Inheritance constructor question

Question

Hi
I am having trouble understanding how the superclasses constructor works in inheritance:
Please look at the following code:
public class mySuperClass
     mySuperClass ()
          System.out.println("super1");
public class myClass extends mySuperClass
     myClass ()
          System.out.println("hello1");
     myClass (int q)
          System.out.println("hello2");
public static void main(String[] args)
          myClass o = new myClass ();
          myClass o = new myClass (3);
When I run this program the console results are:
super1
hello1
super1
hello2
Why does the constructor of the super class run even when I overload it?
Thanks
Aharon

Answer 1

I think you meant to write "Why does the constructor of the super class run even when I overrideit?"
And the point is you can't override a constructor (technically, they are not even methods). A constructor in a derived class (MyClass) must call a constructor in its superclass (MySuperClass ). If you do not explicitly call one:
MyClass (int q) {
    super(...arguments...); // <---
    System.out.println("hello2");
}There will be an attempt to implicitly to invoke super();