Java regex problem

Hi:
I have the following texts in a flat file:
scheduler is running
system default destination: llp
device for ps3: /dev/ps3
device for ps: /dev/ecpp0
device for llp: /dev/ecpp0
How can I use java regex to print out the string after "device for " in this case the string "ps3" ,"ps" and "llp".

    static final Pattern DEVICE_PATTERN = Pattern.compile(
                                      "device for ([^:]++)" );
    String text = "";
    Matcher m = DEVICE_PATTERN.matcher( text );
    while ( (text = bufferedReader.readLine()) != null ) {
        if ( m.reset(text).lookingAt() ) {
            String device = m.group( 1 );
    }

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sorry, I try to expain it in more details. I want to parse this text file and save the status like "warning" and "ok" into a list. The question is I only need the "ok" that follow the "warning", that means if "test1 warning" then looking for "test1 ok".
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Java regex problem

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