Issue with sorting results on the basis of specfic values.

Question

Hello,
I written an sql that will sort the results on the basis of values defined in 'IN' clause. I have made use of CASE statement in ORDER BY clause. Its not functioning. My code is:
SELECT GWLO.productcode,
          GWLA.parentsampletype,
          GWLO.sampletype SampleType,
          max(GWLA.loginid) Loginid,
          max(GWLA.modifiedts) modifiedts
     FROM gwloginattribvars GWL,
          gwloginkeyvals GWLO,
          gwloginkeysadmin GWLA
     WHERE GWLO.productcode = GWLA.productcode
          AND GWLO.sampletype = GWLA.sampletype
          AND GWLO.productcode in ('1002124', 'ABPG', 'ABIG')
          AND GWLO.sampletype <> 'CERTIFICATE-OF-ANALYSIS'
          AND GWLA.parentsampletype IS NOT NULL
     GROUP BY GWLO.productcode, GWLA.parentsampletype, GWLO.sampletype
     ORDER BY
          (CASE GWLO.productcode WHEN '1002124'     THEN 1
               WHEN 'ABPG'     THEN 2
               WHEN 'ABIG'     THEN 3
               ELSE 'LL'
               END) ASC
I expected the results to be in sequence what it is defined in CASE - ORDER By clause. This code is givin me error. The error is
(CASE GWLO.productcode WHEN '1002124' THEN 1
ERROR at line 16:
ORA-00907: missing right parenthesis
Please help. Thanks!

Answer 1

     ORDER BY
          (CASE GWLO.productcode WHEN '1002124'     THEN 1
               WHEN 'ABPG'     THEN 2
               WHEN 'ABIG'     THEN 3
               ELSE 'LL'>                END) ASC
Can u just explain me in this context? I think it should be another number in the else part - since you are returning numbers in all the 'WHEN' option. Pls explain it.
Regards.
Satyaki De.