Is it possible to make the fnd_user table as an authenticator to weblogic

Question

Hi,
I am looking for a way to make fnd_user table as an authenticator for a weblogic users.
Is it possible in first place without OVD and SSO ? My goal is to have fnd_users involve in human task approvals.
Thanks
Sai

Answer 1

I think your question is: how do you compare the encrypted password in FND_USER to the password that the end user entered in your custom application front end?
If that is indeed your question, you can decrypt the password in FND_USER as follows:
1) Take the standard fnd_web_sec package and make a copy called cust_fnd_web_sec. Delete all procedures in the package body except for decrypt. Then add decrypt to the package spec.
create or replace PACKAGE apps.cust_fnd_web_sec AUTHID CURRENT_USER AS
function decrypt(key in varchar2, value in varchar2)
return varchar2;
END cust_FND_WEB_SEC;
create or replace PACKAGE BODY apps.cust_fnd_web_sec AS
-- Exception
dml_inside_query exception;
pragma exception_init(dml_inside_query,-14551);
-- Function to encrypt a string using a specified key.
function decrypt(key in varchar2, value in varchar2)
return varchar2
as language java name 'oracle.apps.fnd.security.WebSessionManagerProc.decrypt(java.lang.String,java.lang.String) return java.lang.String';
END cust_FND_WEB_SEC;
2) Run the following query to decrypt the password.
WITH guest AS
SELECT 'GUEST/ORACLE' user_pwd,
UPPER (SUBSTR ('GUEST/ORACLE',
1,
INSTR ('GUEST/ORACLE',
- 1
) user_name
FROM DUAL)
SELECT distinct u.user_name,
apps.cust_fnd_web_sec.decrypt
((SELECT apps.cust_fnd_web_sec.decrypt
(g.user_pwd,
u.encrypted_foundation_password
) apps_password
FROM apps.fnd_user u,
apps.guest g
WHERE u.user_name = g.user_name),
u.encrypted_user_password
) decrypted_user_password
FROM apps.fnd_user u,
apps.fnd_user_resp_groups_direct r
where u.user_id = r.user_id
and u.user_name = <user name>
Good luck!
Scot