Java Regular Expression for double spaces

Question

I am using ([\\s\\s]+) this regex for finding double spaces but if in single segment (Text Line) there exists two or more double spaces then it is finding only one from it .
Matcher m = Pattern.compile( regexp ).matcher(Segment );
while(m.find)
p.println(" ERROR :: Punctuation (Double Dot ) Error");
Suggets solution
Thanks
amit

Answer 1

Hi,
I understood the question like this:
You have a String, and you want to find if the string have 2 or more than double spaces till the end of the string.
I have attached a sample code for the above problem. Please have a look into it.
public class FindDoubleSpacesInString {
     private static final String DOUBLE_SPACE_STRING = "tetett  etetete etetete     etete et e tet ";
      * @param args
      * loganathank
      * void
     public static void main(String[] args) {
          String doubleSpaceRegExPattern = "\\s{2,}";
          Pattern doubleSpacePattern = Pattern.compile(doubleSpaceRegExPattern);
          Matcher doubleSpaceMatcher = doubleSpacePattern.matcher(DOUBLE_SPACE_STRING);
          while(doubleSpaceMatcher.find()) {
               System.out.println("double space found");
}Please let me know, whether it resolves your problem.
Regards,
Loga