Java binary to decimal?

how do i convert a binary number to a decimal number using Jbuttons and Jlabel for the output? the binary number should be entered into a Jtextfield
thank you

rpgangsta wrote:
how do i convert a binary number to a decimal number using Jbuttons and Jlabel for the output? the binary number should be entered into a Jtextfield
thank youThe user sees a text. You read that text, convert it into an internal representation, manipulate it, and then show the result to the user again as a text.
You have: String (read from user) -> internal data -> (manipulation of data) - > internal data - > String (shown to user).

Similar Messages

Binary to Decimal problems

Ok to give a background to why i am writing this and so everyone has a better understanding of exactly what it is that i want it to do it goes like this.... My girlfriend got a message from a friend that was all in ones and zeros, and no its not because something on one of the mail servers is messed up he meant for it to be that way. But through the process of converting the 8 digit binary numbers into decimal values so that the corresponding ANSI character could be found I decided that it was taking to damn long so i would just write a prog to do it for me and then i could send back an annoying long message to that guy with ease. Only there is a catch over the summer i went from hotshot for a newb to a newb without a clue, i more or less didnt write a single line of code over 4 months and now i am having problems.
I wanted to write a program that could-
-convert long strings of chars into all 8 digit binary code
-as well as convert large blocks of 8 digit binary back into ANSI letter values and then ANSI characters
-I want it to use a frame and have a relativly simple usage procedure
Now that you know what i set out to do I can show you how far i got -
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.awt.GradientPaint.*;
public class BinaryToDec extends JFrame implements ActionListener
     // member variables
     JButton quit;
     JButton color;
     JButton convert;
     JLabel     label11_5, labelPassingWord;
     JTextField inputBinary, outputDecimal;
     Color      colorStore;
     String drawString;
     String bin;
     public BinaryToDec()
          drawString = "";
          setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
          setLocation(100,250);
          setTitle("Binary to Decimal");
          setSize(420,200);
          getContentPane().setBackground(Color.BLACK);
          getContentPane().setLayout(null);
          quit= new JButton("DONE");
          quit.setForeground(Color.GREEN);
          quit.setBackground(Color.BLACK);
          quit.setBounds(100,10,75,20);
          getContentPane().add(quit);
          quit.addActionListener(this);
          color= new JButton("Bkgnd Clr");
          color.setForeground(Color.GREEN);
          color.setBackground(Color.BLACK);
          color.setBounds(15,10,75,20);
          getContentPane().add(color);
          color.addActionListener(this);
          convert= new JButton("Convert to Decimal");
          convert.setForeground(Color.GREEN);
          convert.setBackground(Color.BLACK);
          convert.setBounds(185,10,75,20);
          getContentPane().add(convert);
          convert.addActionListener(this);
          label11_5 = new JLabel("Enter a Binary Number");
          label11_5.setBounds(75,60,250,20);
          label11_5.setForeground(Color.GREEN);
          getContentPane().add(label11_5);
          inputBinary = new JTextField(25);
          inputBinary.setBounds(5,40,225,20);
          inputBinary.setForeground(Color.BLACK);
          getContentPane().add(inputBinary);
          inputBinary.addActionListener(this);
          labelPassingWord = new JLabel("Your Deciaml Equivilant");
          labelPassingWord.setBounds(75,120,250,20);
          labelPassingWord.setForeground(Color.GREEN);
          getContentPane().add(labelPassingWord);
          outputDecimal = new JTextField(25);
          outputDecimal.setBounds(5,100,225,20);
          outputDecimal.setForeground(Color.BLACK);
          getContentPane().add(outputDecimal);
          outputDecimal.addActionListener(this);
          setVisible(true);
     }// end of constructor
     public void actionPerformed (ActionEvent evt)
          if(evt.getActionCommand().equals("DONE"))
               System.out.println("Quit Caught");
               int choice = JOptionPane.showConfirmDialog(null , "You Pressed " + evt.getActionCommand() + " are you sure?"
                    , "Close Frame",JOptionPane.YES_NO_OPTION);
               if(choice == 0)
                    this.dispose();
               if (evt.getSource() == color)
                    Color color = Color.lightGray;
                    color = JColorChooser.showDialog(BinaryToDec.this,"Choose a color",color);
                    getContentPane().setBackground(color);
               if (evt.getSource() == convert)
                    bin = inputBinary.getText();
                    int strLength = bin.length();
                    int pos1=0, pos2=7;
                    String temp = "";
                    String Decimal1 = "";
                    String Decimal2 = "";
                    int binLength = 8;
                    int count = 0;
                         do
                              temp = bin.substring(pos1,pos2);
                              Decimal1 = Convert(temp);
                              Decimal2 = Decimal2 + "" + Decimal1;
                              pos1 = pos1 + binLength;
                              pos2 = pos2 + binLength;
                              count++;
                              outputDecimal.setText(Decimal2);
                              repaint();
                         }while((strLength/8) >count);
     }//end of actionPerform
     public void paint( Graphics g)
          super.paint(g);
     public String Convert(String a)
          int ctr=1, decimal=0;
          for (int i = a.length()-1; i>=0; i--)
          if(a.charAt(i)=='1')      decimal+=ctr;
          ctr*=2;
          String converted = "" + decimal;
          return converted;
     public static void main(String args[])
          System.out.println("Binary to Dec");
          BinaryToDec in = new BinaryToDec();
     }// end of main()
}// end of class FrameExample1
OK so other than that i decided to play with some of the paint functions i more or less stayed on task, at first i had it just convert 8 digit binary nums into decimal form using this -
          int ctr=1, decimal=0;
          for (int i = a.length()-1; i>=0; i--)
          if(a.charAt(i)=='1')      decimal+=ctr;
          ctr*=2;
which i found in someone elses post and made some changes to, thank you someone whoever you are i hope you see this, anyways,.. then i decided i wanted it to check the length of a string and divide it by 8 assuming that it it a perfect block of 8 digit nums and then cut it into substring and go through the proccess of converting the binary to deciaml one piece at a time. I did it more or less, well it compiles right but whenever you put in more than one 8 digit binary number it ends up giving you some really strange decimal numbers and i cant seem to figure out why the hell it is doing this.??? I was hoping that some one could help me out.
If you read this far than thanks for taking the time on my post :)

Did you try to decode that message by hand and verified that it really is encoded the way you think it is?
Here some code to try
public static void decode(String fileIn, String fileOut) {
        try {
        FileReader in=new FileReader(fileIn);
        PrintWriter out=new PrintWriter(fileOut);
        char[] buffer=new char[8];
        int i;
        do {
            i=in.read(buffer, 0, 8);
            if(i==8) {
                out.write(Integer.parseInt(new String(buffer),2));
        } while(i==8);
        in.close();
        out.close();
        } catch (Exception e) {}
    public static void encode(String fileIn, String fileOut) {
        try {
        FileReader in=new FileReader(fileIn);
        PrintWriter out=new PrintWriter(fileOut);
        int i;
        while( (i=in.read()) >= 0 ) {
            String str=Integer.toBinaryString(i);
            for(int j=str.length(); j<8; j++)
                out.write('0');
            out.write(str);
        in.close();
        out.close();
        } catch (Exception e) {}
    }

Help converting binary to decimal.

Hi all.
I'm taking a course in Java programming and so far its been a great experience. I'm currently stumped on one of my assignments and I am kindly requesting some assistance.
Basically I have to convert a binary entry into its decimal comparison.
so for instance an entry of 1101 would output 13.
I have the calculation formula, but my problem is finding out whether the point i'm looking at is either a 1 or a 0. I can't seem to 'strip it down' to the value.
My current thought is something like this:
binary = 1101;
// problem is here
thou = (binary % 1000) / 1000;
hund = (thou % 100) / 100;
tens = (hund % 10) / 10;
ones = (tens % 1) / 1;
// then do formular
decimal = ones * 1 + tens * 2 + hund * 4 + thou * 8;
I have searched but all the suggestions say to use a custom function or other obscure method. I don't know that stuff real well and we aren't even that far in the book either. All we've done so far is while, if .. else, condition statements.
I will include the actual text for the question, in case i'm not clear. This text also includes a 'tip' which isn't helping me. (http://www.geocities.com/kaveman2000/q-4-25.pdf)
Thanks again for any pointers.

angeles1016 (and all),
thanks for your great help and code snippets.
angeles1016,
using the code you provided i noticed that the last (single digit) was giving the wrong response in certain cases. (1000, 0111, 0001, ..) i could be off one.
either way, i decided to fix it up and give you all the update.
// do class, main function stuff
     if(binary/1000 == 1){
          thousands += (binary/1000);
     temp = binary % 1000;
     if(temp/100 == 1){
          hundreds += (temp/100);
     temp = temp % 100;
     if(temp/10 == 1){
          tens += (temp/10);
     temp = temp % 10;
     if(temp/1 == 1){
          ones += (temp/1);
     // calculate binary to decimal
     decimal = (ones * 1) + (tens * 2) + (hundreds * 4) + (thousands * 8);
     // take result and convert to string for output
     result += "Decimal: " + decimal + "\n";
// display in gui ?
// end function and class stuff(note: i suppose the statements similar to "thousands += (binary/1000);" can be simplified as "thousands = 1;")

Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program

I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
   public static void main(String[] args)throws IOException
      Scanner input = new Scanner(System.in);
      System.out.println("Enter a binary number: ");
      String binary = input.nextLine(); // store input from user
     if (binary == input.nextLine())
      //int i= Integer.parseInt(hex,2);
      //String hexString = Integer.toHexString(i);
      //System.out.println("Hexa decimal: " + hexString);
      //int finaldecimalvalue = binaryToDecimal(hexString);
      int finaldecimalvalue = binaryToDecimal(hexString);
     if (binary != input.nextLine())
      String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
      // Create a Scanner object for keyboard input.
      //Scanner keyboard = new Scanner(System.in);
      // Get the number of binary files.
      System.out.print("Enter the Hex value: ");
      hexInput = keyboard.nextLine();
      System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      System.out.println("Hex String: "+ hexEquivalent);
      String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
     if (binary != input.nextLine() && hexInput != keyboard.nextLine())
         BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
         System.out.println("Enter the Binary number:");
         String hex = binInput.readLine();
         //String finaldecimalvalue = binaryToDecimal(decimal);
         //long finalhexvalue = BinaryToHexadecimal(num);
         long finalhexvalue = BinaryToHexadecimal();
   public static String BinaryToHexadecimal(String hex)
      //public static void main(String[] args)throws IOException
         //BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
         //System.out.println("Enter the Binary number:");
         //String hex = binInput.readLine();
         long num = Long.parseLong(hex);
         long rem;
         while(num > 0)
         rem = num % 10;
         num = num / 10;
         if(rem != 0 && rem != 1)
         System.out.println("This is not a binary number.");
         System.out.println("Please try once again.");
         System.exit(0);
         int i= Integer.parseInt(hex,2);
         String hexString = Integer.toHexString(i);
         System.out.println("Hexa decimal: " + hexString);
      return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
   //public static String HexAsciiConverter(String hextInput)
      // Get the number of binary files.
      //System.out.print("Enter the Hex value: ");
      //hexInput = keyboard.nextLine();
      //System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      //String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      //System.out.println("Hex String: "+ hexEquivalent);
      //String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      //System.out.println("Ascii String: "+ asciiEquivalent);
   //} // End function
   private static String asciiToHex(String asciiValue)
      char[] chars = asciiValue.toCharArray();
      StringBuffer hex = new StringBuffer();
      for (int i = 0; i < chars.length; i++)
         hex.append(Integer.toHexString((int) chars[i]));
      return hex.toString();
   private static String hexToASCII(String hexValue)
      StringBuilder output = new StringBuilder("");
      for (int i = 0; i < hexValue.length(); i += 2)
         String str = hexValue.substring(i, i + 2);
         output.append((char) Integer.parseInt(str, 16));
      return output.toString();
   public static String binaryToDecimal(String binary)
        //Scanner input = new Scanner(System.in);
        //System.out.println("Enter a binary number: ");
        //String binary = input.nextLine(); // store input from user
        int[] powers = new int[16]; // contains powers of 2
        int powersIndex = 0; // keep track of the index
        int decimal = 0; // will contain decimals
        boolean isCorrect = true; // flag if incorrect input
       // populate the powers array with powers of 2
        for(int i = 0; i < powers.length; i++)
            powers[i] = (int) Math.pow(2, i);
        for(int i = binary.length() - 1; i >= 0; i--)
            // if 1 add to decimal to calculate
            if(binary.charAt(i) == '1')
                decimal = decimal + powers[powersIndex]; // calc the decimal
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
                isCorrect = false; // flag the wrong input
                break; // break from loop due to wrong input
            } // end else if
            // keeps track of which power we are on
            powersIndex++; // counts from zero up to combat the loop counting down to zero
        } // end for
        if(isCorrect) // print decimal output
            System.out.println(binary + " converted to base 10 is: " + decimal);
        else // print incorrect input message
            System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
        return decimal.toint();
   } // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
   public static String BinaryToHexadecimal(String hex)
                 ^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
         long rem;
         ^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
         while(num > 0)
         ^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
         num = num / 10;
         ^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
         if(rem != 0 && rem != 1)
         ^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
         System.out.println("Please try once again.");
         ^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
         System.exit(0);
         ^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
         ^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
         String hexString = Integer.toHexString(i);
         ^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
         System.out.println("Hexa decimal: " + hexString);
         ^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
      return num.tolong();
      ^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
      StringBuffer hex = new StringBuffer();
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                                        ^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                                             ^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
         output.append((char) Integer.parseInt(str, 16));
         ^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
   public static String binaryToDecimal(String binary)
                 ^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
        int powersIndex = 0; // keep track of the index
        ^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
        int decimal = 0; // will contain decimals
        ^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
        boolean isCorrect = true; // flag if incorrect input
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                       ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                                          ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
        ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                         ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                                 ^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
            ^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
                break; // break from loop due to wrong input
                ^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
            } // end else if
            ^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
        } // end for
        ^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
        else // print incorrect input message
        ^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
        return decimal.toint();
        ^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
   } // end function
   ^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
      public static void main(String[] args)throws IOException      {
         Scanner input = new Scanner(System.in);
         System.out.println("Enter a binary number: ");
         String binary = input.nextLine(); // store input from user
              public static String BinaryToHexadecimal(String hex)     {     } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method.

NI 9870 and binary coded decimal (BCD)

I have a scale that outputs the weight in 4 digit ASCII form which I would like to input into a CompactRio 9072 with a NI 9870 card and convert to a binary integer. The weight appears as the 7th to 10th character on lines that are terminated by a CR. I am thinking I will need a loop that once the 10th character is read, the 4 least significant bits of the 4 characters are converted from BCD to binary and the character counter resets to 0 when a CR is read. I need a good method for converting BCD to an integer value in either labview or vhdl. The rest of the logic for this project is in vhdl, so I would not mind adding the conversion logic there, except that all the algorithms I have found require decimal division or comparison in several clock cycles.
Solved!
Go to Solution.

Hello imr
Thank you very much for getting in touch with us!
I believe the following community example will resolve part of your issue.
Binary String to Number
https://decibel.ni.com/content/docs/DOC-11704
I have also provided some further information for those unaware of what Binary Coded Decimal represents.
What is Binary Coded Decimal (BCD)?
http://digital.ni.com/public.nsf/allkb/59C2A05C123008F286256CA90069A6F8
Thank you for choosing National Instruments!
Sincerely,
Greg S.

When instructed "the java binary in your path"

please help
when Im instructed with the following:
a JDK or JRE 1.0+ (see www.javasoft.com) installed and the java binary in your PATH
my operating system is windows server 2000
how do i set the path to to the java binary, Is the java binary. Is the java binary the bin folder, if so i have two of those, one directly under the jdk folder and one under jre folder.
Do i use autoexecute.bat, if so how.
thank you for any help rendered.
Yaary

Oh oh.
Java uses the sys var CLASSPATH to look for - well - java classes.
For that reason, CLASSPATH should always include ".;<yourJavaDir>\jre\lib\rt.jar" or ".;<yourJavaDir>\j2re1.4.x\lib\rt.jar". This ensures that Java can find the classes that come with the distribution (i.e. everything in rt.jar) and all classes in the directory from which you invoke Java or Javac.
Now, the "<yourJavaDir>\jdk1.x.x\bin" thingie belongs into your PATH variable - that's the var your system uses to look for executables, i.e. java or javac.
Regards, Thomas

How to read non-java binary file?

Hello Team,
I have problem to read non-java binary file.
Let me explain.... I have one binary file created in vc++ having fix structure. Structure of file is like String,int,int,int.
Now I have to read this file in my java application. I am failed to identify length of String value of Structure in java.
Can any body help me to solve this problem?
Thanks in advance.
- Pathik

Thanks for guide me,
I have try using 0x00. And its working.
Now I have another problem:
in file.ext , I have written one record having structure string,int and int.
I have enter data as "HelloWorld", 100 and 111.
To read first record from file file.ext, following code I am using:
try
     FileInputStream fis = new FileInputStream("file.ext");
     DataInputStream in = new DataInputStream(fis);
     char ch;
     while((ch=(char)in.readByte()) != 0x00)
          System.out.print(ch+"");
System.out.println();
     System.out.println("Integer 1 --> " + in.readInt());
     System.out.println("Integer 2 --> " + in.readInt());
     in.close();
     fis.close();
catch(Exception ex)
     System.out.println(ex.toString());
And I am getting following output:
HelloWorld
Integer 1 --> 0
Integer 2 --> 0
File file.ext is created in vc++
I am not getting integer data. Plz guide me for this problem.
Thanks in advance
- Pathik

Convert LRAW to java binary

this question should be asked in ABAP session,
nevertheless, because no one answer at that section,
LRAW have length 1024
FunctionName : YEMM_ATTACHMENT
COL_NAME DATA_TYPE LENGTH
FILE_NAME : CHAR 200
TLINENO: CHAR 4
CONTE: LRAW 1024
in java i can just using this
byte[] attachfile= file.getBytes();
if a file is bigger than 1024 , how do i store it and pass it to JCO..
do i have to pass line by line of binary code ??
JCO.Table inputAttach=function.getTableParameterList().getTable("SOBATTH");
ByteArrayOutputStream byteBuffer=new ByteArrayOutputStream();
if(blnAttach.equalsIgnoreCase("x")==true){
if(inputAttach.getNumRows()>0){
int lineno=Integer.parseInt(inputAttach.getString("TLINENO"));
for(int k=0;k<lineno;k++){
fileName=inputAttach.getString("FILE_NAME");
file=inputAttach.getByteArray("ATTACHMENT");
ByteBuffer.write(file);
OutMailDetailsBean outMailDet=new OutMailDetailsBean();
outMailDet.setAttachment(ByteBuffer.toByteArray());
outMailDet.setAttachmentId(getAttachmentId());
outMailDet.setAttachmentName(fileName);
outMailDet.setEmailId(emailId);
beanList2.add(outMailDet);
1) while converting the file ...i download it and open it....
when open, i always get file corrupted , although the file size is same as the original file
any idea ?
ABAP LRAW to java binary
2) This is printed from ABAP
how to i print the same thing in java and do a comparison i mean the binary code
Row MANDT FILE_NAME TLINENO CONTE
1 dsn.jar 1 504B0304140008000800A6419334000000000000000000000000090004004D4554412D494E462FFECA00000300504B0708000000000200000000000000504B0304140008000800A6419334000000000000000000000000140000004D4554412D494E462F4D414E49464553542E4D46858F3D0BC23014456703F90F01170B266
2 dsn.jar 2 E86A8F26B3D4982B3A3127AFEDF45E51B06E5E3B9375FEDF19DCB5464FD6151A2583C135098AD10E1A9DA98BFF60B69871DC90C619CB8A4BD13CBE56A736D88944A3B0F1443EE9E8D9ACC2D66514A68B4E230C1D2ED70A7D0A136B8B69229E4D470BC54C99ADE8709184DC66C5E764794A6658381D159CA3293B331F2D53E9B
3 dsn.jar 3 75BCE6C88334E5E173D055EC3D492C2765EB89785CCA756C0B45AEBA2135975912E1D8B2BF5D14075E67C95DC036BC41DB6F22828BBCFD2E0E578AE5051A700B4B4D86BF4037F31BBE896E1685B5846E298AAF89456FE43A7A98CD5ECFBE457488A99EDD55D2731ED5E31A7FE7D6BF966D0FD12AF8366DC2DB68E58B7323DF8
4 dsn.jar 4 FEECA515578654EC529CC3ADB0B985F088F433187BE9B10E923F07F46FFBBA9857BE91F90B504B0708A366CF5960020000B1040000504B03041400080008009B41933400000000000000000000000026000000636F6D2F73756E2F6D61696C2F64736E2F4D756C7469706172745265706F72742E636C617373AD5769705B571
5 dsn.jar 5 8286A5D14CDE3986F7CAE58CF75C3A95F096B6A850ED095050C570623B957B68A94DF6DEBDFF8D314BD1BBB914AB19F7DC54E082A571A1161A89A793D5B9EFE6614225C3099521A898D54565791D38B554A184E58164B66C558489B9F3DC8F9B44F0591F8C56375C0DF3C93085FAF9F2437217CF33CBC38B946219A98591B8E
6 dsn.jar 6 348F63AF5416B9F0551C40E779FC59791EB7F0DC57E5197FCD9E872BD8F243CBF43C647A76508BDA55D4CBB3EFAE3534E8814EC840557D2EC6A9C3293489D3681793555117CAF8D88A7C462DF8DC5F91498ACFDBB0F86F504B0708F2B9A927DE070000F6110000504B03041400080008009B419334000000000000000000000
7 dsn.jar 7 E8FD097D2F49986182D63E7A3D922222B40B0C4E622A341B27AA30AB447E457FB633F50A7D998323CD00F21AAD69E8E4A8D098A6BBB0372864270E71EA39BA539387183860072D9073E8C13C06B0482F6D548186E94FD31D9ADA209A909BAA40CD4EFC8C4186324E1FAC56309CAD60245BC61975F410EF90F5B3743BC4B932C
8 dsn.jar 8 A6A07E617A23BAD2F324ED965B7B20996A229CDA8356FC1991D78899D197D08BBF20F21C619298474CA3898F7EC3F00B326648D073986E78E01442380D8B56AA96DE82B00992AAB046E80FC48A83A95F319C6F743D8394B3F49C21CFC0E302C155F1C6946D7A1723CF104D9DD9C56883357A52CEE308AE61140B24251AB7039
9 dsn.jar 9 CCCBFBF840C1719C50F00D9C10D0446D10A23608711B84A80D42E56D20E2F70A3EC41FD8D44702EE74B26D333B8C14A112E8F5F9C40C1D29A136AC8DE9C399714228A0A5C01488510A2DDA0A94DB0F07142C609197AB0AAEB1E37FE4E524BE29C05FB0A617AAE0A82DC770FF24A0B968782895D2126AAACF4C6426A9E64AD0B
10 dsn.jar 10 2CBDCDE169E23B8F67CAB21025BD4E7C0E124DA49DCF3B6EA2EA02063B6EA02AECF2BBBAB2D8338F9EB0DBEFCEE2AEB0C7EFB9893A4ABADF730375ABA539DA4B3962A67C92164953CB45DC5FCA13241E2A9C2CDAE8C5DBCE0B15918FFE29BB64CA979315C22E21ECE6C26AE4747447BBFC14A050D83D8F9AB087F3C3DF4DAB8
11 dsn.jar 11 34D4628588B303000076070000270000000000000000000000000014190000636F6D2F73756E2F6D61696C2F64736E2F6D756C7469706172745F7265706F72742E636C617373504B010214001400080008009B419334A01611112F0800001F10000029000000000000000000000000001C1D0000636F6D2F73756E2F6D61696
Message was edited by:
        yzme yzme

Hi yzme
http://www.apentia-forum.de/viewtopic.php?t=1962&sid=9ac1506bdb153c14edaf891300bfde25
Hope if answers to your question.
Regards
Divya

LRAW to java binary

LRAW have length 1024
FunctionName : YEMM_ATTACHMENT
COL_NAME DATA_TYPE LENGTH
FILE_NAME : CHAR 200
TLINENO: CHAR 4
CONTE: LRAW 1024
in java i can just using this
byte[] attachfile= file.getBytes();
if a file is bigger than 1024 , how do i store it and pass it to JCO..
do i have to pass line by line of binary code ??
JCO.Table inputAttach=function.getTableParameterList().getTable("SOBATTH");
ByteArrayOutputStream byteBuffer=new ByteArrayOutputStream();
if(blnAttach.equalsIgnoreCase("x")==true){
if(inputAttach.getNumRows()>0){
int lineno=Integer.parseInt(inputAttach.getString("TLINENO"));
for(int k=0;k<lineno;k++){
fileName=inputAttach.getString("FILE_NAME");
file=inputAttach.getByteArray("ATTACHMENT");
ByteBuffer.write(file);
OutMailDetailsBean outMailDet=new OutMailDetailsBean();
outMailDet.setAttachment(ByteBuffer.toByteArray());
outMailDet.setAttachmentId(getAttachmentId());
outMailDet.setAttachmentName(fileName);
outMailDet.setEmailId(emailId);
beanList2.add(outMailDet);
1) while converting the file ...i download it and open it....
when open, i always get file corrupted , although the file size is same as the original file
any idea ?
ABAP LRAW to java binary
2) This is printed from ABAP
how to i print the same thing in java and do a comparison i mean the binary code
Row MANDT FILE_NAME TLINENO CONTE
1 dsn.jar 1 504B0304140008000800A6419334000000000000000000000000090004004D4554412D494E462FFECA00000300504B0708000000000200000000000000504B0304140008000800A6419334000000000000000000000000140000004D4554412D494E462F4D414E49464553542E4D46858F3D0BC23014456703F90F01170B266
2 dsn.jar 2 E86A8F26B3D4982B3A3127AFEDF45E51B06E5E3B9375FEDF19DCB5464FD6151A2583C135098AD10E1A9DA98BFF60B69871DC90C619CB8A4BD13CBE56A736D88944A3B0F1443EE9E8D9ACC2D66514A68B4E230C1D2ED70A7D0A136B8B69229E4D470BC54C99ADE8709184DC66C5E764794A6658381D159CA3293B331F2D53E9B
3 dsn.jar 3 75BCE6C88334E5E173D055EC3D492C2765EB89785CCA756C0B45AEBA2135975912E1D8B2BF5D14075E67C95DC036BC41DB6F22828BBCFD2E0E578AE5051A700B4B4D86BF4037F31BBE896E1685B5846E298AAF89456FE43A7A98CD5ECFBE457488A99EDD55D2731ED5E31A7FE7D6BF966D0FD12AF8366DC2DB68E58B7323DF8
4 dsn.jar 4 FEECA515578654EC529CC3ADB0B985F088F433187BE9B10E923F07F46FFBBA9857BE91F90B504B0708A366CF5960020000B1040000504B03041400080008009B41933400000000000000000000000026000000636F6D2F73756E2F6D61696C2F64736E2F4D756C7469706172745265706F72742E636C617373AD5769705B571
5 dsn.jar 5 8286A5D14CDE3986F7CAE58CF75C3A95F096B6A850ED095050C570623B957B68A94DF6DEBDFF8D314BD1BBB914AB19F7DC54E082A571A1161A89A793D5B9EFE6614225C3099521A898D54565791D38B554A184E58164B66C558489B9F3DC8F9B44F0591F8C56375C0DF3C93085FAF9F2437217CF33CBC38B946219A98591B8E
6 dsn.jar 6 348F63AF5416B9F0551C40E779FC59791EB7F0DC57E5197FCD9E872BD8F243CBF43C647A76508BDA55D4CBB3EFAE3534E8814EC840557D2EC6A9C3293489D3681793555117CAF8D88A7C462DF8DC5F91498ACFDBB0F86F504B0708F2B9A927DE070000F6110000504B03041400080008009B419334000000000000000000000
7 dsn.jar 7 E8FD097D2F49986182D63E7A3D922222B40B0C4E622A341B27AA30AB447E457FB633F50A7D998323CD00F21AAD69E8E4A8D098A6BBB0372864270E71EA39BA539387183860072D9073E8C13C06B0482F6D548186E94FD31D9ADA209A909BAA40CD4EFC8C4186324E1FAC56309CAD60245BC61975F410EF90F5B3743BC4B932C
8 dsn.jar 8 A6A07E617A23BAD2F324ED965B7B20996A229CDA8356FC1991D78899D197D08BBF20F21C619298474CA3898F7EC3F00B326648D073986E78E01442380D8B56AA96DE82B00992AAB046E80FC48A83A95F319C6F743D8394B3F49C21CFC0E302C155F1C6946D7A1723CF104D9DD9C56883357A52CEE308AE61140B24251AB7039
9 dsn.jar 9 CCCBFBF840C1719C50F00D9C10D0446D10A23608711B84A80D42E56D20E2F70A3EC41FD8D44702EE74B26D333B8C14A112E8F5F9C40C1D29A136AC8DE9C399714228A0A5C01488510A2DDA0A94DB0F07142C609197AB0AAEB1E37FE4E524BE29C05FB0A617AAE0A82DC770FF24A0B968782895D2126AAACF4C6426A9E64AD0B
10 dsn.jar 10 2CBDCDE169E23B8F67CAB21025BD4E7C0E124DA49DCF3B6EA2EA02063B6EA02AECF2BBBAB2D8338F9EB0DBEFCEE2AEB0C7EFB9893A4ABADF730375ABA539DA4B3962A67C92164953CB45DC5FCA13241E2A9C2CDAE8C5DBCE0B15918FFE29BB64CA979315C22E21ECE6C26AE4747447BBFC14A050D83D8F9AB087F3C3DF4DAB8
11 dsn.jar 11 34D4628588B303000076070000270000000000000000000000000014190000636F6D2F73756E2F6D61696C2F64736E2F6D756C7469706172745F7265706F72742E636C617373504B010214001400080008009B419334A01611112F0800001F10000029000000000000000000000000001C1D0000636F6D2F73756E2F6D61696
Message was edited by:
yzme yzme>

Hi yzme
http://www.apentia-forum.de/viewtopic.php?t=1962&sid=9ac1506bdb153c14edaf891300bfde25
Hope if answers to your question.
Regards
Divya

Conversion from Binary to decimal - Need help

Hi guys,
I am new here and learnt some very basic Java before. I have a program that is in C++(to convert a binary number to decimal) that I found in the internet that interest me a lot. I am thinking whether this can be re-write in Java. I have tried to searh for solution but to no avail. I am wondering whether you guys can suggest a solution to this. Below are the source code in C++ :
#include <iostream.h>
#include <stdlib.h>
int main()
// part 1 : declaration
int Bin, Dec, TempBin;
int div;
char valid, again;
do {
// part 2 : Repeat asking the value of the binary number
Bin = TempBin = 0;
do {
cout << "Please input a binary number (1 to 10 bits) : ";
cin >> Bin;
TempBin = Bin;
do {
if ((TempBin % 10)==0 || (TempBin % 10)==1) // Note (1)
valid='Y';
else {
cout << "Invalid pattern! use 0's and 1's only\n\n";
valid='N';
break;
TempBin = (TempBin/10);
} while (TempBin>0);
} while (valid=='N');
// part 3 : Convertion
div = 1;
Dec = 0;
TempBin = Bin;
do {
Dec += (TempBin % 10)*div; // Note (2)
div *= 2;
TempBin = (TempBin/10);
} while (TempBin>0);
cout << "\nThe binary pattern " << Bin << " is equal to "
<< Dec << " in decimal pattern.\n" << endl;
// part 4 : try another number ?
cout << "\aTry another number (Y/N) : ";
cin >> again;
cout << "\n";
} while (again=='Y' || again=='y');
cout << "\n" << endl;
system("PAUSE");
return 0;
Appreciate your help. Thank you.
CK

So for Java, in your example, it takes a Java
String like "1001" and converts it to an int whose
value is one thousand and one. Can suggest a code for
this that takes user input str and convert to bin int.
I read books and noticed they are various ways to do
that. I am quite confused actually. It is like there
is no fix way to do that, unlike C++ which is more
easier to understand(in my opinion). Probably, because
I knew C better than Java.
The 'standard' way to take a String and convert it to an int...
int TempBin=Integer.parseInt(your_string);
You seem to be saying that you do not want to use the standard method, so you should not complain that there is no standard method. Here's some code that re-uses most of your modulo 10.
import java.io.*;
public class Test {
     public static void main(String []args) throws IOException {
          BufferedReader bf=new BufferedReader(new InputStreamReader(System.in));
          String result=null;
          while(true) {
               String input=bf.readLine().trim();
               try {
                    long v=Long.parseLong(input);
                    result=toBin(v);
                    System.out.println(result);
               } catch(NumberFormatException e) {
                         System.out.println("Only enter 1 or 0, nothing else!");
               System.out.println();
     public static String toBin(long btemp) {
          long temp=btemp;
          do {
               if ((temp % 10)!=0 && (temp % 10)!=1) {
                    System.out.println("Invalid pattern! use 0's and 1's only\n\n");
                    return null;
               temp = (temp/10);
          } while (temp>0);
          // part 3 : Convertion
          int div = 1;
          int Dec = 0;
          long TempBin = btemp;
          do {
               Dec += (TempBin % 10)*div; // Note (2)
               div *= 2;
               TempBin = (TempBin/10);
          } while (TempBin>0);
          return ""+Dec;

Program to convert binary to decimal number?

I only know how to do a program that converts only 4 numbers, but it to convert any amount of digits the number enters, I think you need to use a loop or something, but I'm not sure how. Could someone please help me? This is my code so far:
import javax.swing.JOptionPane;
public class bintodec {
     public static void main (String[] args) {
          String input;
          int number,digit1,digit2,digit3,digit4,result;
          input = JOptionPane.showInputDialog ("Enter a binary number.");
          number = Integer.parseInt(input);
          digit1 = ((number % 10000) - (number % 10000 % 1000)) / 1000;
          digit2 = ((number % 1000) - (number % 1000 % 100)) / 100;
          digit3 = ((number % 100) - (number % 100 % 10)) / 10;
          digit4 = (number % 10);
          result = (digit1 * 8) + (digit2 * 4) + (digit3 * 2) + (digit4 * 1);
          System.out.println ( "Binary number: " + input + "\nConverted Decimal Number: " + result);
          System.exit( 0 );
     } // main
} // bintodecany help is super-appreciated.

I am not sure if this will help you. Check it out, run it and let me know if it helped.
import java.util.*;
   public class BitwiseTest1 {
       public static void main(String[] args){
        System.out.println("Enter a integer number:");
        Scanner keyboard = new Scanner(System.in);
        int n1 = keyboard.nextInt();
        System.out.println( "n1 as binary " +
               Integer.toBinaryString( n1 ));
        System.out.println( "NOT n1 =     " +
               Integer.toBinaryString( ~n1 ));
        System.out.println("Enter another integer number:");
        int n2 = keyboard.nextInt();
        System.out.println( "n2 as binary " +
               Integer.toBinaryString( n2 ));
         System.out.println( "NOT n2 =     " +
               Integer.toBinaryString( ~n2 ));
}

Convert binary to decimal

hi, i was wondering what's the code to convert binary numbers to decimal numbers?

import java.io.*;
class convertBinarytoDecimal{
     public static void main (String args[])
     throws Exception {
          System.out.println("Enter the Binary Number");
          BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
          String str = br.readLine().trim();
          int [] myArray = new int [str.length()];
          for(int i=0;i<myArray.length;i++){
               myArray[i] = Integer.parseInt(str.charAt(i)+"");
          convertBinarytoDecimal(myArray);
     static void convertBinarytoDecimal(int [] myArray){
          int decimal = 0;
          for (int i =0;i<myArray.length;i++){
               decimal += myArray[i] * Math.pow(2,myArray.length-(i+1));
          System.out.println(decimal);
}

Binary to decimal IP address

Hello all,
I have an IP address in binary format in an array
11000000101010000110010000100010
and I want to transform it into decimal format : 192.168.100.32.
How can I implement this in java?
Thanks!

denisa wrote:
Hello all,
I have an IP address in binary format in an array
11000000101010000110010000100010
and I want to transform it into decimal format : 192.168.100.32.
...That's 192.168.100.34, by the way...

Core Java Issue in decimal division....SOS!!!!

Hi People,
I was just wondering the reason for below output generated in java.
double d2 = 0.142;
double d3 = d2/100;
System.out.println(d3);
Output = 0.0014199999999999998
But if i do in calculator i get 0.00142
double d2 = 0.152;
double d3 = d2/100;
System.out.println(d3);
Output = 0.0015199999999999999
But if i do in calculator i get 0.00152
Any help is highly appreciated.

939520 wrote:
You also might want to read up on Java's 'strictfp' reserved word. I don't know if it will help and weather or not it applies to both float and double since I never used it.
Setting 'strictfp' will make no difference. The Goldberg article explains the problem.
If the OP is doing scientific or engineering work then the errors due to the fact that not all decimal values have a finite length binary representation will usually be small enough to be neglected. If the OP is working with money then, even though double has about 14 decimal places, it is unlikely to be acceptable.

Binary To Decimal

Hi i am having trouble from converting a binary number into decimal. I found the following code from a tutorial online and would like to merge it inside the code i currently have.
This is the example i found online:
//initialize the place values
var place:Array = [32, 16, 8, 4, 2, 1];
//initialize your binary number
var binary:Array = [1, 1, 0, 0, 1, 1];
//trace it as a string
trace(binary.join(""));
//convert it to a decimal number
var decimalNumber = (place[0]*binary[0])+(place[1]*binary[1])+(place[2]*binary[2])+(place[3]*binary[3])+(place[4]*binary[4])+(place[5]*binary[5]);
//trace the result
trace(decimalNumber);
This is the code i currently have
var binaryArray:Array = new Array();
var num:Number;
var binaryString:String;
var round:Number;
var bString:String;
var bNumber:Number;
decimal_txt.addEventListener(KeyboardEvent.KEY_DOWN, checkEnterKey);
function checkEnterKey(e:KeyboardEvent):void
if(decimal_txt.text != '' && e.keyCode == Keyboard.ENTER)
num = Number(decimal_txt.text);
//trace(e.keyCode + " : " + tf.text);
bString = convertDecimalToBinary(num);
bNumber = Number(binaryString);
binary_txt.text = bString;
function getTextInput(e:KeyboardEvent):void
num = Number(decimal_txt.text);
//trace(e.keyCode + " : " + tf.text);
bString = convertDecimalToBinary(num);
bNumber = Number(binaryString);
binary_txt.text = bString;
function convertDecimalToBinary(num:Number):String
if(num == 0)
return String("");
binaryString = ''; //starts with an empty string
while(num > 0)
num /= 2;
if(Math.floor(num) == num)
binaryArray.push(0);
else
binaryArray.push(1);
trace(num);
num = Math.floor(num);
for(var i:int = binaryArray.length-1; i >= 0; i--)
binaryString += binaryArray[i];
// clear array to prepare for next input
binaryArray.pop();
while (binaryString.length<8) {
binaryString = "0"+binaryString;
//trace(binaryString);
return binaryString;
However the first code already sets a decimal value in the array and calculates it but i would like to merge it with the one i have which outputs the decimal value from an input of a binary number. How would this be possible?

what output?
all you're doing is defining n when a key is down. you're not doing anything with n so i don't see how you expect any output.
if binary_txt is a textfield with a binary (string) and decimal_txt is a textfield that should display the decimal representation of binary_txt.text, use:
binary_txt.addEventListener(KeyboardEvent.KEY_DOWN, checkEnterKey2);
function checkEnterKey2(e:KeyboardEvent):void{
if(binary_txt.text != '' && e.keyCode == Keyboard.ENTER){
decimal_txt.text=binaryToDecimal(binary_txt.text);
function binaryToDecimal(s:String):Number{
for(var i:int=0;i<s.length;i++){
n+=Number(s.substr(i,1))<<(s.length-1-i)
return n;

Java binary to decimal?

Similar Messages

Maybe you are looking for