Is it possible to make non-virtual calls in Java?

Hi all,
I'd like to hear some expert's opinion about this: if I mark a class as final, its method call will not be virtual? that is, there won't be "late binding" in the Virtual Machine? or still the JVM binds its calls at runtime ??
I'm asking this because I had a long discussion with a guy programming in C++ that claims that ALL java calls are virtual, while on the other hand in C++ ONLY those declared as "virtual" are in fact virtual call.
So he says that this is the reason why Java will be always slower then C++.
I'd like to hear your opinion/feedback
Regards
Francesco

About this being "the reason" why C++ will
always be faster than Java: it's not. The main reason
C++ is faster than Java is that Java needs to run its
code through the virtual machine...No, that's not a reason for Java to be slower. In practice, Java code is compiled to native code on the fly, so it does not "run its code through the virtual machine."
One main reason why Java is slower than C++ is that it keeps all objects on the heap instead of on the stack. Take a look at this article on optimizing code: http://www.pgh.net/~newcomer/optimization.htm Less than halfway through the article, the author describes a performance bottleneck in a memory allocation routine. By changing the memory to be allocated on the stack instead of on the heap, the program ran about twice as fast.
Allocating memory on the heap is one of the slowest operations in Java. Programs that allocate lots of objects are going to be slow.

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Simple and perhaps idiotic question... but here it goes.
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================
import java.io.*;
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=============
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==============
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Regards
echardrd

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Simple and perhaps idiotic question... but here it goes.
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Regards
echardrd

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