Inserting a line in schema

Hi,
How to insert a line in between the schema. Through Edit->Add line, it is adding at the end of the schema.
Samriddhi

Type in 'I' in the LHS of the screen where you see the line numbers and
press enter. It creates a blank line. You type 'I5', it will insert 5
new lines in the schema
Note:- If it does not type any value in the line numbers, delete the
line number and type the 'I' in. Also if you want to copy the same
thing to the
Next line, use 'R' and press enter. 'r' means 'to repeat'
I think this is what you need.
Thanks,
Manu

Similar Messages

How to insert new line in the copied schema with transaction code PE01?

Dear Experts,
I have copied HKT0 to ZKT0 , i want to insert new line between line 150 and line 160 in ZKT0, I don't know how to insert new line 160, who can tell me ?
Looking forward to your reply.
Best Regards,
Merry

Hi,
1. Open your schema,
2. In first colume "Line" select line where you want to add new line,
3. Replace first value in the column field (that indicates number of line) with character I (means insert),
4. Press enter
The line will be added. The same way you can add lines to PCR.
To delete use character D.
Cheers

Deleting specific line in schema

Dear Experts,
                           I had a problem regarding deletion of specific line in schema say e.g i want to delete 120 number line in schema one way to delete is from keyboard .tell me the syntax of deleting 120 number line with command.
Regards
Tayyab

000010 COM                         Import further paym./deducs. off
000020 BLOCK BEG                   Process additional payments/deductions
000070 P0015 IN11 GEN NOAB        Import additional payments
00012d PIT   ZXP8      NOAB
000130 P0579                     * Import addtnl pymnts (3rd prty system)
000140 BLOCK END                   Process additional payments/deductions
Here in the above given example i am trying to delete the line number 000120 so that , i just removed the last zero and insert a d, after that while entering the line will be delete
00012d PIT      ZXP8          NOAB
It is better to comment the line in the SCHEMA and keep it for reference you can do it by putting a star *** in the Deactivate
000130 P0579                    * Import addtnl pymnts (3rd prty system)
Note: It is better do not make any changes in the Standard SCHEMAs please copy the standard one and do your changes ( doing like this there will be a back up available for reference )
Edited by: Sujith Nambiar on May 26, 2011 10:48 AM

IF statement inserts extra line.

I am having problems with IF statements inserting extra lines;
POH_VENDOR_NAME<?if:POH_PO_NUM != ''?>(POH_PO_NUM)<?end if?>
Returns:
Consolidated Supplies
(1085)
Instead of:
Consolidated Supplies (1085)
I have tried using CHOOSE but get the same results. Any help appreciated.
Thanks
Carl.

Hi Carl,
Hope your development is going ok. Not sure why the choose wouldn't work with @inline, if the IF statement did. What I would suggest instead is using a series of IF statements. So <?if@inline:x=1?> and the opposite <?if@inline:x!=1?>
Its a bit of a pain, but I can't think of any other way to get around this.
Regards,
Cj

How to insert horizontal lines in alv report?

hi,
    i have to insert horizontal lines in alv report.( RM07MLBB )
        actually my requirement is:
                           basis list = RM07MLBB.
first secondary list = another report is called here ( RM07DOCS )
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functional modules used are REUSE_ALV_HIERSEQ_LIST_DISPLAY & REUSE_ALV_GRID_DISPLAY.
    here in this program,
                    is_layout = alv_layout.
hence i tried to give
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but not effecting.
          can some one please tell me , how to insert lines in the alv report.
thanks in advance,
Dastagir.

hello,
     so i cannot insert horizontal lines in the first secondary list according to my sorting condition, i.e., in a single block there should be :
       if same delivery challan number is repeating they should come in the same block,
for the corresponding delivery challen number, if have po number, is repeating , they also should come in the same block.
                   in this way i have to seperate the blocks containing EXNUM , EBELN CONDITIONED.

Insert specific line in an internal table at a specific place

Hi
i have an internal table (itab) let's say
Name1 Name2 NUM1 NUM2 NUM3
Which already populater with data.
i have to do a subtotal for every NAME1 and insert a line just after the NAME1 in the internal table
and another subtotal by every NAME1 NAME2 and insert a line just after every NAME1 and NAME2 in the internal table
then another Grand total at the end of the table
My psudeo code is a bit like that but the insert is done in the wrong row
Index=1
LOOP at itab index
if itab-name1 NE old
insert structure in itab index
elseif itab-name1 NE old and itab-name2 NE old
insert structure in itab index
elseif itab EQ last line
insert structure in itab index
else
structure-num1 = structure-num1 + itab-num1
structure-num2 = structure-num2 + itab-num2
endif
index = index + 1
endloop
Do you think i need to use a temporary table here. can u guide me in code plz..

sort internal table by name1 and name2. Have name1 and name2 as the first two variables in the internal table
declare a work area and an internal table with the same structure as internal table.
declare num1 as type itab-num1.
num2 and i_num2 type itab-num2.
sort itab by name1 and name2.
loop the internal itab1.
append itab1 to itab2.
wa-num1 = structure-num1 + itab-num1
wa-num2 = structure-num2 + itab-num2.
i_num2 = i_num2 + itab-num2.
num1 = num1 + itab-num1.
num2 = num2 + itab-num2.
at end of name2.
append wa to itab2.
clear wa_name2.
endat.
at end of name1.
wa-num2 = i_num2.
append wa to itab2.
clear: i_num2, wa.
endat.
at last.
wa-num1 = num1.
wa-num2 = num2.
append wa_itab2.
endat.
endloop.
Thanks.

Insert new line item in va01&va02 - urgent

Hi frndz,
At the time of creation standard sales order using va01.
When user enters the sold to party in header and then
material & quantity in line item reocrds. After user enters the details in first line. I have some checks to be executed and on the basis of that customer will get the free material that should come on second line item.
I am getting the details which i will be inserting on new line item but the problem is that in which exit i should write the code for the same.
So frndz could you please let me know, in which userexit I should insert this new line item. There can be more than one free material.
If anyone has done this already, please let me know.
I know one exit i.e.MV45AFZB but in that there are many forms. so exactly which form i should where i will write the code to insert new line item???
Points will be awarded surely.
Regards,
Prashant

HI Stephen,
I have the same prolem. I modified the 5 global tables, but I don't see the new line in the screen.
Can you help me with some details?
Thx!
Mihaela

How to insert new line break in XSLT mapping

Hi experts,
I am doing file to mail scenario, i am sending the text file as an attachment using reciever mail adapter.
I did everything, i can able to send the mail with text file attachment, but with in the file i got multiple rows, i need to put line break in XSLT mapping.
I did use following statement but it is inserting small rectangle between the records, the records are not separating with new lines, all are in one line.
<xsl:text>*#xA;</xsl:text>
note: in real coding replace * with &
Can anyone suggest me how to insert new line in XSLT mapping.
My XSLT mapping as look like:
<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://www.Coj.co.za/SapIsuToABSA/DirectDebitFile">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:variable name="break"> </xsl:variable>
<xsl:variable name="space"> </xsl:variable>
<xsl:variable name="newline"><xsl:text></xsl:text></xsl:variable>
<xsl:template match="/">
<ns1:Mail xmlns:ns1="http://sap.com/xi/XI/Mail/30">
<Subject>Please Check Attached Direct Debit File</Subject>
<From>S@za</From>
<To>P@za</To>
<Content_Type>text/plain</Content_Type>
<Content>
<xsl:for-each select="MT_SapIsuToABSA_DirectDebitFile/DirectDebitRec/Body">
<xsl:value-of select="Space1"/>
<xsl:value-of select="Cust_AccNo"/>
<xsl:value-of select="Reserve_1"/>
<xsl:value-of select="Cust_Name"/>
<xsl:value-of select="Cust_Name1"/>
<xsl:value-of select="Cust_Bank_AccNo"/>
<xsl:value-of select="Space2"/>
<xsl:value-of select="Cust_Bank_BranchNo"/>
<xsl:value-of select="Reserve_2"/>
<xsl:value-of select="Space3"/>
<xsl:value-of select="Cust_AccNo_1"/>
<xsl:value-of select="Space4"/>
<xsl:value-of select="Reserve_3"/>
<xsl:value-of select="Deduction_Amnt"/>
<xsl:value-of select="Space5"/>
<xsl:value-of select="Reserve_4"/>
<xsl:value-of select="Space6"/>
<xsl:value-of select="Action_Date"/>
<xsl:value-of select="Space7"/>
<xsl:value-of select="Reserve_5"/>
<xsl:text>*#xA;</xsl:text>
note: in real coding replace * with &
</xsl:for-each>
</Content>
</ns1:Mail>
</xsl:template>
</xsl:stylesheet>
Kind regards,
Praveen

Hi,
I think <xsl:text>#xa;</xsl:text> should do the trick, but depending on which OS (ux or win), the "new line" chars sequence is different (win would require a CRLF like <xsl:text>#xd;*#xa;</xsl:text>)
Chris
-> &
Edited by: Christophe PFERTZEL on Apr 14, 2010 2:16 PM

Report Painter insert blank line after report header

Hi Expert,
I have a problem to insert a blank line (a spacing) after the report header of my customized report painter.
For example, in standard cost center report, S_ALR_87013611, there is a small box listed information like cost center/group ... and reporting period.
Right after reporting period, the report header box ends, and there is a space line between it and the cost element data ...
For my customized report painter, I cannot make this space line.
I tried edit > row > insert blank line ... but not successful ... kindly advise.
Thanks and regards,
-CK

Hi
In KKO2 go to output tab, here under layout, tick header and then press pencil symbol and in the editor you write your header. I think this will give you desired result.
Regards
Rajneesh Saxena

Inserting new line to a text file at position #

Hi,.
Is it possible to do this in java?
1. Open a new text File (woutFile)
2. woutFile.write(" line #1\r\n"); // write new line
3. woutFile.write(" line #2\r\n"); // write new line
4.woutFile.write(" line #3\r\n"); // write new line
5. Go to line #2 position on a text file
6. Insert NEW LINE between line #2 and Line #3
7. move to the end-of-file
8.Close the file
Please help

Is it possible to do this? please look at question
inside comments.Your question has already been answered. Beyond that,
if you have some code and you want to know if it will
work, then run it and see.The answer was no. It's one of the fundamental properties of files that you cannot insert content in the middle, just at the end. To insert content you first have to make room for it. In this respect a file works like an array and not like a linked list.

How to insert multiple line items in fv60 using bdc.

Hi all,
 How to insert multiple line items in fv60 using bdcs

hi
chk this
DATA : IT_BDCDATA LIKE BDCDATA OCCURS 0 WITH HEADER LINE.
DATA : IT_MESSAGES LIKE BDCMSGCOLL OCCURS 0 WITH HEADER LINE.
DATA : V_EBELP(30) , V_MENGE(30) , V_WERKS(30), V_EMATN(30) ,
V_PEINH(30).
DATA : FILE TYPE STRING, V_MSG(100) , V_IND(2) TYPE N , FLAG VALUE 'X'.
PARAMETERS: P_FILE(50) TYPE C DEFAULT 'C:\ME21_TEST'.
DATA : BEGIN OF ITAB OCCURS 0,
 IND(02),
 LIFNR_001(010),
data element: BSART
 BSART_002(004),
data element: BEDAT
data element: EKORG
 EKORG_004(004),
 EKGRP_006(003),
data element: LPEIN
 LPEIN_005(001),
data element: EMATNR
 EMATN_01_007(018),
data element: EWERK
 WERKS_01_008(004),
data element: EPEIN
 PEINH_01_009(006),
data element: EWERK
 MENGE_01_013(017),
data element: AUFEP
 EBELP_014(005),
data element: AUFEP
 END OF ITAB.
START-OF-SELECTION.
FILE = P_FILE.
CALL FUNCTION 'GUI_UPLOAD'
EXPORTING
 FILENAME = FILE
 FILETYPE = 'ASC'
 HAS_FIELD_SEPARATOR = 'X'
HEADER_LENGTH = 0
READ_BY_LINE = 'X'
DAT_MODE = ' '
CODEPAGE = ' '
IGNORE_CERR = ABAP_TRUE
REPLACEMENT = '#'
CHECK_BOM = ' '
IMPORTING
FILELENGTH =
HEADER =
TABLES
 DATA_TAB = ITAB
EXCEPTIONS
 FILE_OPEN_ERROR = 1
 FILE_READ_ERROR = 2
 NO_BATCH = 3
 GUI_REFUSE_FILETRANSFER = 4
 INVALID_TYPE = 5
 NO_AUTHORITY = 6
 UNKNOWN_ERROR = 7
 BAD_DATA_FORMAT = 8
 HEADER_NOT_ALLOWED = 9
 SEPARATOR_NOT_ALLOWED = 10
 HEADER_TOO_LONG = 11
 UNKNOWN_DP_ERROR = 12
 ACCESS_DENIED = 13
 DP_OUT_OF_MEMORY = 14
 DISK_FULL = 15
 DP_TIMEOUT = 16
 OTHERS = 17
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
 WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
SORT ITAB BY IND.
START-OF-SELECTION.
LOOP AT ITAB.
REFRESH IT_MESSAGES.
V_IND = V_IND + 1.
AT NEW IND.
READ TABLE ITAB INDEX SY-TABIX.
PERFORM BDC_DYNPRO USING 'SAPMM06E' '0100'.
PERFORM BDC_FIELD USING 'EKKO-LIFNR'
 ITAB-LIFNR_001.
PERFORM BDC_FIELD USING 'RM06E-BSART'
 ITAB-BSART_002.
*perform bdc_field using 'RM06E-BEDAT'
 ITAB-BEDAT_003.
PERFORM BDC_FIELD USING 'EKKO-EKORG'
 ITAB-EKORG_004.
PERFORM BDC_FIELD USING 'RM06E-LPEIN'
 ITAB-LPEIN_005.
PERFORM BDC_FIELD USING 'EKKO-EKGRP'
 ITAB-EKGRP_006.
PERFORM BDC_FIELD USING 'BDC_OKCODE'
 '/00'.
ENDAT.
PERFORM BDC_DYNPRO USING 'SAPMM06E' '0120'.
CONCATENATE 'EKPO-EMATN(' V_IND ')' INTO V_EMATN.
PERFORM BDC_FIELD USING V_EMATN
 ITAB-EMATN_01_007.
CONCATENATE 'EKPO-WERKS(' V_IND ')' INTO V_WERKS.
PERFORM BDC_FIELD USING V_WERKS
 ITAB-WERKS_01_008.
CONCATENATE 'EKPO-PEINH(' V_IND ')' INTO V_PEINH.
PERFORM BDC_DYNPRO USING 'SAPMM06E' '0120'.
PERFORM BDC_FIELD USING V_PEINH
 ITAB-PEINH_01_009.
*CONCATENATE 'EKPO-MENGE(' V_IND ')' INTO V_MENGE.
*perform bdc_dynpro using 'SAPMM06E' '0120'.
*perform bdc_field using V_MENGE
 ITAB-MENGE_01_013.
*CONCATENATE 'EKPO-EBELP(' V_IND ')' INTO V_EBELP.
PERFORM BDC_DYNPRO USING 'SAPMM06E' '0120'.
PERFORM BDC_FIELD USING 'RM06E-EBELP'
 ITAB-EBELP_014.PERFORM BDC_FIELD USING 'BDC_OKCODE'
 '/00'.
AT END OF IND.
PERFORM BDC_FIELD USING 'BDC_OKCODE'
 '=BU'.
ENDAT.
CALL TRANSACTION 'ME21' USING IT_BDCDATA MODE 'A'
 UPDATE 'S'
 MESSAGES INTO IT_MESSAGES.
 LOOP AT IT_MESSAGES WHERE MSGTYP = 'E' OR MSGTYP = 'A'.
 IF FLAG = 'X'.
 CALL FUNCTION 'BDC_OPEN_GROUP'
 EXPORTING
 CLIENT = SY-MANDT
 DEST = FILLER8
 GROUP = 'GAMY_FAILURE'
 HOLDDATE = FILLER8
 KEEP = 'X'
 USER = SY-UNAME
 RECORD = FILLER1
 PROG = SY-CPROG
 IMPORTING
 QID =
 EXCEPTIONS
 CLIENT_INVALID = 1
 DESTINATION_INVALID = 2
 GROUP_INVALID = 3
 GROUP_IS_LOCKED = 4
 HOLDDATE_INVALID = 5
 INTERNAL_ERROR = 6
 QUEUE_ERROR = 7
 RUNNING = 8
 SYSTEM_LOCK_ERROR = 9
 USER_INVALID = 10
 OTHERS = 11
 IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
 WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
 ENDIF.
 CLEAR FLAG.
 ENDIF.
 CALL FUNCTION 'BDC_INSERT'
 EXPORTING
 TCODE = 'ME21'
 POST_LOCAL = NOVBLOCAL
 PRINTING = NOPRINT
 SIMUBATCH = ' '
 CTUPARAMS = ' '
 TABLES
 DYNPROTAB = IT_BDCDATA
 EXCEPTIONS
 INTERNAL_ERROR = 1
 NOT_OPEN = 2
 QUEUE_ERROR = 3
 TCODE_INVALID = 4
 PRINTING_INVALID = 5
 POSTING_INVALID = 6
 OTHERS = 7
 IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
 WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
 ENDIF.
 ENDIF.
CALL FUNCTION 'FORMAT_MESSAGE'
EXPORTING
 ID = IT_MESSAGES-MSGID
 LANG = 'EN'
 NO = IT_MESSAGES-MSGNR
 V1 = IT_MESSAGES-MSGV1
 V2 = IT_MESSAGES-MSGV2
 V3 = IT_MESSAGES-MSGV3
 V4 = IT_MESSAGES-MSGV4
IMPORTING
 MSG = V_MSG
EXCEPTIONS
 NOT_FOUND = 1
 OTHERS = 2
 WRITE : / V_MSG.
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
 WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
ENDLOOP.
 ENDLOOP.
IF FLAG NE 'X'.
CALL FUNCTION 'BDC_CLOSE_GROUP'
 EXCEPTIONS
 NOT_OPEN = 1
 QUEUE_ERROR = 2
 OTHERS = 3
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
 WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
ENDIF.
 Start new screen *
FORM BDC_DYNPRO USING PROGRAM DYNPRO.
CLEAR IT_BDCDATA.
IT_BDCDATA-PROGRAM = PROGRAM.
IT_BDCDATA-DYNPRO = DYNPRO.
IT_BDCDATA-DYNBEGIN = 'X'.
APPEND IT_BDCDATA.
ENDFORM.
 Insert field *
FORM BDC_FIELD USING FNAM FVAL.
 CLEAR IT_BDCDATA.
 IT_BDCDATA-FNAM = FNAM.
 IT_BDCDATA-FVAL = FVAL.
 APPEND IT_BDCDATA.

How to insert new line character?

Hi all,
I have two lines to print.
out.println("Available number of columns="+cols);
out.println("Number of columns must be present=10");My problem is:
i want both the lines to be printed one below the other. But, it is displayed in one single line.....
Can anyone please tell me how to insert new line character?
I tried with \n, '\n' and \r\n but, in vain......
Thanks for your time.
Regards,
Ashvini

You should never use "\n" directly.
The line separator character is different on different operating systems.
And putting quotes around it in your string will make absolutely no difference in the JSP.
To find out what the line separator is you should use System.getProperty("line.separator");
The JSPWriter and PrintWriter classes will automatically use this property with a println statement, so a println will always finish with a line separator.
The issue here was that HTML by default ignores all whitespace.
The solutions provided
- use a tag instead of a carriage return
- use <pre> tags, which tells the browser not to ignore whitespace. That can be troublesome in JSP which generates a lot of extraneous carriage returns into the code.
Cheers,
evnafets

Inserting new line item into existing delivery using BAPI

Hi
can you send me the code for inserting new line item into existing delivery either using BAPI or
Function module.
We are using SAP 4.7 version

Hi Sreekanth,
Refer to this links
New item for outbound delivery via FM/BAPI?
/message/3976349#3976349 [original link is broken]
BAPI_OUTB_DELIVERY_CHANGE Help - Add new line item
hope it is useful to you.
Regards!

Inserting new line in an array

I need to insert a line of data into a file
These are the steps I am taking
1)read the old file
2)put each line of old file into a single demention array element (248 lines)
3)add one more empty element to array (one more line)
4)shift the last four elements "down" one element <---THIS IS WHERE I AM HAVING PROBLEMS
5)insert new data into element at element 244
6)convert string array in to string
7)write the file
I am having trouble juggling the array to insert the new line.
Attachments:
lineinsert.jpg ‏54 KB

Thanks, but I guess I forgot to mention I am using Labview 5.11 and do not have the Insert into array function.
I ditched shifting and inserting into an array all together and went a completly different route.
Convert file to array
Split array at element 244 (location where new line is to be added)
Write first half of file to disk
Append the new line to the file
Append the remaining lines to the file
Message Edited by RTSLVU on 04-25-2007 11:04 AM
Message Edited by RTSLVU on 04-25-2007 11:07 AM
Attachments:
LineInsert2.jpg ‏39 KB

Inserting New Line item in PO

Hi,
I need to insert new line item into PO if the material entered is BOM material. My requirement is like this, If the user creates the PO with BOM material then i need to insert all the inside components as line item in that PO. Please suggest me any user exits avaiable or any way to achieve this( It's not a subcontracting PO).
Thanks,
Ganga.

hi
PCSD0001 Applications development R/3 BOMS
PCSD0002 BOMs: Customer fields in item
PCSD0003 BOMs: Customer fields in header
PCSD0004 BOM comparison
PCSD0005 BOMs: component check for material items
PCSD0006 Mass changes user exit
PCSD0007 Check changes in STKO
PCSD0008 WBS BOM: Customer-specific explosion for creating
PCSD0009 Order/WBS BOM, determine URL page
PCSD0010 Order/WBS BOM, determine explosion date
PCSD0011 Knowledge-based order BOM, parallel update
PCSD0012 Customer - Mat. number/mat. number during material exch
PCSD0013 Customer-specific processing of an explosion for BOM br
**Please reward suitable points***
With Regards
Navin Khedikar

Inserting a line in schema

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