Integer.parseInt() error

I am writing an applet that reads a file containing groups of 5 lines of which the first 4 hold a number. Then these values are used to draw circles. When I compile, I get this error message: "incompatible types
found: int, required: java.lang.Integer, ia = Integer.parseInt(a)".
Suggestions?
Thanks!
import java.awt.*;
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import javax.swing.*;
import java.awt.geom.*;
public class Section2 extends Applet {
TextField tekst;
public void init() {
resize(400,400);
tekst = new TextField(20);
add(tekst);
public void paint(Graphics g) {
try {
String a, b, c, d, e;
Integer ia, ib, ic, id;
File inputFile = new File(tekst.getText());
FileReader in = new FileReader(inputFile);
BufferedReader BR = new BufferedReader(in);
while (e != null){
a = BR.readLine();
b = BR.readLine();
c = BR.readLine();
d = BR.readLine();
e = BR.readLine();
ia = Integer.parseInt(a);
ib = Integer.parseInt(b);
ic = Integer.parseInt(c);
id = Integer.parseInt(d);
Graphics2D g2d = (Graphics2D)g;
Ellipse2D.Double circle = new Ellipse2D.Double(ia, ib, ic, id);     
g2d.setPaint(Color.blue);
g2d.draw(circle);
in.close();
catch (IOException e) {}

Ok everything works! I still have some questions:
*** Can anyone tell me why I get this:
--------------------Configuration: Section2 - j2sdk1.4.0_01 <Default>--------------------
Note: C:\Program Files\Xinox Software\JCreator LE\MyProjects\Section textfield\Section2.java uses or overrides a deprecated API.
Note: Recompile with -deprecation for details.
Process completed.
*** Is there a way to go from string to double in one step?
This is the code:
import java.awt.*;
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import javax.swing.*;
import java.awt.geom.*;
public class Section2 extends Applet {
     TextField tekst;
     Button knop;     
     public void init() {
          resize(400,400);
          tekst = new TextField(20);
          add(tekst);
          knop = new Button("teken");
          add(knop);
     public boolean action (Event e, Object o){
          if(e.target.equals(knop)){
               repaint();
          return true;
     public void paint(Graphics g) {
          try {
               String a, b, c, d, e;
               Integer ia, ib, ic, id;
               File inputFile = new File(tekst.getText());
               FileReader in = new FileReader(inputFile);
               BufferedReader BR = new BufferedReader(in);
               e = "start";
               if (tekst.getText() != null){
                    while (e != null){
                         a = BR.readLine();
                    b = BR.readLine();
                         c = BR.readLine();
                         d = BR.readLine();
                         e = BR.readLine();
                         ia = Integer.valueOf(a);
                         ib = Integer.valueOf(b);
                         ic = Integer.valueOf(c);
                         id = Integer.valueOf(d);
                         Graphics2D g2d = (Graphics2D)g;
                         Ellipse2D.Double circle = new Ellipse2D.Double(ia.doubleValue(), ib.doubleValue(), ic.doubleValue(), id.doubleValue());     
                         g2d.setPaint(Color.blue);
                         g2d.draw(circle);
                    in.close();
          catch (IOException e) {}

Similar Messages

  • I have jave 7 I'm trying underscore option in String.   as String strNum = "1000_000";System.out.println("..abc..."  Integer.parseInt(strNum)); but getting error. could you please help in this?

    Hi,
    There is a new feature added in java 7 on integer, called as underscore '_" and it is working fine
    if it is a normal int variable  but if it is coming with String jvm throw the error.
    if  any one of you have java8 installed on your PC can you check this is working on that version.
    int a = 1000_000;   
    String strNum = "1000_000";
    // System.out.println("..abc..."+ Integer.parseInt(strNum));
    System.out.println("a..."+a);
    Thank you,
    Shailesh.

    what is your actual question here?
    bye
    TPD

  • String equivalent of Integer.parseInt()

    Hey..
    Integer.parseInt() reads an integer that is being inputted right? what im looking though is some sort of a String equivalent of Integer.parseInt.
    ex:
    nString = JOptionPane.showInputDialog("Enter number:");
    n = Integer.parseInt(nString);
    what im looking:
    nString = JOptionPane.showInputDialog("Enter text:");
    n = ? (nString);
    a keyword that reads the text inputted.

    how do i reset the counter to 0 if the user tries again? because it doesn't reset and it makes a logical error if the user tries again.
    while (trya != 0){
           if ((trya > 1) || (trya < 0))
              break; 
         else{
      z=JOptionPane.showInputDialog("Choose Difficulty:\n[1]BATHROOM SINGER\n[2]MAINSTREAM MUSICIAN\n[3]GRAMMY WINNER");
      x=Integer.parseInt(z);
      switch(x){
           case 1:
                JOptionPane.showMessageDialog(null,"DIFFICULTY: BATHROOM SINGER");
                String stringInput = JOptionPane.showInputDialog(q1);
            if (stringInput.equals(a1)){
            JOptionPane.showMessageDialog(null, "Correct!");
            i++;
            } else {
                j++;
            JOptionPane.showMessageDialog(null,"Wrong");
    String stringInput29 = JOptionPane.showInputDialog(q15);
            if (stringInput29.equals(a15)){
            JOptionPane.showMessageDialog(null, "Correct!");
            i++;
            } else {
                j++;
            JOptionPane.showMessageDialog(null,"Wrong");
                JOptionPane.showMessageDialog(null,"Correct answers: "+i+"\nWrong answers: "+j+"\nTHANKS FOR PLAYING");
                break;
         default:
              JOptionPane.showMessageDialog(null,"Press either [1] [2] or [3]", "ERROR",JOptionPane.WARNING_MESSAGE);
              break;
        stry = JOptionPane.showInputDialog("Do you want to PLAY AGAIN? \n Press [1] for YES \n Press [0] for NO");
         trya = Integer.parseInt(stry);
      }

  • Integer.parseInt()

    Hi!
    I have a problem that for an experienced programmer like you should be easy.
    I have in my program:
    int num = Integer.parseInt(numbers);
    And I get:
    Exception in thread "main" java.lang.NumberFormatException: For input string: "195400011111111111111113"
    It (195400011111111111111113) looks like not an integer,and I tried:
    long num = Integer.parseInt(numbers);
    But I get the same error.
    What could I do?
    Thank you,
    Nata

    That number is too big for an int, so Integer.parseInt doesn't like it. It doesn't matter if you put a long on the left side of the equals sign, Integer.parseInt only handles ints.
    Do you know about the Long class? Have you looked at its docs to see if it might have something that can help you?

  • Integer.parseInt(in.readLine()) - "null"

    I just realized that if I don't enter a value in the following:
            System.out.print("Enter the column you'd like to mark in: ");
            int col = Integer.parseInt(in.readLine());I get this error:
    Enter the column you'd like to mark in:
    java.lang.NumberFormatException: For input string: ""
         at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
         at java.lang.Integer.parseInt(Integer.java:447)
         at java.lang.Integer.parseInt(Integer.java:476)
         at la5.TicTacToeDriver.main(TicTacToeDriver.java:37)
    Exception in thread "main" Is there a way to prevent this error and prompt the user for a proper input (any integer will work).

    Enclose the parse attempt in a try/catch block.

  • Something's wrong with my Integer.parseInt...

    hi...I think something's wrong with my code.
    when i don't add the loop for(int s = h; s > 0; s--) { }, it's correct, but when i do, it shows:
    java.lang.NumberFormatException: 27.0
    at java.lang.Integer.parseInt(Integer.java:414)
    at java.lang.Integer.parseInt(Integer.java:454)
    at chiayaochien3.evaluate.find(evaluate.java:55)
    at chiayaochien3.evaluate.operate(evaluate.java:48)
    at chiayaochien3.Main.main(Main.java:10)
    Exception in thread "main"
    (But i am sure the things in Integer.parseInt is String...)
    public class Main
    public static void main(String[] args)
    String[] data = {"3","+","12","*","27","/","1","-","6", "+", "222"};
    String[] operStack = null;
    String[] numStack = null;
    myStack num1 = new myStack();
    myStack num2 = new myStack();
    myStack oper1 = new myStack();
    myStack oper2 = new myStack();
    int calculateNum1 = 0;
    int calculateNum2 = 0;
    String calculate1 = null;
    String calculate2= null;
    String oper = null;
    double resultNum = 0;
    double result = 0;
    int operSize = 0;
    int numSize = 0;
    int h = 0;
    for(int i = 0; i < data.length; i++) {
    String f = data;
    if(f.compareTo("+") == 0)
    oper1.push(f);
    else if(f.compareTo("-") == 0)
    oper1.push(f);
    else if(f.compareTo("*") == 0) {
    oper1.push(f);
    h++;
    else if(f.compareTo("/") == 0){
    oper1.push(f);
    h++;
    else if(f.compareTo("^") == 0){
    oper1.push(f);
    h++;
    else
    num1.push(f);
    }//end of for
    for(int s = h; s > 0; s--){
    while(!oper1.isEmpty()) {
    calculateNum1 = Integer.parseInt((String)num1.pop());
    oper = (String)oper1.pop();
    if(oper.compareTo("*") == 0) {
    calculateNum2 = Integer.parseInt((String)num1.pop());
    resultNum = calculateNum2*calculateNum1;
    num2.push(String.valueOf(resultNum));
    while(oper1.isEmpty() == false && num1.isEmpty() == false) {
    oper2.push((String)oper1.pop());
    num2.push((String)num1.pop());
    }//end of while
    }//end of if
    else if(oper.compareTo("/") == 0) {
    calculateNum2 = Integer.parseInt((String)num1.pop());
    resultNum = calculateNum2/calculateNum1;
    num2.push(String.valueOf(resultNum));
    while(oper1.isEmpty() == false && num1.isEmpty() == false) {
    oper2.push((String)oper1.pop());
    num2.push((String)num1.pop());
    }//end of while
    }//end of else-if
    else if(oper.compareTo("^") == 0) {
    calculateNum2 = Integer.parseInt((String)num1.pop());
    resultNum = Math.pow(calculateNum2, calculateNum1);
    num2.push(String.valueOf(resultNum));
    while(oper1.isEmpty() == false && num1.isEmpty() == false) {
    oper2.push((String)oper1.pop());
    num2.push((String)num1.pop());
    }//end of while
    }//end of else-if
    else {
    num2.push(String.valueOf(calculateNum1));
    oper2.push(oper);
    }//end of else
    }//end of while
    while(!oper2.isEmpty()){
    oper1.push((String)oper2.pop());
    while(!num2.isEmpty()) {
    num1.push((String)num2.pop());
    while(!num1.isEmpty()) {
    System.out.println(num1.pop());
    while(!oper1.isEmpty())
    System.out.println(oper1.pop());
    }//end of main
    }//end of class

    "27.0" is not an integer. (Well, it is numerically, but it's a representation of a double.)

  • Integer.parseInt, NumberFormatException

    Hi,
    I'm trying to convert numbers back and forth with parseInt and toHexString.
    The number that I want to manipulate is 56789abc.
    String str = Integer.toHexString(1450744508);
    int i = 0;
    try
    i = Integer.parseInt(str, 16);
    catch(NumberFormatException e)
    e.printStackInfo();
    I'm not sure why I'm getting NumberFormatException, since I think
    56789ABC doesn't cross the line. It's not out of boundary.
    Any suggestion or help really be appreciated.
    Thanks in advance,

    I don't know what you're talking about.
    Integer.parseInt("56789ABC", 16);gives 1450744508
    Works fine.

  • Integer.parseInt() method

    Hi to all
    I'm trying to write a piece of a lexical analizer in Java and I need the method the does the contrary of Integer.parseInt() method in order to do the following:
    once i have as input an integer and with the Integer.parseInt() method i know it's value I want to count it's digits. I'm sure there is a method that do the contrary of Integer.parseInt() method that I can't remeber.
    Thanks for your help
    Maddy

    Integer.parseInt() takes in a String and returns an int value, so the contrary would take in an int value and return a String. Is this what you want?
    You can use Integer.toString()
    Also, when you call Integer.parseInt(String s), you should already have the number as a String (the argument).
    Maybe I am not understanding the question right. If not, please explain exactly what you need.

  • Integer.parseInt problems

    Hi everyone,
    I want to use the Integer.parseInt and Byte.parseByte methods to parse hex strings - the problem is that they don't parse negative 2's complement numbers, they explicitly need a minus sign in front of an otherwise unsigned number to show that it's negative.
    Examples:
    //System.out.println(Integer.parseInt(Integer.toHexString(-1), 16)); //NumberFormatException
    System.out.println(0xffffffff); // but this prints -1
    //System.out.println(Byte.parseByte("ff", 16)); //NumberFormatException
    System.out.println(Byte.parseByte("-1", 16)); // but this worksIs there some other method that will do what I need?
    Regards,
    Jonathan

    Here's a dirty solution:public class Test {
        private static char[] digits = new char[] {
            '0', '1', '2', '3',
            '4', '5', '6', '7',
            '8', '9', 'a', 'b',
            'c', 'd', 'e', 'f'
        public static void main (String[] parameters) {
            String number = Integer.toHexString (parameters[0].equals ("+") ? Integer.MAX_VALUE : parameters[0].equals ("-") ? Integer.MIN_VALUE : Integer.parseInt (parameters[0]));
            if ((number.length () == 8) && (getPosition (number.charAt (0)) >= 8)) {
                String newNumber = "";
                for (int i = 0; i < number.length (); i ++) {
                    newNumber += digits[15 - getPosition (number.charAt (i))];
                number = "";
                boolean carry = true;
                for (int i = 7; i >= 0; i --) {
                    int position = getPosition (newNumber.charAt (i));
                    if (carry) {
                        position = (position + 1) % 16;
                        carry = (position == 0);
                    number = digits[position] + number;
                number = "-" + number;
            int numberAsInt;
            try {
                numberAsInt = Integer.parseInt (number, 16);
            } catch (NumberFormatException exception) {
                // -8000000
                numberAsInt = Integer.MIN_VALUE;
            System.out.println (numberAsInt);
        private static int getPosition (char digit) {
            int position = 0;
            while ((position < digits.length) && (digits[position] != digit)) {
                position ++;
            return position;
    }Start with java Test <yourNumber>: + for Integer.MAX_VALUE, - for Integer.MIN_VALUE.
    I don't claim it's good or efficient: it's working though. There's lots of things to improve.
    Kind regards,
      Levi

  • NetBeans 6.5 - Integer.parseInt(String)

    Hello,
    I'm beginner with NetBeans 6.5.
    I created a simple hello-java application and a simple hello java-web JSF application.
    I have no error with hello-java application for these 2 lines:
    String name = "12345";
    int aInt = Interger.parseInt(name) ;
    but I get exception handler from java-web JSF application as below.
    Hope you help me to solve this, Thanks !
    Exception Handler
    Description: An unhandled exception occurred during the execution of the web application. Please review the following stack trace for more information regarding the error.
    Exception Details: java.lang.NumberFormatException
    null
    Possible Source of Error:
    Class Name: java.lang.Integer
    File Name: Integer.java
    Method Name: parseInt
    Line Number: 415
    Source not available. Information regarding the location of the exception can be identified using the exception stack trace below.
    ......

    they're different, i was trying to convert the string entered in a TextField to a number, and thought that I already hard coded '12345' in the code to see whether the parseInt works therefore i didn't enter anything in the TextField.
    thanks raychen !

  • HashSet - Adding Integer values - Error Class Excpetion Help

    I am trying to add integers into the HashSet it is not allowing me to add it? does it mean that I cannot add integers. I also tried using the Integer class to input the values, still getting the same error. The Error is in the line : ts.add(3);
    Any thoughts why such an error ?
    The error that I get is :
    java TreeTest
    Exception in thread "main" java.lang.ClassCastException: java.lang.String
    at java.lang.Integer.compareTo(Integer.java:35)
    at java.util.TreeMap.compare(TreeMap.java:1093)
    at java.util.TreeMap.put(TreeMap.java:465)
    at java.util.TreeSet.add(TreeSet.java:210)
    at TreeTest.main(TreeTest.java:12)
    PK
    import java.util.*;
    class TreeTest
         public static void main(String[] args)
              TreeSet ts = new TreeSet();
              ts.add("Z");
              ts.add("A");
              ts.add("P");
              ts.add(3);
              ts.add(new Integer(1));
              ts.add(new Integer(7));
              System.out.println("The size is \t" + ts.size());
    }

    hii,
    In the TreeSet the elements you add should be of same class type.
    otherwise it can't do the sorting process.can u sort alphabets and numeric together? if u are adding Integer type only add int values or objs.if u want to add String add that n String objs.
    try the following code
    import java.util.*;
    class TreeTest
         public static void main(String[] args)
              try
              TreeSet ts = new TreeSet();
              int a=3;
              //ts.add("Z");
              //ts.add("A");
              //ts.add("P");
              ts.add(new Integer(7));
              ts.add(new Integer(1));
              ts.add(a);
              System.out.println("The size is \t" + ts.size());     
              catch (Exception e)
                   System.out.println(e);     
    }

  • "Integer Overflow" error

    I'm seeing this error since i bought my new laptop using windows 8.1 pro. Now i formatted my pc and installed skype voila! The same error again! this is really annoying please what's causing this problem someone help me?

    i have reinstalled an earlier driver and attached new dxdiag diagnostic file. 
    I'm still seeing the error. Here is i found something regarding killer service and skype conflict: http://service.msicomputer.com/msi_user/support/TechFAQdetail.aspx?formid=3054
    my problem is different tough, i will give it a try.
    Attachments:
    DxDiag.zip ‏16 KB

  • CMP findByPrimaryKey( Integer primaryKey ) Error

    I am using WebLogic 7.0 and my test program is throwing following error. I struggled to solve the problem for the last 2 days. Please Help
    run:
         [java]
         [java] Beginning com.tt.schms.school.ejb.cmp.Client...
         [java]
         [java] Trying to find school with id: 0
         [java] There was an exception while creating and using the School.
         [java] This indicates that there was a problem communicating with the server: javax.ejb.FinderException: Problem in
    findByPrimaryKey while preparing or executing statement: 'weblogic.jdbc.rmi.SerialPreparedStatement@353cde':
         [java] java.sql.SQLException: No data found
         [java] java.sql.SQLException: No data found
         [java]     at sun.jdbc.odbc.JdbcOdbc.standardError(JdbcOdbc.java:6207)
         [java]     at sun.jdbc.odbc.JdbcOdbc.SQLGetDataInteger(JdbcOdbc.java:3166)
         [java]     at sun.jdbc.odbc.JdbcOdbcResultSet.getDataInteger(JdbcOdbcResultSet.java:5333)
         [java]     at sun.jdbc.odbc.JdbcOdbcResultSet.getInt(JdbcOdbcResultSet.java:550)
         [java]     at weblogic.jdbc.jts.ResultSet.getInt(ResultSet.java:141)
         [java]     at weblogic.jdbc.rmi.internal.ResultSetImpl.getInt(ResultSetImpl.java:210)
         [java]     at weblogic.jdbc.rmi.internal.ResultSetStraightReader.getInt(ResultSetStraightReader.java:57)
         [java]     at weblogic.jdbc.rmi.SerialResultSet.getInt(SerialResultSet.java:188)
         [java]     at com.tt.schms.school.ejb.cmp.SchoolBean_15djmm__WebLogic_CMP_RDBMS.__WL_loadGroup0FromRS(SchoolBean_1
    5djmm__WebLogic_CMP_RDBMS.java:941)
         [java]     at com.tt.schms.school.ejb.cmp.SchoolBean_15djmm__WebLogic_CMP_RDBMS.ejbFindByPrimaryKey(SchoolBean_15d
    jmm__WebLogic_CMP_RDBMS.java:724)
         [java]     at java.lang.reflect.Method.invoke(Native Method)
         [java]     at weblogic.ejb20.cmp.rdbms.RDBMSPersistenceManager.findByPrimaryKey(RDBMSPersistenceManager.java:216)
         [java]     at weblogic.ejb20.manager.BaseEntityManager.findByPrimaryKey(BaseEntityManager.java:755)
         [java]     at weblogic.ejb20.manager.BaseEntityManager.remoteFindByPrimaryKey(BaseEntityManager.java:698)
         [java]     at weblogic.ejb20.internal.EntityEJBHome.findByPrimaryKey(EntityEJBHome.java:367)
         [java]     at com.tt.schms.school.ejb.cmp.SchoolBean_15djmm_HomeImpl.findByPrimaryKey(SchoolBean_15djmm_HomeImpl.j
    ava:102)
         [java]     at com.tt.schms.school.ejb.cmp.SchoolBean_15djmm_HomeImpl_WLSkel.invoke(Unknown Source)
         [java]     at weblogic.rmi.internal.BasicServerRef.invoke(BasicServerRef.java:362)
         [java]     at weblogic.rmi.cluster.ReplicaAwareServerRef.invoke(ReplicaAwareServerRef.java:114)
         [java]     at weblogic.rmi.internal.BasicServerRef$1.run(BasicServerRef.java:313)
         [java]     at weblogic.security.service.SecurityServiceManager.runAs(SecurityServiceManager.java:821)
         [java]     at weblogic.rmi.internal.BasicServerRef.handleRequest(BasicServerRef.java:308)
         [java]     at weblogic.rmi.internal.BasicExecuteRequest.execute(BasicExecuteRequest.java:30)
         [java]     at weblogic.kernel.ExecuteThread.execute(ExecuteThread.java:213)
         [java]     at weblogic.kernel.ExecuteThread.run(ExecuteThread.java:189)
         [java]
         [java]
         [java] End com.tt.schms.school.ejb.cmp.Client...
         [java]Please note that corresponding data is there in the database. When I access the DB using BMP from the same client code, it works fine.
    I searched this forum but could not find appropriate soln. There was one topic where the problem was solved by putting brackets around the where clause of ejbql. I assume findByPrimaryKey() method is implemented by the Container so I do not need to define ejbql (Am I correct ?) .
    Let me know gurus.
    Thanx

    Got around this problem by using direct jdbc driver instead of jdbc-odbc bridge.
    I know there are several limitations with jdbc-odbc bridge which might be causing this problem

  • Class of Integer.parseInt

    Hi..,
    I really need help. I am trying to make a really simple program. And that I want to make an argument class so that I can reuse it again and again without typing the long word (Integer...)
    Here is the problem:
    Rational r2 = new Rational(toInt(args[0]));
    I think I should make a toInt method, but I don't know how. It is quite confusing. I think this toInt method, we should put it inside the main method. But i don't know yet.
    Please Help me!

    well with the way you wrote it, toInt is a class, not a method. What you are probably envisioning is a class with a constructor which takes a String parameter and returns an int. Unfortunately, constructors don't return values. You can try using the object wrapper class Integer though.
    One suggestion, if you hate the typing for getting arg parameters, make a method which takes the whole args array and parses them into a nice int array or some other data structure you dream up to make it easier?

  • Is there any way to use Integer.parseInt using jstl

    Hi
    actually i m getting a string in a varible i need to convert it to int so that i can use it for further calculation.
    so plz tell how to do that...
    thanks

    The exception clearly states the variable isn't a valid number. Print out the value and see what it is.
    And no, you can't set the 'JSTL variable' for the simple reason that there are no 'JSTL variables' ( at least none that are public ). You're probably thinking of the EL. And no, you can't do anything there either.
    People on the forum help others voluntarily, it's not their job.
    Help them help you.
    Learn how to ask questions first: http://faq.javaranch.com/java/HowToAskQuestionsOnJavaRanch
    (Yes I know it's on JavaRanch but I think it applies everywhere)
    ----------------------------------------------------------------

Maybe you are looking for

  • Sims 3 crashes all the time on new MacBook Pro, what do I do?

    Got a brand new MacBook Pro 13inch (not retina) for Christmas. I was advised when buying the Mac to update the ram if I wanted to use it for playing the Sims 3 (which I did). Previsoulsy I had a Sony VAIO (top spec) in which the Sims 3 worked on for

  • Error received when trying to import/only one track at a time...

    When I go to import my cd into iTunes it is only letting me import one track at a time. Also occasionally I getting this error when I try to import a track. "The file 'xxxxx.cda' cannot be imported because it does not appear to be a valid exported fi

  • Accessing a file and more.

    Hi, I have an encrypted text file. I need to do the following things within my program to make it useful. 1. Read the rather large 3.2MB file. 2. Decrypt the file, it is a simple translation of A = F, B = O etc. 3. Put each word into an ArrayList<Str

  • ORA-00979: not a GROUP BY expression in Oracle11g R2

    hi, I am working in Oracle 9i Environement. I want to update Our production database from Oracle 9i to Oracle11g R2. Note :- Oracle 9i & 11g R2 are different systems. We follow the migration through import & Export Commands from Production database t

  • Failed to execute SQL via TxDataSource/JDBCConnectionPool

    I have an application running well on WLS doamin. After I deployed it to an EAI domain, it does not work any more. The WLI DB is an Oracle instance on the local box, and the application DB is an Oracle instance running on a remote box. The JDBCConnec