 without the subscription model, but it's $700 for the Standard version and a cool $1,000 for the Extended version.
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Hi
Dany
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O.T. Image Stacker

Shareware but free trial. Windows only.
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Malcolm....
I came across this a while back but somehow I just can't seem to take Microsoft seriously when it comes to Digital Imaging - sure they'd like to rule the world but they're coming from behind.
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Hi premkant81,
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http://web.mac.com/douglasm/2009/January/January.html
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..in case you like to know, the imageIndex you looking for is 15
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I have two ListViews, displaying the contents of two ImageLists ("ImageList1" & "ImageList2"):
(mockup)
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My code:
ImageList1.Images.Item(intLeftChecked) = ImageList2.Images.Item(intRightChecked)
But when I do this, I get the following runtime error:
InvalidArgument=Value of '0' is not valid for 'index'.
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This is my first time using the "ImageList" control, so I'm not too familiar with its eccentricities. :(
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What do the lines
debug.print(ImageList1.Images.count)
debug.print(ImageList2.Images.count)
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The mockup I used isn't exactly what I'm doing (which is a bit more complex). I was trying to simplify the issue and may have simplified it too much. The "Left = Right" mistake is just my bumbling fingers. :)
What my app really does is show a fixed number of imageboxes on top (for example: playing cards) and a ListView below showing more images from a different folder (for example: the remaining cards). Both lists load their images directly from the
computer:
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This portion of the program works just fine:
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Image stacking (z-index) flex 3.5

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