Interpret sample schema of sample plan table

Question

Hi guru,
May I know if my following understanding and interpretation on the sample plan table (sampling type is sampling schema) is correct:
Lot Size ---Sample Sze---c1--------d1--------c2 ------ d2------c3-------d3------c4------d4 --------c5---------d5----------c6-----------d6----------c7------------d7
10000----------20--------0----------4--------0---------4-------0---------4------0--------4----------0---------4-----------0------------4------------0-------------0
If lot size is equal or above 10000, the sample size computed by the system will be 20.
The first sample has an acceptance of zero (C1) and rejection of 4 (d1). In another word, if there is 4 or above 4 sample size is fail, it will be rejected. Correct?
Question 1 - what does the zero in C1 means? actually what is the usage of C1, C2, CN means, someone told me it is optional?
Next, if on the first sample, the 4 out of 20 of the sample size are failed, the inspection lot is failed.
Therefore, the system will triggers 2nd sample (i.e. C2, and D2) in which it is similar to C1 and D1 (i.e. 0 for acceptance, 4 for rejection), and if it fail again, the system will trigger the subsequent sample (i.e. C3, and D3) till C7 and D7, correct?
Question 2 - what will the system response if the sample lot kept failing until C6 and D6? Because the last sample (i.e. C7, and D7 are both 0), what will the system do on this?
Thanks
YY

Answer 1

Hi Gajesh,
Thanks so much on your reply, but on the answer 4 which you replied to me, I still have a bit double..
4) Question 2: what if I have 5 sample size, and the actual test result is 2 sample size are pass (which meet C1 value), and 3 sample size are fail (which is smaller than D1 value), I said the whole MIC is pass.. am I correct?
*You said: No, system will propose you to check next sample to check C2 /D2*
Why system propose the next C2/D2? My rational is based on the following statement which you previously confirmed that I am correct:
IF the actual number sample size inspection fall outside the lower & upper limit range (i.e. fail) is Equal to OR Larger than D1, THEN, the whole MIC is rejected.
Thus, my rational is if the above statement is correct, which mean if the failed number of sample size (i.e. 3) is less than d1 (i.e. 4), isn't it clearly pass? Furthermore, out of the 5 sample size, 2 sample sizes are passed (i.e. which is equal to the C1 of 2). Thus, why would the system still propose to check next which is C2/D2? Beside on the very first time, you had replied to me on this topic you saidu2026.
Suppose you have a lot size of 10 having sampling size 5 with C1(acceptance number) 0 and D1(rejection number) 3
You have quantitative MIC with single recording with a specification limit of 10 (lower) to 20 (upper)
If, in actual results, if the 3 of the results is outside the spec limits, the MIC as whole is rejected. If only 2 results are rejected the MIC stands accepted.
The following is the sample plan we talking about...
Lot Size -Sample Size-c1--d1c2---d2--c3---d3--c4--d4 -c5d5c6d6c7--
d7
10--52404---04--0404040--
0
Thanks,
Yong-Yeow