Is it possible to do this in one SQL query?

Hi there.
Please forgive me, I only have rudimentary knowledge of databases - I would just like to know if it is possible to do something. That's the most important thing I need to know. Anything additional anyone is nice enough to add regarding how to go about it would be a welcome bonus =)
As it happens, I'm sure this must have been necessary in some capacity before.
Anyway, I have two tables with a very similar attribute 'name' and 'owner name'. They aren't linked as foreign keys. I need to find examples where 'name' and 'owner' name are not the same. Unfortunately, both 'name' and 'owner name' can contain titles and/or first name and/or surname and/or any other nonsense the person completing the form cares to enter. I need a query that will not return results along the lines of:
Name Owner Name
Mr Bob Monkhouse & B Monkhouse
I need to query to classify this as the same thing, and therefore not return this result.
What I am looking to do, is retrieve entries that have the same surname. Obviously there is the disadvantage of the following being classed as the same (when, for the purpose of the query, they are not) :
Name Owner Name
Mrs Dorris Monkhouse & B Monkhouse
I just can't see anyway around that though - to change the database so that it has a First Name attribute, and Surname attribute just isn't possible.
So basically, if anyone could comment on whether it is possible to 'match' a string of characters (i.e. the surname element of 'Name' and 'Owner Name'), and write a query that will return entries with a high probability of the person in each not being the same person, I would be delighted to hear from you!
Thank you for reading

If you assume that the surname is always in the last part of the field (so you will always have "B Monkhouse", never "Monkhouse, B" and it is a varchar(2) field, then thiscan be done using a combination of INSTR (to find the ' ' (space)) and SUBSTR to clip text backwards until you find the space
I'm sure someone knows how to do this off the top of their head - I'll look it up and if no-one replies in the meantime, I'll let you know.
I'm working off a version 7 database - there may be a nattier way to do it in newer versions...

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