Insert the previous value
What will be the easy way to insert the previous value in this table, for example if you look in row 3 I want to insert 200510, in row 6 I want to insert 200390 in row 8
I want to insert 200310..
Thank you
1 SELECT
2 szslife_pidm,
3 szslife_sgbstdn_term_code_eff
4 FROM SZSLIFE
5* WHERE SZSLIFE_pidm = 1862
SQL> /
SZSLIFE_PIDM SZSLIF
1862 200410
1862 200510
1862
1862 200290
1862 200390
1862
1862 200310
1862
Poster wants to update the values in rownumber 3,6,8
There is no rownum. Oracle will calculate the rownum according to you statement. Don't confuse with ROWID which is something completely different.
do you thing that the merge statemenet will work?
The problem is still: Whats the previous value. You still don't have a order by in you sql. Simply executing
alter table szslife parallel 2;
might change the result - no order by. Inserting of new rows might change the output of you sql. So how do you what to decide which one is the previous value? There is no order in a table!! You have to use order by in your sql statement.
Dim
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I want to do a simple thing but found it impossible.
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Hi all,
I have to include a statement in a query which allows to compare the current value of column A with the previous value of column A (same column). from there, I need to add a condition in order to have the expected result.
Let's take an example to illustrate what I want to achieve:
I have the following columns in table called 'Charges':
Ship_id batch_nr Order_nr Price
SID1111 9997 MD5551 50
SID1111 9998 MD5552 50
SID1111 9999 MD5553 50
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I want to check if the ship_id of row 2,3 (and more if available) is equal to the ship_id of row 1.
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PLease see below the expected result:
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Imco20030Hi,
user11961002 wrote:
Hi,
Here is the query that I use:
[ select
sl.ship_id,
o.ordnum,
o.reffld_5 "BatchNR",
sum(tc1.chrg_amt) "FreightPRC",
sum(tc2.chrg_amt) "FuelPRC",
sum (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt) "Total Price"
from ord_line ol
join ord o on (ol.ordnum = o.ordnum and ol.client_id = o.client_id)
join shipment_line sl on (ol.ordnum = sl.ordnum and ol.client_id = sl.client_id and ol.ordlin = sl.ordlin)
join adrmst a2 on (o.rt_adr_id = a2.adr_id)
left join tm_chrg tc1 on (tc1.chargetype = 'FREIGHT' and tc1.chrg_role = 'PRICE' and tc1.ship_id = sl.ship_id)
left join tm_chrg tc2 on (tc2.chargetype = 'FUELSURCHARGE'and tc2.chrg_role = 'PRICE' and tc2.ship_id = sl.ship_id)
where sl.ship_id = 'SID0132408'
group by o.client_id, o.ordnum, o.reffld_2, sl.ship_id, a2.adrnam, a2.adrln1, a2.adrpsz, a2.adrcty, a2.ctry_name,
o.reffld_5, ol.early_shpdte
order by ship_id
]That looks like the query you were using before you started this thread.
Modify it, using the analytic fucntions FIRST_VALUE and LAG, like I showed you.
I see that you did simplify the problem quite a bit, and it's good that you did that.
It doesn't matter that your real problem involves joins or GROUP BY. Analytic functions are calculated on the results after all joins and GROUPS BYs are done. Just substitute your real expressions for the simplified ones.
For example, in your simplified problem, there was a column called order_nr, but I see now that's it's really called o.ordnum. Where the solution I posted earlier says "ORDER BY order_nr", you should say "ORDER BY o.ordnum".
Here's a less obvious example: in your simplifed problem, there was a column called price, but I see now that it's really SUM (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt). Where the solution I posted earlier says "TO_CHAR (price)", you should say "TO_CHAR (SUM (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt))". (You can't use an alias, like "Total Price", in the same SELECT clasue where it is defined.)
I removed some columns from the select as they are not relevant for the wanted action like 'adress details or other references'.
Now here is the result:
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SID0132408 MDK-000014-05602649 04641401 110 10 120
SID0132408 MDK-000014-05602651 04641402 110 10 120
SID0132408 MDK-000014-05602652 04641363 110 10 120
as you can see, the 3 orders have the same shipment ID.
The expected result should be shown under column 'Total Price' as follows:
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SID0132408 MDK-000014-05602649 04641401 110 10 120
SID0132408 MDK-000014-05602651 04641402 110 10 tog with 04641401
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before the formatted section and this different character
after the formatted section. To post formatted text on this site, type these 6 characters
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Anyone has idea on how to compare a string value in a table.
I have a Students Table with Student_id and Student_Subject_list columns as below.
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1 Math,Science,Arts,Music,Computers,Law,Business,Social,Language arts,History
2 Math,Law,Business,Social,Language arts,History,Biotechnology,communication
3 History,Spanish,French,Langage arts
4 History,Maths,Science,Chemistry,English,Reading
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3 5 Language arts,History
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Is there an alternate approach to this without using xmlagg/xmlelement What Oracle version are you using? In 11.2 you can use LISTAGG:
insert
into Matched_Subjects
with t as (
select student_id,
column_value l,
regexp_substr(student_subject_list,'[^,]+',1,column_value) subject
from students,
table(
cast(
multiset(
select level
from dual
connect by level <= length(regexp_replace(student_subject_list || ',','[^,]'))
as sys.OdciNumberList
select t1.student_id,
t2.student_id,
listagg(t1.subject,',') within group(order by t1.l)
from t t1,
t t2
where t1.student_id < t2.student_id
and t1.subject = t2.subject
group by t1.student_id,
t2.student_id
STUDENT_ID MATCHING_STUDESNT_ID MATCHED_STUDENT_SUBJECT
1 2 Math,Law,Business,Social,Language arts,History
1 3 Language arts,History
1 4 Science,History
1 5 Math,Science,Arts,Music,Language arts,History
2 3 Language arts,History
2 4 History
2 5 Math,Language arts,History
3 4 History
3 5 History,Language arts
4 5 History,Science
10 rows selected.
SQL> Prior to 11.2 you can create your own string aggregation function STRAGG - there are plenty of example on this forum. Or use hierarchical query:
insert
into Matched_Subjects
with t1 as (
select student_id,
column_value l,
regexp_substr(student_subject_list,'[^,]+',1,column_value) subject
from students,
table(
cast(
multiset(
select level
from dual
connect by level <= length(regexp_replace(student_subject_list || ',','[^,]'))
as sys.OdciNumberList
t2 as (
select t1.student_id student_id1,
t2.student_id student_id2,
t1.subject,
row_number() over(partition by t1.student_id,t2.student_id order by t1.l) rn
from t1,
t1 t2
where t1.student_id < t2.student_id
and t1.subject = t2.subject
select student_id1,
student_id2,
ltrim(sys_connect_by_path(subject,','),',') MATCHED_STUDENT_SUBJECT
from t2
where connect_by_isleaf = 1
start with rn = 1
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